date

(PHP 4, PHP 5)

dateФорматира местно време/дата

Описание

string date ( string $format [, int $timestamp ] )

Връща низ, форматиран съгласно посочения форматиращ низ, използвайки дадения целочислен timestamp или текущото местно време, ако не е подаден timestamp (момент във времето). С други думи, timestamp е незадължителен и по подразбиране има стойността, връщана от time().

Параметри

format

Формата на низа за дата, който ще се извежда. Вижте опциите за форматиране по-долу.

В параметричния низ format се разпознават следните знаци
format символ Описание Примерни връщани стойности
Ден --- ---
d Ден от месеца, 2 цифри с водещи нули От 01 до 31
D Текстово представяне на ден, три букви От Mon до Sun
j Ден от месеца без водещи нули 1 to 31
l (малко 'L') Пълно текстово представяне на деня от седмицата От Sunday до Saturday
N ISO-8601 цифрово представяне на деня от седмицата (добавено в PHP 5.1.0) от 1 (за Monday) до 7 (за Sunday)
S Английско редно окончание за деня от месеца, 2 символа st, nd, rd или th. Подхожда си с j
w Цифрово представяне на деня от седмицата От 0 (за неделя) до 6 (за събота)
z Денят в годината (започвайки от 0) От 0 до 365
Седмица --- ---
W ISO-8601 пореден номер на седмица в годината, седмиците започват в понеделник (добавено в PHP 4.1.0) Пример: 42 (42-рата седмица в годината)
Месец --- ---
F Пълно текстово представяне на месец, като January или March От January до December
L Дали годината е високосна От 1 ако е високосна година, 0 иначе.
m Цифрово представяне на месец, с водещи нули От 01 до 12
M Кратко текстово представяне на месец, три букви От Jan до Dec
n Цифрово представяне на месец, без водещи нули От 1 до 12
t Брой на дните в даден месец От 28 до 31
Година --- ---
L Дали годината е високосна От 1 ако е високосна година, 0 иначе.
o Година съгласно ISO-8601. Има същата стойност като Y, с тази разлика, че ако номера на седмицата съгласно ISO (W) принадлежи на предишната или следващата година, вместо нея се използва тази година. (добавено в PHP 5.1.0) Примери: 1999 или 2003
Y Пълно цифрово представяне на година, 4 цифри Примери: 1999 или 2003
y Двуцифрено представяне на година Примери: 99 или 03
Време --- ---
a Малки букви Ante meridiem (преди пладне) и Post meridiem (след пладне) От am или pm
A Главни букви Ante meridiem (преди пладне) и Post meridiem (след пладне) От AM или PM
B Swatch Internet време От 000 до 999
g 12-часов формат на час без водещи нули От 1 до 12
G 24-часов формат на час без водещи нули От 0 до 23
h 12-часов формат на час с водещи нули От 01 до 12
H 24-часов формат на час с водещи нули От 00 до 23
i Минути с водещи нули От 00 до 59
s Секунди, с водещи нули От 00 до 59
u Милисекунди (добавено в PHP 5.2.2) Пример: 54321
Часова зона --- ---
e Идентификатор на часовата зона (добавено в PHP 5.1.0) Примери: UTC, GMT, Atlantic/Azores
I (главно i) Дали датата е по лятно часово време (daylights savings time) 1 ако е по лятно време, 0 - по зимно.
O Разлика от гринуичкото време (GMT) в часове Пример: +0200
P Разликата от времето по Гринуич (GMT) с двоеточиеwith между часовете и минутите (добавено в PHP 5.1.3) Пример: +02:00
T Съкращение на часовата зона Примери: EST, MDT ...
Z Отместване на часовата зона в секунди. Отместването за часови зони на запад от Гринуич (UTC) е винаги отрицателно, а за тези на изток от Гринуич (UTC) е винаги положително. От -43200 до 43200
Пълни дата/час --- ---
c ISO 8601 дата (добавено в PHP 5) 2004-02-12T15:19:21+00:00
r » RFC 2822 форматирана дата Пример: Thu, 21 Dec 2000 16:01:07 +0200
U Секунди от Unix Епохата (1 януари 1970 00:00:00 GMT) Вж. също time()

Непознатите знаци във форматиращия низ ще бъдат отпечатани едно към едно. Форматът Z ще връща винаги 0, когато бъде използван посредством gmdate().

Забележка: Тъй като тази функция приема единствено целочислени времеви отпечатъци, форматиращият знак u е полезен единствено при използване на функцията date_format() с потребителски-базиран времеви отпечатък, създаден с date_create().

timestamp

Незадължителният параметър timestamp е целочислен Unix timestamp, чиято стойност по подразбиране е текущото локално време. С други думи, стойността му по подразбиране е стойността върната от функция time().

Връщани стойности

Връща форматиран низ за дата. Ако за timestamp не се използва цифрова стойност, се връща FALSE и се генерира грешка от ниво E_WARNING.

Грешки/Изключения

Всяко извикване на функция за дата и час ще генерира E_NOTICE , ако часовият пояс не е валиден, и/или E_STRICT съобщение ако се използват настройките на системата или променливата на обкръжението TZ. Вж. също date_default_timezone_set()

Дневник на промените

Версия Описание
5.1.0 Валидните стойности за timestamp са обикновено от Fri, 13 Dec 1901 20:45:54 GMT до Tue, 19 Jan 2038 03:14:07 GMT. (Това са датите, които отговарят на минималните и максималните стойности за 32 битово цяло число със знак). Преди PHP 5.1.0, при някои системи (като Windows), този обхват беше ограничен от 01-01-1970 до 19-01-2038.
5.1.0

Вече генерира E_STRICT и E_NOTICE грешки за часовият пояс.

5.1.1 Съществуват няколко полезни константи за стандартни формати за дата и час, които могат да се използват за указване на параметъра format .

Примери

Example #1 Примери за date()

<?php
// установяне на стойността по подразбиране за часовата зона. Достъпно от PHP 5.1
date_default_timezone_set('UTC');

// Извежда нещо подобно на: Monday
echo date("l");

// Извежда нещо подобно на: Monday 8th of August 2005 03:12:46 PM
echo date('l jS \of F Y h:i:s A');

// Извежда: July 1, 2000 is on a Saturday
echo "July 1, 2000 is on a " date("l"mktime(000712000));

/* употреба на константи при параметъра за форматиране */
// извежда нещо подобно на: Mon, 15 Aug 2005 15:12:46 UTC
echo date(DATE_RFC822);

// извежда нещо подобно на: 2000-07-01T00:00:00+00:00
echo date(DATE_ATOMmktime(000712000));
?>

Можете да предотвратите разпознаването на някой от приетите символи във форматиращия низ, избягвайки го с обратно наклонена черта пред него. Ако символът с обратно наклонена черта е специална последователност, може би ще трябва да избегнете и наклонената черта.

Example #2 Избягване на символи в date()

<?php
// prints something like: Wednesday the 15th
echo date("l \\t\h\e jS");
?>

Възможно е да използвате date() и mktime() заедно, за да намирате дати в бъдещето или в миналото.

Example #3 Пример за date() и mktime()

<?php
$tomorrow  
mktime(000date("m")  , date("d")+1date("Y"));
$lastmonth mktime(000date("m")-1date("d"),   date("Y"));
$nextyear  mktime(000date("m"),   date("d"),   date("Y")+1);
?>

Забележка: Това може да бъде по-благонадеждно, отколкото простото добавяне или изваждане на броя секунди за деня или месеца, поради лятното часово време (daylight savings time).

Някои примери за форматиране на date(). Обърнете внимание на това, че трябва да избягвате всички останали символи, тъй като всички, които в момента имат специално значение, ще доведат до нежелани резултати, а на всички останали може да бъде присвоено значение в бъдещи версии на PHP. При избягване, бъдете сигурни, че използвате единични кавички, за да предотвратите символи като \n да се превръщат в нови редове.

Example #4 Форматиране на date()

<?php
// Да предположим, че днес е: March 10th, 2001, 5:16:18 pm

$today date("F j, Y, g:i a");                 // March 10, 2001, 5:16 pm
$today date("m.d.y");                         // 03.10.01
$today date("j, n, Y");                       // 10, 3, 2001
$today date("Ymd");                           // 20010310
$today date('h-i-s, j-m-y, it is w Day z ');  // 05-16-17, 10-03-01, 1631 1618 6 Fripm01
$today date('\i\t \i\s \t\h\e jS \d\a\y.');   // It is the 10th day.
$today date("D M j G:i:s T Y");               // Sat Mar 10 15:16:08 MST 2001
$today date('H:m:s \m \i\s\ \m\o\n\t\h');     // 17:03:17 m is month
$today date("H:i:s");                         // 17:16:17
?>

За да форматирате дати на други езици, трябва да използвате функциите setlocale() и strftime() вместо date().

Бележки

Забележка: За да генерирате timestamp на базта на низово представяне на дата, може да използвате функция strtotime(). Освен това, някои бази от данни притежават функции за преобразуване на собствените формати за дати към timestamp (като функция » UNIX_TIMESTAMP при MySQL).

Съвет

Timestamp стойността на началото на заявката към сървъра е достъпна чрез $_SERVER['REQUEST_TIME'] от PHP 5.1.

Вж. също

  • getlastmod() - Gets time of last page modification
  • gmdate() - Форматира грийнуички (GMT/UTC) дата и час
  • mktime() - Взима Unix времеви отпечатък за дата
  • strftime() - Форматира местно време и дата съгласно локала
  • time() - Връща текущия Unix времеви отпечатък

add a note add a note

User Contributed Notes 42 notes

up
51
Jimmy
2 years ago
Things to be aware of when using week numbers with years.

<?php
echo date("YW", strtotime("2011-01-07")); // gives 201101
echo date("YW", strtotime("2011-12-31")); // gives 201152
echo date("YW", strtotime("2011-01-01")); // gives 201152 too
?>

BUT

<?php
echo date("oW", strtotime("2011-01-07")); // gives 201101
echo date("oW", strtotime("2011-12-31")); // gives 201152
echo date("oW", strtotime("2011-01-01")); // gives 201052 (Year is different than previous example)
?>

Reason:
Y is year from the date
o is ISO-8601 year number
W is ISO-8601 week number of year

Conclusion:
if using 'W' for the week number use 'o' for the year.
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9
Anonymous
7 months ago
It's common for us to overthink the complexity of date/time calculations and underthink the power and flexibility of PHP's built-in functions.  Consider http://php.net/manual/en/function.date.php#108613

<?php
function get_time_string($seconds)
{
    return
date('H:i:s', strtotime("2000-01-01 + $seconds SECONDS"));
}
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10
FiraSEO
1 year ago
this how you make an HTML5 <time> tag correctly

<?php

echo '<time datetime="'.date('c').'">'.date('Y - m - d').'</time>';

?>

in the "datetime" attribute you should put a machine-readable value which represent time , the best value is a full time/date with ISO 8601 ( date('c') ) ,,, the attr will be hidden from users

and it doesn't really matter what you put as a shown value to the user,, any date/time format is okay !

This is very good for SEO especially search engines like Google .
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8
SpikeDaCruz
8 years ago
The following function will return the date (on the Gregorian calendar) for Orthodox Easter (Pascha).  Note that incorrect results will be returned for years less than 1601 or greater than 2399. This is because the Julian calendar (from which the Easter date is calculated) deviates from the Gregorian by one day for each century-year that is NOT a leap-year, i.e. the century is divisible by 4 but not by 10.  (In the old Julian reckoning, EVERY 4th year was a leap-year.)

This algorithm was first proposed by the mathematician/physicist Gauss.  Its complexity derives from the fact that the calculation is based on a combination of solar and lunar calendars.

<?php
function getOrthodoxEaster($date){
 
/*
   Takes any Gregorian date and returns the Gregorian
   date of Orthodox Easter for that year.
  */
 
$year = date("Y", $date);
 
$r1 = $year % 19;
 
$r2 = $year % 4;
 
$r3 = $year % 7;
 
$ra = 19 * $r1 + 16;
 
$r4 = $ra % 30;
 
$rb = 2 * $r2 + 4 * $r3 + 6 * $r4;
 
$r5 = $rb % 7;
 
$rc = $r4 + $r5;
 
//Orthodox Easter for this year will fall $rc days after April 3
 
return strtotime("3 April $year + $rc days");
}
?>
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3
Anonymous
10 months ago
To quickly convert date("N") to a 0 based index with Sunday being represented as 0, you can run it against modulus 7:

<?php
$first_of_month_index
= date('N', strtotime('4/1/1990')) % 7;
?>
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2
adityabhai at gmail dot com
1 year ago
For Microseconds, we can get by following:

echo date('Ymd His'.substr((string)microtime(), 1, 8).' e');

Thought, it might be useful to someone !
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3
Leopietroni
2 years ago
This function will add working day to a given timestamp

<?php
function addworkinday($timestamp,$daystoadd){
    
    
$dayoftheweek = date("N",$timestamp);
    
$sum =$dayoftheweek +$daystoadd;
    
while (
$sum >= 6) {
    
    
$daystoadd=$daystoadd+1;
   
$sum=$sum-1;
}
return
$timestamp +(60*60*24*$daystoadd);

}
?>
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6
ghotinet
3 years ago
Most spreadsheet programs have a rather nice little built-in function called NETWORKDAYS to calculate the number of business days (i.e. Monday-Friday, excluding holidays) between any two given dates. I couldn't find a simple way to do that in PHP, so I threw this together. It replicates the functionality of OpenOffice's NETWORKDAYS function - you give it a start date, an end date, and an array of any holidays you want skipped, and it'll tell you the number of business days (inclusive of the start and end days!) between them.

I've tested it pretty strenuously but date arithmetic is complicated and there's always the possibility I missed something, so please feel free to check my math.

The function could certainly be made much more powerful, to allow you to set different days to be ignored (e.g. "skip all Fridays and Saturdays but include Sundays") or to set up dates that should always be skipped (e.g. "skip July 4th in any year, skip the first Monday in September in any year"). But that's a project for another time.

<?php

function networkdays($s, $e, $holidays = array()) {
   
// If the start and end dates are given in the wrong order, flip them.   
   
if ($s > $e)
        return
networkdays($e, $s, $holidays);

   
// Find the ISO-8601 day of the week for the two dates.
   
$sd = date("N", $s);
   
$ed = date("N", $e);

   
// Find the number of weeks between the dates.
   
$w = floor(($e - $s)/(86400*7));    # Divide the difference in the two times by seven days to get the number of weeks.
   
if ($ed >= $sd) { $w--; }        # If the end date falls on the same day of the week or a later day of the week than the start date, subtract a week.

    // Calculate net working days.
   
$nwd = max(6 - $sd, 0);    # If the start day is Saturday or Sunday, add zero, otherewise add six minus the weekday number.
   
$nwd += min($ed, 5);    # If the end day is Saturday or Sunday, add five, otherwise add the weekday number.
   
$nwd += $w * 5;        # Add five days for each week in between.

    // Iterate through the array of holidays. For each holiday between the start and end dates that isn't a Saturday or a Sunday, remove one day.
   
foreach ($holidays as $h) {
       
$h = strtotime($h);
        if (
$h > $s && $h < $e && date("N", $h) < 6)
           
$nwd--;
    }

    return
$nwd;
}

$start = strtotime("1 January 2010");
$end = strtotime("13 December 2010");

// Add as many holidays as desired.
$holidays = array();
$holidays[] = "4 July 2010";            // Falls on a Sunday; doesn't affect count
$holidays[] = "6 September 2010";        // Falls on a Monday; reduces count by one

echo networkdays($start, $end, $holidays);    // Returns 246

?>

Or, if you just want to know how many work days there are in any given year, here's a quick function for that one:

<?php

function workdaysinyear($y) {
   
$j1 = mktime(0,0,0,1,1,$y);
    if (
date("L", $j1)) {
        if (
date("N", $j1) == 6)
            return
260;
        elseif (
date("N", $j1) == 5 or date("N", $j1) == 7)
            return
261;
        else
            return
262;
    }
    else {
        if (
date("N", $j1) == 6 or date("N", $j1) == 7)
            return
260;
        else
            return
261;
    }
}

?>
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3
Tim Connolly
2 years ago
Here's my solution for looking up the month number by name (used when parsing an 'ls'):

<?php
 
for($m=1;$m<=12;$m++){
   
$month=date("M",mktime(0,0,0,$m,1,2000));
   
$mon["$month"]=$m;
  }
?>
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1
matthew dot hotchen at worldfirst dot com
8 months ago
FYI: there's a list of constants with predefined formats on the DateTime object, for example instead of outputting ISO 8601 dates with:

<?php
echo date('c');
?>

or

<?php
echo date('Y-m-d\TH:i:sO');
?>

You can use

<?php
echo date(DateTime::ISO8601);
?>

instead, which is much easier to read.
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3
webmaster1989 at gmail dot com
2 years ago
Sometimes it is very useful to convert a sql timestamp to an also called NTP time. This is often used as time date notation in XML RSS pages. To convert a timestamp to this NTP notation try the following:

<?php
 
echo date('D, d M Y h:i:s O', strtotime ($timestamp);
?>
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3
nathan
2 years ago
<?php
/* the following variables are set to appropriate
  characters recognized by php version 5 that
  will get the date. To display the date, we have
  to use 'echo' or 'print' to send the variable
  data to the browser
*/

$day=date("l");
$date=date("j");
$suffix=date("S");
$month=date("F");
$year=date("Y");
echo
$day . ", " . $month . " " . $date . $suffix . ", " . $year;
?>

rudimentary, simple way to due things, but it gets the job done for someone learning more on the subject.
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3
bakerj417 at gmail dot com
2 years ago
If you are having an issue getting u to work so is everyone else. The solution that I am using which I found on another site(so not taking credit) is to use this:

     date("Y/m/d H:i:s"). substr((string)microtime(), 1, 6);

that will give you:

     yyyy/mm/dd hh:ii:ss.uuuuuu

hope this helps someone in need!

thanks all
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2
gerben at gerbenwijnja dot nl
2 years ago
I use the function below to calculate the Unix timestamp of the start of a week. It includes a boolean flag to request a GMT offset instead of the current locale setting.

<?php

function getWeekOffsetTimestamp($year, $week, $useGmt = false) {
        if (
$useGmt) {
               
// Backup timezone and set to GMT
               
$timezoneSettingBackup = date_default_timezone_get();
               
date_default_timezone_set("GMT");
        }

       
// According to ISO-8601, January 4th is always in week 1
       
$halfwayTheWeek = strtotime($year."0104 +".($week - 1)." weeks");

       
// Subtract days to Monday
       
$dayOfTheWeek = date("N", $halfwayTheWeek);
       
$daysToSubtract = $dayOfTheWeek - 1;

       
// Calculate the week's timestamp
       
$unixTimestamp = strtotime("-$daysToSubtract day", $halfwayTheWeek);

        if (
$useGmt) {
               
// Reset timezone to backup
               
date_default_timezone_set($timezoneSettingBackup);
        }

        return
$unixTimestamp;
}

?>
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3
Edward Rudd
5 years ago
To actually make use ot the "u" (microsecond) you need to use the DateTime object and not the date() function.

For example

<?php
$t
= microtime(true);
$micro = sprintf("%06d",($t - floor($t)) * 1000000);
$d = new DateTime( date('Y-m-d H:i:s.'.$micro,$t) );

print
$d->format("Y-m-d H:i:s.u");
?>
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4
mel dot boyce at gmail dot com
8 years ago
I've been flicking through the comments looking for some succinct date code and have noticed an alarming number of questions and over-burdened examples related to date mathematics. One of the most useful skills you can utilize when performing date math is taking full advantage of the UNIX timestamp. The UNIX timestamp was built for this kind of work.

An example of this relates to a comment made by james at bandit-dot-co-dot-en-zed. James was looking for a way to calculate the number of days which have passed since a certain date. Rather than using mktime() and a loop, James can subtract the current timestamp from the timestamp of the date in question and divide that by the number of seconds in a day:
<?php
$days
= floor((time() - strtotime("01-Jan-2006"))/86400);
print(
"$days days have passed.\n");
?>

Another usage could find itself in a class submitted by Kyle M Hall which aids in the creation of timestamps from the recent past for use with MySQL. Rather than the looping and fine tuning of a date, Kyle can use the raw UNIX timestamps (this is untested code):
<?php
$ago
= 14; // days
$timestamp = time() - ($ago * 86400);
?>

Hopefully these two examples of "UNIX-style" timestamp usage will help those finding date mathematics more elusive than it should be.
up
2
JonathanCross.com
6 years ago
<?php
// A demonstration of the new DateTime class for those
// trying to use dates before 1970 or after 2038.
?>
<h2>PHP 2038 date bug demo (php version <?php echo phpversion(); ?>)</h1>
<div style='float:left;margin-right:3em;'>
<h3>OLD Buggy date()</h3>
<?php
  $format
='F j, Y';
  for (
$i = 1900; $i < 2050; $i++) {
   
$datep = "$i-01-01";
   
?>
    Trying: <?php echo $datep; ?> = <?php echo date($format, strtotime($datep)); ?><br>
    <?php
 
}
?></div>
<div style='float:left;'>
  <h3>NEW DateTime Class (v 5.2+)</h3><?php
 
for ( $i = 1900; $i < 2050; $i++) {
   
$datep = "$i-01-01";
   
$date = new DateTime($datep);
   
?>
    Trying: <?php echo $datep; ?> = <?php echo $date->format($format); ?><br>
    <?php
 
}
?></div>
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2
Just.Kevin
5 years ago
In order to determine if a year is a leap year an earlier poster suggested simply checking to see if the year is a multiple of four:

<?php
function is_leapyear_broken($year = 2004) {
return (
$year%4)==0;
}
?>

While this will work for the majority of years it will not work on years that are multiples of 100 but not multiples of 400 i.e.(2100).
A function not using php's date() function that will also account for this small anomaly in leap years:

<?php
function is_leapyear_working($year = 2004) {
    if(((
$year%4==0) && ($year%100!=0)) || $year%400==0) {
        return
true;
    }
    return
false;
}
?>

While is_leapyear_working will not return true for the few non-leap years divisible by four I couldn't tell you if this is more or less efficient than using php's date() as an even earlier poster suggested:

<?php
function is_leapyear($year = 2004) {
$is_leap = date('L', strtotime("$year-1-1"));
return
$is_leap;
}
?>
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1
frank at interactinet dot com
2 years ago
If you want to compare this week with the same week last year, here is some code to get you the time at the beginning of the week.  You can then add days, hours, etc to get to the day of the week that you want to know about.

<?php
        $time_passed
= (date('N')-1)* 24 * 3600; // time since start of week in days
       
$startOfWeek = mktime(0,0,0,date('m'),date('d'),date('Y')) - $time_passed;
       
   
       
$lastyear = $startOfWeek - 365*24*3600;   

       
// make sure time used from last year is the same week of the year   
       
$weekdiff = date('W') - date('W',$lastyear);
        if(
$weekdiff != 0)
        {
           
$lastyear = $lastyear + ($weekdiff*7*24*3600);
        }
       
       
$lastyear_time_passed = (date('N',$lastyear)-1) * 24 * 3600; // time since start of week in days
       
       
$startOfWeek_lastyear = mktime(0,0,0,date('m',$lastyear),date('d',$lastyear),date('Y',$lastyear)) - $lastyear_time_passed;
?>

So now you have the unix time for the start of this week ($startOfWeek), and the start of the same week last year ($startOfWeek_lastyear).

You can convert back to datetime format easily:

<?php
       
echo date('Y-m-d H:i:s',$startOfWeek).'<br>';
        echo
date('Y-m-d H:i:s',$startOfWeek_lastyear).'<br><br>';
       
        echo
date('l F jS, Y',$startOfWeek).'<br>';
        echo
date('l F jS, Y',$startOfWeek_lastyear);
?>
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0
Ryan
5 days ago
That  is just too hard anyone have it easier terms for a lad who only has internet for 5 mis a day cause he has to walk his pet peanut
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0
jock
4 months ago
As of PHP 5.3.3, date('c') will produce a string like this:

2014-06-17T16:22:42+02:00

Instead date (DATE_ISO8601) will produce:

2014-06-17T16:23:36+0200

which lacks the semicolon in the timezone part. Both are ISO8601 compliant anyway, but I found that the latter has better compatibility with other languages like python.
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0
david dot leon at gmx dot com
5 months ago
<?php
//date returns microseconds.
function mdate($format, $microtime = null) {
       
$microtime = explode(' ', ($microtime ? $microtime : microtime()));
        if (
count($microtime) != 2) return false;
       
$microtime[0] = $microtime[0] * 1000000;
       
$format = str_replace('u', $microtime[0], $format);
        return
date($format, $microtime[1]);
    }
?>

echo mdate('Y-m-d H:i:s.u');

2014-05-19 12:41:59.202303
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0
Bas Vijfwinkel
2 years ago
Note that some formatting options are different from MySQL.
For example using a 24 hour notation without leading zeros is the option '%G' in PHP but '%k' in MySQL.
When using dynamically generated date formatting string, be careful to generate the correct options for either PHP or MySQL.
up
0
Anonymous
6 years ago
Correct format for a MySQL DATETIME column is
<?php $mysqltime = date ("Y-m-d H:i:s", $phptime); ?>
up
0
jc
6 years ago
date("W") returns the iso8601 week number, while date("Y") returns the _current_ year. This can lead to odd results. For example today (dec 31, 2007) it returns 1 for the week and of course 2007 for the year. This is not wrong in a strict sense because iso defines this week as the first of 2008 while we still have 2007.

So, if you don't have another way to safely retrieve the year according to the iso8061 week-date - strftime("%G") doesn't work on some systems -, you should be careful when working with date("W").

For most cases strftime("%W") should be a safe replacement.

[edit: Much easier is to use "o" (lower case O) instead of "Y"]
up
-1
lb at bostontech dot net
4 years ago
Not sure why this got ignored the first time, but this is an even simpler way to check leap year:

<?php
function isLeapYear($year)
    { return (((
$year%4==0) && ($year%100)) || $year%400==0) ? (true):(false); }
?>
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-1
stokestack at gmail dot com
2 years ago
If you want to find your server's timezone offset from GMT, it seems as though you could just do:

date('Z')

to get the number of seconds offset. But PHP requires that you call date_default_timezone_set().  So if you have to hard-code a timezone, why not simply hard-code a variable that tells you the offset from GMT?  If you set the timezone to GMT, the dates in your database will still be in local time, but time('Z') will return zero.

To keep your code portable across servers in different timezones, you can do this:

date_default_timezone_set(date_default_timezone_get())

This keeps PHP from complaining that you haven't called date_default_timezone_set(), but makes your code portable.  Ridiculous.
up
-1
eduardo at digmotor dot com dot br
5 years ago
Thanks to tcasparr at gmail dot com for the great idea (at least for me) ;)
I changed the code a little to replicate the functionality of date_parse_from_format, once I don't have PHP 5.3.0 yet. This might be useful for someone. Hope you don't mind changing your code tcasparr at gmail dot com.

<?php
/*******************************************************
* Simple function to take in a date format and return array of associated
* formats for each date element
*
* @return array
* @param string $strFormat
*
* Example: Y/m/d g:i:s becomes
* Array
* (
*     [year] => Y
*     [month] => m
*     [day] => d
*     [hour] => g
*     [minute] => i
*     [second] => s
* )
*
*  This function is needed for  PHP < 5.3.0
********************************************************/
function dateParseFromFormat($stFormat, $stData)
{
   
$aDataRet = array();
   
$aPieces = split('[:/.\ \-]', $stFormat);
   
$aDatePart = split('[:/.\ \-]', $stData);
    foreach(
$aPieces as $key=>$chPiece)   
    {
        switch (
$chPiece)
        {
            case
'd':
            case
'j':
               
$aDataRet['day'] = $aDatePart[$key];
                break;
               
            case
'F':
            case
'M':
            case
'm':
            case
'n':
               
$aDataRet['month'] = $aDatePart[$key];
                break;
               
            case
'o':
            case
'Y':
            case
'y':
               
$aDataRet['year'] = $aDatePart[$key];
                break;
           
            case
'g':
            case
'G':
            case
'h':
            case
'H':
               
$aDataRet['hour'] = $aDatePart[$key];
                break;   
               
            case
'i':
               
$aDataRet['minute'] = $aDatePart[$key];
                break;
               
            case
's':
               
$aDataRet['second'] = $aDatePart[$key];
                break;           
        }
       
    }
    return
$aDataRet;
}
?>

Also, if you need to change the format of dates:

<?php
function changeDateFormat($stDate,$stFormatFrom,$stFormatTo)
{
 
// When PHP 5.3.0 becomes available to me
  //$date = date_parse_from_format($stFormatFrom,$stDate);
  //For now I use the function above
 
$date = dateParseFromFormat($stFormatFrom,$stDate);
  return
date($stFormatTo,mktime($date['hour'],
                                   
$date['minute'],
                                   
$date['second'],
                                   
$date['month'],
                                   
$date['day'],
                                   
$date['year']));
}

?>
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-1
m_ocx at yahoo dot com
2 years ago
Here is a cool Date class to implement the date function:

<?php
/*
* @author    Gchats
*
* Date class
*/
class Date
{   
    private
$shortDateFormat = "F j, Y";
    private
$longDateFormat = "F j, Y, g:i a";
    private
$timestamp = 0;
   
   
/**
    * Default constructor
    *
    * @param    integer        $timestamp    unix time stamp
    */
   
function __construct($timestamp = 0)
    {
       
$this->timestamp = $timestamp;
    }
   
   
/**
    * Returns the given timestamp in the constructor
    *
    * @return    integer        time stamp
    */
   
public function getTime()
    {
        return (int)
$this->timestamp;
    }
   
   
/*
     * Returns long formatted date of the given timestamp
     *
     * @access public
     * @return     string    Long formatted date
     */
   
public function long()
    {
        if (
$this->timestamp > 0 )
        {
            return
date ( $this->longDateFormat , $this->timestamp );
        }
        else
        {
            return
"";
        }
    }

   
/*
     * Returns short formatted date of the given timestamp
     *
     * @access public
     * @return     string    Short formatted date
     */   
   
public function short()
    {
        if (
$this->timestamp > 0 )
        {
            return
date ( $this->shortDateFormat , $this->timestamp );
        }
        else
        {
            return
"";
        }
    }
   
    public function
__toString()
    {
        return
$this->timestamp;
    }
   
}
?>
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-1
@PeteWilliams
4 years ago
If you want to use HTML5's <date> tag, the following code will generate the machine-readable value for the 'datetime' attribute:

<?php

/**
* formats the date passed into format required by 'datetime' attribute of <date> tag
* if no intDate supplied, uses current date.
* @param intDate integer optional
* @return string
**/
function getDateTimeValue( $intDate = null ) {

   
$strFormat = 'Y-m-d\TH:i:s.uP';
   
$strDate = $intDate ? date( $strFormat, $intDate ) : date( $strFormat ) ;
   
    return
$strDate;
}

echo
getDateTimeValue();

?>
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-2
Anonymous
1 year ago
Was trying to compare dates when I noticed that:

<?php

var_dump
(date('d.m.Y', null));//string(10) "01.01.1970"
var_dump(date('d.m.Y', ''));//bool(false)

?>

Thought it's worth mentioning. Caused some weird logs to be produced in our system since this does not evaluate to the same.
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-2
scott at keenot dot es
1 year ago
If anyone needs a really fast function for converting a datetime string (i.e. as retrieved from a MySQL DATETIME entry) into a human-friendly time output analogous to date($format, $time), here's a useful function.

<?php
function fdate($datetimestring = '1970-01-01 00:00:00', $format = 'U') {
 
// Create a datetime object, return it formatted
  // If you want to give credit for this somewhere, thanks.
  // You really don't have to though; this is kinda obvious
 
$dt = new DateTime($datetimestring);
  return
$dt->format($format);
}
?>

The main purpose of this is to reduce lines of code and allow inline coding. For example:
<?php
/* ... */
echo "This page was submitted on ".fdate($row['created'], 'F j, Y g:i:s A')." and last modified ".fdate($row['modified'], 'F j, Y g:i:s A')."<br />\n";
/* ... */
?>
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-5
Anon
2 years ago
I needed to convet a duration timestamp into H:i:s but whenever I did it kept bringing 5 back as 01:00:05 (due to some DST stuff) so I made this function to replace date(). It has no optimisations but hopefully someone might find it useful:

<?php
   
function get_time_string(){
       
$time = 3600+(60*32)+(50); // 01:32:50
       
$time_string = '';

       
$hours = (int)($time/(60*60));
        if(
strlen($hours) > 1){
           
$time_string = $hours.':';
        }else{
           
$time_string = '0'.$hours.':';
        }

       
$minutes = (int)(($time%(60*60))/(60));
        if(
$minutes >= 1){
            if(
strlen($minutes) > 1){
               
$time_string .= $minutes.':';
            }else{
               
$time_string .= '0'.$minutes.':';
            }

           
$seconds = ($time%(60*60))%(60);
            if(
strlen($seconds) > 1){
               
$time_string .= $seconds;
            }else{
               
$time_string .= '0'.$seconds;
            }
        }else{
            if(
strlen($time) > 1){
               
$time_string .= '00:'.$time;
            }else{
               
$time_string .= '00:0'.$time;
            }
        }
        return
$time_string;
    }
?>
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-4
Chris
2 years ago
Use this to convert the local/UTC hour to the UTC/local hour:

<?php
for($utc_to_local = array(), $offset = date('Z'), $h = 0; $h < 24; $utc_to_local[] = date('G', mktime($h++)+$offset));
$local_to_utc = array_flip($utc_to_local);

echo
"2 am local is ", $local_to_utc[2], " UTC";
echo
"3 pm UTC is ", $utc_to_local[15], " local";
?>

This is useful when you need to do many conversions. Lookup tables are faster than calling date() and mktime() multiple times.
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-5
chubby at chicks dot com
6 years ago
<?php
/**
     * Checks wether a date is between an interval
     *
     * Usage:
     *     
     * // check if today is older than 2008/12/31
     * var_dump(currentDayIsInInterval('2008/12/31'));
     * // check if today is younger than 2008/12/31
     * var_dump(currentDayIsInInterval(null,'2008/12/31'));
     * // check if today is between 2008/12/01 and 2008/12/31
     * var_dump(currentDayIsInInterval('2008/12/01','2008/12/31')); 
     *
     * Will trigger errors if date is in wrong format, notices if $begin > $end    
     *         
     * @param string $begin Date string as YYYY/mm/dd
     * @param string $end Date string as YYYY/mm/dd
     * @return bool 
     */
function currentDayIsInInterval($begin = '',$end = '')
{
       
$preg_exp = '"[0-9][0-9][0-9][0-9]/[0-9][0-9]/[0-9][0-9]"';
       
$preg_error = 'Wrong parameter passed to function '.__FUNCTION__.' : Invalide date
format. Please use YYYY/mm/dd.'
;
       
$interval_error = 'First parameter in '.__FUNCTION__.' should be smaller than
second.'
;
        if(empty(
$begin))
        {
               
$begin = 0;
        }
        else
        {
                if(
preg_match($preg_exp,$begin))
                {
                       
$begin = (int)str_replace('/','',$begin);
                }
                else
                {
                       
trigger_error($preg_error,E_USER_ERROR);
                }
        }
        if(empty(
$end))
        {
               
$end = 99999999;
        }
        else
        {
                if(
preg_match($preg_exp,$end))
                {
                       
$end = (int)str_replace('/','',$end);
                }
                else
                {
                       
trigger_error($preg_error,E_USER_ERROR);
                }
        }
        if(
$end < $begin)
        {
               
trigger_error($interval_error,E_USER_WARNING);
        }
       
$time = time();
       
$now = (int)(date('Y',$time).date('m',$time).date('j',$time));
        if(
$now > $end or $now < $begin)
        {
                return
false;
        }
        return
true;
}
?>
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-2
ttt_joe_08
9 months ago
Just FYI, it's more appropriate to say "UTC", not "GMT". GMT was given up in 1972 and UTC is now the proper way. The reason being G stands for Greenwich, which naturally upset some people.
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Anonymous
2 years ago
To find last sunday for given date

<?php
         $day
= '2012-10-04';
         echo
'last sunday :  '.date("Y-m-d",strtotime($day." last Sunday "));
?>

output:

last sunday : 2012-09-30
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-7
lehal2 at hotmail dot com
2 years ago
here is an example how you can make numeric days of the week from 1 to 7(Monday to Friday)

<?php
$currentdate 
= mktime(0, 0, 0, date("m")  , date("d"), date("Y"));
     echo
$day_eg1 = date ('N',$currentdate);
      echo
$day_eg2 = date("N", $today+1 * 24 * 3600);
    echo
$day_eg3= date("N", $today+2 * 24 * 3600);
    echo
$day_eg4 = date("N", $today+3 * 24 * 3600);
    echo
$day_eg5 = date("N", $today+4 * 24 * 3600);
    echo
$day_eg6 = date("N", $today+5 * 24 * 3600);
    echo
$day_eg7 = date("N", $today+6 * 24 * 3600);
?>
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blinov vyacheslav AT gmail.com
3 years ago
It was oblivious and discouraging that it dont mentioned in docs. If you will use W to get week number be aware:
first days of year can be in a week of previous year, and week number always has leading zero

<?php

echo date("YW", strtotime("2011-01-07")); // gives 201101
echo date("YW", strtotime("2011-01-01")); // gives 201152
echo date("YW", strtotime("2011-12-31")); // gives 201152 too

?>

so you can`t rely on number of week given from this function inside your program if you want to use it for some logic
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-5
Jacques Marais
9 months ago
If you want to print something like: Tuesday, the 14th of January, 2014

Use this:

<?php
echo date("l", strtotime("now")).', the'.date(" jS", strtotime("now")).' of'.date(" F, Y", strtotime("now"));
?>

This is because you cannot use words in the date string. If you use words in the date string it will be seen as a format character

So if you use:

<?php
echo date("l, the jS of F, Y", strtotime("now"));
?>

It will print something like: Tuesday, 3108Europe/Berlin 14th 2014f January, 2014
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-18
matt
2 years ago
date() has some strange behavior at extremely high values:

<?php
echo "9223372036854775805: " . date("Y-m-d g:i:s a"9223372036854775805) . "\n";
echo
"9223372036854775806: " . date("Y-m-d g:i:s a"9223372036854775806) . "\n";
echo
"9223372036854775807: " . date("Y-m-d g:i:s a"9223372036854775807) . " (0x7FFFFFFFFFFFFFFF)\n";
echo
"9223372036854775808: " . date("Y-m-d g:i:s a"9223372036854775808) . "\n";
echo
"9223372036854775809: " . date("Y-m-d g:i:s a"9223372036854775809) . "\n";
echo
"9223372036854775810: " . date("Y-m-d g:i:s a"9223372036854775810) . "\n";
echo
"...\n";
echo
"9223372036854776832: " . date("Y-m-d g:i:s a"9223372036854776832) . "\n";
echo
"9223372036854776833: " . date("Y-m-d g:i:s a"9223372036854776833) . "\n";
echo
"...\n";
echo
"9223372036854778879: " . date("Y-m-d g:i:s a"9223372036854778879) . "\n";
echo
"9223372036854778880: " . date("Y-m-d g:i:s a"9223372036854778880) . "\n";
echo
"...\n";
echo
"9223372036854780928: " . date("Y-m-d g:i:s a"9223372036854780928) . "\n";
echo
"9223372036854780929: " . date("Y-m-d g:i:s a"9223372036854780929) . "\n";
echo
"...\n";
echo
"9223372036854782975: " . date("Y-m-d g:i:s a"9223372036854782975) . "\n";
echo
"9223372036854782976: " . date("Y-m-d g:i:s a"9223372036854782976) . "\n";
echo
"...\n";
echo
"9223372036854785024: " . date("Y-m-d g:i:s a"9223372036854785024) . "\n";
echo
"9223372036854785025: " . date("Y-m-d g:i:s a"9223372036854785025) . "\n";
echo
"...\n";
echo
"9223372036854787071: " . date("Y-m-d g:i:s a"9223372036854787071) . "\n";
echo
"9223372036854787072: " . date("Y-m-d g:i:s a"9223372036854787072) . "\n";
echo
"...\n";
echo
"9223372036854789120: " . date("Y-m-d g:i:s a"9223372036854789120) . "\n";
echo
"9223372036854789121: " . date("Y-m-d g:i:s a"9223372036854789121) . "\n";
echo
"...\n";
echo
"9223372036854791167: " . date("Y-m-d g:i:s a"9223372036854791167) . "\n";
echo
"9223372036854791168: " . date("Y-m-d g:i:s a"9223372036854791168) . "\n";
echo
"...\n";
echo
"9223372036854793215: " . date("Y-m-d g:i:s a"9223372036854793215) . "\n";
echo
"9223372036854793216: " . date("Y-m-d g:i:s a"9223372036854793216) . "\n";
echo
"9223372036854793217: " . date("Y-m-d g:i:s a"9223372036854793217) . "\n";
echo
"9223372036854793218: " . date("Y-m-d g:i:s a"9223372036854793218) . "\n";
?>

Output:

9223372036854775805: 292277026596-12-04 10:30:05 am
9223372036854775806: 292277026596-12-04 10:30:06 am
9223372036854775807: 292277026596-12-04 10:30:07 am (0x7FFFFFFFFFFFFFFF)
9223372036854775808: 292277026596-12-04 10:30:08 am
9223372036854775809: 292277026596-12-04 10:30:08 am
9223372036854775810: 292277026596-12-04 10:30:08 am
...
9223372036854778879: 292277026596-12-04 10:30:08 am
9223372036854778880: 292277026596-12-04 11:04:16 am
...
9223372036854778879: 292277026596-12-04 11:04:16 am
9223372036854778880: 292277026596-12-04 11:38:24 am
...
9223372036854780928: 292277026596-12-04 11:38:24 am
9223372036854780929: 292277026596-12-04 12:12:32 pm
...
9223372036854782975: 292277026596-12-04 12:12:32 pm
9223372036854782976: 292277026596-12-04 12:46:40 pm
...
9223372036854785024: 292277026596-12-04 12:46:40 pm
9223372036854785025: 292277026596-12-04 1:20:48 pm
...
9223372036854787071: 292277026596-12-04 1:20:48 pm
9223372036854787072: 292277026596-12-04 1:54:56 pm
...
9223372036854789120: 292277026596-12-04 1:54:56 pm
9223372036854789121: 292277026596-12-04 2:29:04 pm
...
9223372036854791167: 292277026596-12-04 2:29:04 pm
9223372036854791168: 292277026596-12-04 3:03:12 pm
...
9223372036854793215: 292277026596-12-04 3:03:12 pm
9223372036854793216: 292277026596-12-04 3:03:12 pm
9223372036854793217: -292277022657-01-27 8:37:04 am
9223372036854793218: -292277022657-01-27 8:37:04 am

---

So, the last reliable unix timecode is 9223372036854775808 (0x1000000000000000). Not that you would probably ever need a date that high.
up
-3
Manu Manjunath
6 months ago
If you want to use "u" format specifier for micrseconds without changing to DateTime object, you may write a function as below:
<?php
/**
* Quick replacement to date() function to handle the 'u' format specifier (for microseconds)
* @param string $format Date format string - the same format string you would pass to date() function
* @param float $timestamp [optional] Unix timestamp with microseconds - Typically output of <b>microtime(true)</b>
* @return string Formatted string
*/
function date_with_micro($format, $timestamp = null) {
    if (
is_null($timestamp) || $timestamp === false) {
       
$timestamp = microtime(true);
    }
   
$timestamp_int = (int) floor($timestamp);
   
$microseconds = (int) round(($timestamp - floor($timestamp)) * 1000000.0, 0);
   
$format_with_micro = str_replace("u", $microseconds, $format);
    return
date($format_with_micro, $timestamp_int);
}
?>

You can safely replace your date() function with date_with_micro().
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