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mysql_fetch_row

(PHP 4, PHP 5)

mysql_fetch_rowGet a result row as an enumerated array

Warning

This extension is deprecated as of PHP 5.5.0, and will be removed in the future. Instead, the MySQLi or PDO_MySQL extension should be used. See also MySQL: choosing an API guide and related FAQ for more information. Alternatives to this function include:

Description

array mysql_fetch_row ( resource $result )

Returns a numerical array that corresponds to the fetched row and moves the internal data pointer ahead.

Parameters

result

The result resource that is being evaluated. This result comes from a call to mysql_query().

Return Values

Returns an numerical array of strings that corresponds to the fetched row, or FALSE if there are no more rows.

mysql_fetch_row() fetches one row of data from the result associated with the specified result identifier. The row is returned as an array. Each result column is stored in an array offset, starting at offset 0.

Examples

Example #1 Fetching one row with mysql_fetch_row()

<?php
$result 
mysql_query("SELECT id,email FROM people WHERE id = '42'");
if (!
$result) {
    echo 
'Could not run query: ' mysql_error();
    exit;
}
$row mysql_fetch_row($result);

echo 
$row[0]; // 42
echo $row[1]; // the email value
?>

Notes

Note: This function sets NULL fields to the PHP NULL value.

See Also

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User Contributed Notes 8 notes

up
6
michael and then an at sign wassupy.com
11 years ago
to print an array, simply use print_r(array name)

like this:
    $myrow = mysql_fetch_row($result);
echo "<pre>";
print_r($myrow);
echo "</pre>";

this will output the array in a readable form, with the index, too. Don't forget the 'pre' tags or the output will be on a single line.
up
1
murapaka dot sateesh at gmail dot com
2 months ago
<?php

$conn
=mysql_connect("localhost","root","");
if(
$conn)
{
    echo(
"Connection Successfully");
   
$seldb=mysql_select_db("test",$conn);
    if(
$seldb)
    {
        echo(
"Database selected successfully");
       
$retrive=mysql_query("select name,number from login1 where name='sateesh'",$conn);
        if(
$retrive)
        {
            echo(
"Successfully data retrived<br>");
           
           
$result=mysql_fetch_row($retrive);
           
                echo (
"Name".$result[0]);
                echo (
"Number".$result[1]);
                   
        }
        else
        {
        echo
"Table not inserted";
        }
        }
        else
        {
            die(
"database not selected");
        }
    }
    else
    {
        die(
"connection faild");   
    }
   
mysql_close($conn);
?>
up
0
m dot s at programmers-online dot net
8 years ago
The following function to read all data out of a mysql-resultset, is may be faster than Rafaels solution:

<?
function mysql_fetch_all($result) {
   while($row=mysql_fetch_array($result)) {
       $return[] = $row;
   }
   return $return;
}
?>
up
-2
a at simongrant dot org
12 years ago
Maybe worth pointing out that all the fields returned by this (and other?) calls are returned with type string. This had me puzzled for quite some time.
up
-4
ryhan_balboa at yahoo dot com
6 years ago
The following are the basic codes to get a specific row from the mysql db into a $row variable:


$query = "SELECT * FROM table";
$result = mysql_query($query);
$row = mysql_fetch_row($result);

And $row[0], $row[1] ... $row[n] are used to access those field values.

Does anyone know how I can add a new field to $row, so that the field count increases from n to n+1?

I have tried treating $row like an array, and tried array_push function, but didn't work.

Thanks.
up
-4
pepik at gmail dot cz
1 year ago
<?php 
 
require 'prhlavicka.php';
 
pis_hlavicku('Vypis článků');        
   
   require_once
'db.php';
   
$kom = new server();
   
$sql=$kom->query("SELECT autor,nazev,obsah FROM `Clanky_Sadek`");
               while (
$data = mysql_fetch_row($sql)){
                 ECHO
'<br />--AUTOR--<br />'.$data[0].'<br />__NÁZEV ČLÁNKU__<br />'.$data[1].'<br />..OBSAH ČLÁNKU..<br />'.$data[2];     }   
 
  include
'Paticka.html'; ?>
up
-5
larkitetto at gmail dot com
6 years ago
sry :) note now fixed:

<?php
$esi
=mysql_list_tables($db);$ris=mysql_fetch_row($esi);
//example: $db has >= 1 tabs
echo var_dump($ris);
//echoes only array(1). solution:
while($ris=mysql_fetch_row($esi)) echo $ris[0];
/*debug:
$ris=array("1st_tab"); ... $ris=array("n_tab");$ris=false;*/
while ($ris[]=mysql_fetch_row($esi));
//debug:$ris=array(array("1st_tab"), ... array("n_tab"));
echo $ris[n][0];//echo:"n_tab"
echo $ris[0][n];//echo:array | null
?>

hope it helps
up
-9
jhulbert at redf dot com
4 years ago
Creates table from all db info:

<?php
$qry
= "SELECT * FROM exp_member_data";
$res = mysql_query($mem_qry);

function
mysql_fetch_all($res) {
   while(
$row=mysql_fetch_array($res)) {
      
$return[] = $row;
   }
   return
$return;
}

function
create_table($dataArr) {
    echo
"<tr>";
    for(
$j = 0; $j < count($dataArr); $j++) {
        echo
"<td>".$dataArr[$j]."</td>";
    }
    echo
"</tr>";
}

$all = mysql_fetch_all($res);

echo
"<table class='data_table'>";

for(
$i = 0; $i < count($all); $i++) {
   
create_table($all[$i]);
}

echo
"</table>";

?>
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