PHP 5.4.31 Released

zip_entry_name

(PHP 4 >= 4.1.0, PHP 5 >= 5.2.0, PECL zip >= 1.0.0)

zip_entry_nameRetrieve the name of a directory entry

Description

string zip_entry_name ( resource $zip_entry )

Returns the name of the specified directory entry.

Parameters

zip_entry

A directory entry returned by zip_read().

Return Values

The name of the directory entry.

See Also

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User Contributed Notes 2 notes

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0
kevyn at opsone dot net
5 years ago
Big note for filename with accents.

Some Zip softwares encode accents with CP850.

So use iconv for keeping your accents SAFE !
up
0
leandro_dealmeida at hotmail dot com
11 years ago
If you want to get the real name of the file without the directory name, you can just use the function basename() as the follow:

<?
$zip_dir = "./import/";
$zip = zip_open($zip_dir."import.zip");
if ($zip) {
    while ($zip_entry = zip_read($zip)) {

        $file = basename(zip_entry_name($zip_entry));
        $fp = fopen($zip_dir.basename($file), "w+");
       
        if (zip_entry_open($zip, $zip_entry, "r")) {
            $buf = zip_entry_read($zip_entry, zip_entry_filesize($zip_entry));
            zip_entry_close($zip_entry);
        }
       
           fwrite($fp, $buf);
        fclose($fp);
       
        echo "The file ".$file." was extracted to dir ".$zip_dir."\n<br>";
    }
    zip_close($zip);
}
?>

Thefore you can extract files without concern with the directory that is set inside the zip source.

Remember to give write permission (w) on that directory.

Hello from Brazil.
Leandro
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