PHP 5.4.33 Released

ArrayObject::__construct

(PHP 5 >= 5.0.0)

ArrayObject::__constructساخت شی آرایه جدید

Description

ArrayObject::__construct() ([ mixed $input [, int $flags [, string $iterator_class ]]] )

ساخت object آرایه جدید.

Parameters

input

پارامتر input array یا Object.

flags

پرچم‌های کنترل رفتار شی ArrayObject.

iterator_class

تعیین کلاس استفاده شده برای تکرار شی ArrayObject. ArrayIterator کلاس پیش‌فرض مورد استفاده است.

Return Values

No value is returned.

Examples

Example #1 مثال ArrayObject::__construct()

<?php
$array 
= array('1' => 'one',
               
'2' => 'two',
               
'3' => 'three');

$arrayobject = new ArrayObject($array);

var_dump($arrayobject);
?>

The above example will output:

object(ArrayObject)#1 (3) {
  [1]=>
  string(3) "one"
  [2]=>
  string(3) "two"
  [3]=>
  string(5) "three"
}

See Also

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User Contributed Notes 6 notes

up
3
kjarli at gmail dot com
1 year ago
As of PHP 5.3 I recommend to use this, I have replace "new self" by "new static". This allows you to extend this class by your own and let your class create itself recursively without overwriting the constructor.

<?php
/**
* @author Iltar van der Berg
* @version 2.0.0
*/
class RecursiveArrayObject extends ArrayObject
{
   
/**
     * overwrites the ArrayObject constructor for
     * iteration through the "array". When the item
     * is an array, it creates another self() instead
     * of an array
     *
     * @param Array $array data array
     */
   
public function __construct(Array $array)
    {   
        foreach(
$array as $key => $value) {
            if(
is_array($value)){
               
$value = new static($value);
            }
           
$this->offsetSet($key, $value);
        }
    }
   
   
/**
     * returns Array when printed (like "echo array();")
     * instead of an error
     *
     * @return string
     */
   
public function __ToString()
    {
        return
'Array';
    }
}
?>
up
1
german dot rumm at gmail dot com
6 years ago
BTW, if you need to change array later, use exchangeArray() method. Good to know when you are writing a class that extends ArrayObject()

AFAIK, exchangeArray() doesn't return anything.

<?php
    $a
= array('one', 'two', 'three');
   
$ao = new ArrayObject($a);

    foreach (
$ao as $element) {
        echo
$element . ' '; // one two three
   
}

   
$b = array('four', 'five', 'six');
   
$ao->exchangeArray($b); // returns null

   
foreach ($ao as $element) {
        echo
$element . ' '; // four five six
   
}
?>
up
0
ashley at nospam dot zincdigital dot com
5 years ago
The great confusion with this class is in its naming.  ArrayObject infers it will behave as an Array and as an Object.  It won't.  It behaves as an array.  It would better be called ArrayType.  You can, with some work, get it to work both as an object and as an array, but that is up to you.
up
0
kjarli at gmail dot com
6 years ago
This extend allows multidimensional arrays to be converted aswell. It also returns 'Array' when echoed (unlike ArrayObject which gives an error).
<?php
/**
* @author iltar van der berg
* @version 1.0.1
*/
class RecursiveArrayObject extends ArrayObject
{
   
/**
     * overwrites the ArrayObject constructor for
     * iteration through the "array". When the item
     * is an array, it creates another self() instead
     * of an array
     *
     * @param Array $array data array
     */
   
public function __construct(Array $array)
    {   
        foreach(
$array as $key => $value) {
            if(
is_array($value)){
               
$value = new self($value);
            }
           
$this->offsetSet($key, $value);
        }
    }
   
   
/**
     * returns Array when printed (like "echo array();")
     * instead of an error
     *
     * @return string
     */
   
public function __ToString()
    {
        return
'Array';
    }
}
?>
up
0
agalkin at agalkin dot ru
7 years ago
Note that the first argument to ArrayObject::__construct, the initial array, is passed by reference. Nevertheless, modification of the array doesn't modify the object, so it may cause unexpected behaviour.

<?php
$array
= array('foo' => 'initial');
$obj = new ArrayObject($array);

// array was passed by reference:
$obj['foo'] = 'modified';
var_dump($array); // foo => modified

// but it doesn't work backwards:
$array['foo'] = 'modified_again';
var_dump($obj); // foo => modified
var_dump($array); // foo => modified_again
?>
up
0
Grigori Kochanov
8 years ago
As Marcus explained, the flag ArrayObject::SPL_ARRAY_AS_PROPS means the array element may be used as a property if there is no conflict with visible properties.

If there are visible properties in the class, the array element will not overwrite it's value.

<?php
class Rules extends ArrayObject {
    public
$len = 1;
    function
__construct($array){
       
parent::__construct($array,ArrayObject::ARRAY_AS_PROPS);
       
$this['len'] = 2;
    }
}
$x = new Rules(array(1,2));
echo
$x->len;
?>
Result: 1

<?php
class Rules extends ArrayObject {
    private
$len = 1;
    function
__construct($array){
       
parent::__construct($array,ArrayObject::ARRAY_AS_PROPS);
       
$this['len'] = 2;
    }
}
$x = new Rules(array(1,2));
echo
$x->len;
?>
Result: 2
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