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(PHP 4, PHP 5)

mysql_field_nameGet the name of the specified field in a result


string mysql_field_name ( resource $result , int $field_offset )

mysql_field_name() returns the name of the specified field index.



The result resource that is being evaluated. This result comes from a call to mysql_query().


The numerical field offset. The field_offset starts at 0. If field_offset does not exist, an error of level E_WARNING is also issued.

Return Values

The name of the specified field index on success or FALSE on failure.


Example #1 mysql_field_name() example

/* The users table consists of three fields:
 *   user_id
 *   username
 *   password.
$link mysql_connect('localhost''mysql_user''mysql_password');
if (!
$link) {
'Could not connect to MySQL server: ' mysql_error());
$dbname 'mydb';
$db_selected mysql_select_db($dbname$link);
if (!
$db_selected) {
"Could not set $dbname: " mysql_error());
$res mysql_query('select * from users'$link);

mysql_field_name($res0) . "\n";

The above example will output:



Note: Field names returned by this function are case-sensitive.


For backward compatibility, the following deprecated alias may be used: mysql_fieldname()

See Also

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User Contributed Notes 12 notes

anonymous at site dot com
9 years ago
This function is slightly stupid to be honest, why not just make an array of field names... You could consolidate the two of these functions that way and it makes it a lot easier to list them when your script is dynamic.


function mysql_field_array( $query ) {
$field = mysql_num_fields( $query );
        for (
$i = 0; $i < $field; $i++ ) {
$names[] = mysql_field_name( $query, $i );
// Examples of use
$fields = mysql_field_array( $query );
// Show name of column 3
echo $fields[3];
// Show them all
echo implode( ', ', $fields[3] );
// Count them - easy equivelant to 'mysql_num_fields'
echo count( $fields );

11 years ago
james, why make so difficult when it's very simple :\

$numberfields = mysql_num_fields($res_gb);

   for ($i=0; $i<$numberfields ; $i++ ) {
       $var = mysql_field_name($res_gb, $i);
       $row_title .= $var;

echo $row_title;
jimharris at blueyonder dot co dot uk
13 years ago
The code in the last comment has an obvious mistake in the for loop expression.  The correct expression in the for-loop is $x<$y rather than $x<=$y...

$result = mysql_query($sql,$conn) or die(mysql_error());
for ($x=0; $x<$y; $x++) {
   echo = mysql_field_name($result, $x).'<br>';
janezr at jcn dot si
12 years ago
This is another variant of displaying all columns of a query result, but with a simplified while loop.

$query="select * from user";
$numfields = mysql_num_fields($result);

echo "<table>\n<tr>";

for ($i=0; $i < $numfields; $i++) // Header
{ echo '<th>'.mysql_field_name($result, $i).'</th>'; }

echo "</tr>\n";

while ($row = mysql_fetch_row($result)) // Data
{ echo '<tr><td>'.implode($row,'</td><td>')."</td></tr>\n"; }

echo "</table>\n"
matt at iwdt dot net
16 years ago
here's one way to print out a row of <th> tags from a table
NOTE: i didn't test this

$result = mysql_query("select * from table");

for ($i = 0; $i < mysql_num_fields($result); $i++) {
    print "<th>".mysql_field_name($result, $i)."</th>\n";

post a comment if there's an error
jason dot chambes at phishie dot net
15 years ago
    By simply calling the searchtable() function
    with these variables it will serach the desired
    database and procude a table for each field that
    there is a match.

function searchtable($host,$user,$pass,$database,$tablename,$userquery)
    $link   = mysql_connect($host, $user, $pass) or die("Could not connect: " . mysql_error());
    $db     = mysql_select_db($database, $link) or die(mysql_error());
    $fields = mysql_list_fields($database, $tablename, $link);
    $cols   = mysql_num_fields($fields);

    for ($i = 1; $i < $cols; $i++) {
        $allfields[] = mysql_field_name($fields, $i);
    foreach ($allfields as $myfield) {
        $result = mysql_query("SELECT * FROM $tablename WHERE $myfield like '%$userquery%' ");
        if (mysql_num_rows($result) > 0){
            echo "<h3>search <i>$database</i> for <i>$userquery</i>, found match(es) in <i>$myfield</i>: </h3>\n";
            echo "<table border=1 align=\"center\">\n\t<tr>\n";
            for ($i = 1; $i < $cols; $i++) {
                echo "\t\t<th";
                if ($myfield == mysql_field_name($fields, $i)){
                    echo " bgcolor=\"orange\"> ";
                } else {
                    echo ">";
                echo mysql_field_name($fields, $i) . "</th>\n";
            echo "\t</tr>\n";
            $myrow = mysql_fetch_array($result);
            do {
                echo "\t<tr>\n";
                for ($i = 1; $i < $cols; $i++){
                    echo "\t\t<td> $myrow[$i] &nbsp;</td>\n";
                echo "\t</tr>\n";
            } while ($myrow = mysql_fetch_array($result));
            echo "</table>\n";

blackjackdevel at gmail dot com
10 years ago
Strangely using an aproach like this:
$res=mysql_query("SELECT * FROM `orders`",$conec) or die (mysql_error());

$fields = mysql_num_fields($res);
for ($i = 0; $i < $fields; $i++) {
    $fname=mysql_field_name($res, $i);


Outputted the E_Warning:
Warning: mysql_field_name() [function.mysql-field-name]: Field N is invalid for MySQL result index

With a lot of different number at N. But expliciting all fields instead of *. Didn't outputted the error.

It maybe a caracteristic of this mysql database(it is from a open source application) because i never saw this in my own databases. Anyway hope this help if someone face the same strange situation
tiptonentserv at gmail dot com
6 years ago
simple sql to xml converter works with any sql query and returns the name of the table as the root element "row" as each row element and the names of the columns are your children of row. fully tested.

function sqlToXml($host,$user,$pass,$database,$tablename,$query){

$link   = mysql_connect($host, $user, $pass) or die("Could not connect: " . mysql_error());
$db     = mysql_select_db($database, $link) or die(mysql_error());
$result = mysql_query($query);
$result){ die('Invalid query: '.mysql_error()); }
$numOfCols = mysql_num_fields($result);
$numOfRows = mysql_num_rows($result);
$info = mysql_fetch_assoc($result);
//send headers
header('Content-type: text/xml');
header('Pragma: public');       
header('Cache-control: private');
header('Expires: -1');
$xml = '<?xml version="1.0" encoding="utf-8"?>';
$xml.= "<{$tablename}>";
$numOfRows > 0){
        do {
$xml.= "<row>";
$info as $column => $value) {
$xml.= "<{$column}>{$value}</{$column}>";
$xml.= "</row>";
        while (
$info = mysql_fetch_array($result));
$xml.= "</{$tablename}>";
7 years ago
When using aliases, it appears impossible to discover the name of the underlying column.
select `ID` as `anAlias` from `aTable` returns 'anAlias' as the mysql_field_name(). I have tried all the mysql_field_xxx() functions and none return the real column name.
clinnenb at hotmail dot com
12 years ago
The following will create a PHP array, $array, containing the MySQL query results with array indexes of the same name as field names returned by the MySQL query.

while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
    foreach ($line as $col_value) {
        $array[$field] = $col_value;
colin dot truran at shiftf7 dot com
13 years ago
T simply itterate through all the field names on a result set try using this.

$result = mysql_query($sql,$conn) or die(mysql_error());
for ($x=0; $x<=$y; $x++) {
    echo = mysql_field_name($result, $x).'<br>';

This is useful if you have a result set that joins several tables dynamicaly and you are never sure what all the fields will be when you come to display them.

I suggest you place this within a loop through your result rows and include a field flag check  around the echo to only show certain data types like this.

while ($row=mysql_fetch_array($result)) {
  for ($x=0; $x<=$y; $x++) {
    $fieldtype=mysql_field_type($result, $x);
    if ($fieldtype=='string' && $row[$fieldname]!='')   
       echo $row[$fieldname].' , ';
   echo '<br>';
aaronp123 att yahoo dott comm
14 years ago
You could probably elaborate on this by sending a full sql query to this function...but I titled it simple_query() because it doesn't really allow for joins.  Never the less, if you want to get a quick array full of a single row result set this is painless:

function simple_query($table_name, $key_col, $key_val) {
    // open the db
    $db_link = my_sql_link();
    // query table using key col/val
    $db_rs = mysql_query("SELECT * FROM $table_name WHERE $key_col = $key_val", $db_link);
    $num_fields = mysql_num_fields($db_rs);
    if ($num_fields) {
        // first (and only) row
        $row = mysql_fetch_assoc($db_rs);
        // load up array
        for ($i = 0; $i < $num_fields; $i++) {
            $simple_q[mysql_field_name($db_rs, $i)] = $row[mysql_field_name($db_rs, $i)];
        // and return
        return $simple_q;
    } else {
        // no rows
        return false;

**Please note that my_sql_link() is just a function I have to open up a my sql connection.**
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