PHP 5.4.33 Released

number_format

(PHP 4, PHP 5)

number_formatFormat a number with grouped thousands

Description

string number_format ( float $number [, int $decimals = 0 ] )
string number_format ( float $number , int $decimals = 0 , string $dec_point = '.' , string $thousands_sep = ',' )

This function accepts either one, two, or four parameters (not three):

If only one parameter is given, number will be formatted without decimals, but with a comma (",") between every group of thousands.

If two parameters are given, number will be formatted with decimals decimals with a dot (".") in front, and a comma (",") between every group of thousands.

If all four parameters are given, number will be formatted with decimals decimals, dec_point instead of a dot (".") before the decimals and thousands_sep instead of a comma (",") between every group of thousands.

Return Values

A formatted version of number.

Parameters

number

The number being formatted.

decimals

Sets the number of decimal points.

dec_point

Sets the separator for the decimal point.

This function only takes the first byte for the separator. This means that multibyte characters will NOT work, resulting in a broken multibyte sequence.

thousands_sep

Sets the thousands separator.

Only the first byte of thousands_sep is used. For example, if you use & as thousands_sep on the number 1000, number_format() will return 1&000.

As noted above in the description of the dec_point parameter, then this function is not multibyte aware so using multibyte characters as separators will result in broken sequences.

Examples

Example #1 number_format() Example

For instance, French notation usually use two decimals, comma (',') as decimal separator, and space (' ') as thousand separator. This is achieved with this line :

<?php

$number 
1234.56;

// english notation (default)
$english_format_number number_format($number);
// 1,235

// French notation
$nombre_format_francais number_format($number2','' ');
// 1 234,56

$number 1234.5678;

// english notation without thousands seperator
$english_format_number number_format($number2'.''');
// 1234.57

?>

See Also

add a note add a note

User Contributed Notes 59 notes

up
3
mobi dot lenoe at gmail dot com
10 months ago
I'd like to comment to the old notes of "stm555" and "woodynadobhar".
They wrote about "number_format_unlimited_precision()".
I guess many of us need that kind of function, which is the almost same function as number_format but don't round a number.

Does Anyone know any new solution in a recent PHP version?

...
If no, how about the following function? (I fixed somethings like bugs of the function in the old comment.)
<?php
function number_format_unchanged_precision($number, $dec_point='.', $thousands_sep=','){
    if(
$dec_point==$thousands_sep){
       
trigger_error('2 parameters for ' . __METHOD__ . '() have the same value, that is "' . $dec_point . '" for $dec_point and $thousands_sep', E_USER_WARNING);
       
// It corresponds "PHP Warning:  Wrong parameter count for number_format()", which occurs when you use $dec_point without $thousands_sep to number_format().
   
}
    if(
preg_match('{\.\d+}', $number, $matches)===1){
       
$decimals = strlen($matches[0]) - 1;
    }else{
       
$decimals = 0;
    }
    return
number_format($number, $decimals, $dec_point, $thousands_sep);
}
var_dump(number_format_unchanged_precision(1234.5678, ',', '.'));
var_dump(number_format_unchanged_precision(1234.5678, ','));
var_dump(number_format_unchanged_precision(12345678));
var_dump(number_format_unchanged_precision(-0.5678, ',', '.'));  // It occurred a bug with the function in the old comment.
?>
output is:
    string(10) "1.234,5678"
    PHP Warning:  2 parameters for number_format_unchanged_precision() have the same value, that is "," for $dec_point and $thousands_sep in...
    string(10) "1,234,5678"
    string(10) "12,345,678"
    string(7) "-0,5678"
up
16
james at bandit dot co.nz
5 years ago
Outputs a human readable number.

<?php
   
#    Output easy-to-read numbers
    #    by james at bandit.co.nz
   
function bd_nice_number($n) {
       
// first strip any formatting;
       
$n = (0+str_replace(",","",$n));
       
       
// is this a number?
       
if(!is_numeric($n)) return false;
       
       
// now filter it;
       
if($n>1000000000000) return round(($n/1000000000000),1).' trillion';
        else if(
$n>1000000000) return round(($n/1000000000),1).' billion';
        else if(
$n>1000000) return round(($n/1000000),1).' million';
        else if(
$n>1000) return round(($n/1000),1).' thousand';
       
        return
number_format($n);
    }
?>

Outputs:

247,704,360 -> 247.7 million
866,965,260,000 -> 867 billion
up
4
me dot nosp at m dot unreal4u dot com
4 years ago
Maybe it is documented, but I just missed it. However, a comment is always useful.

An array will always be converted into 1, so, if you have:

<?php
$my_array
= array(55);
echo
number_format($my_array,0,',','.');
// 1
var_dump(number_format($my_array,2,',','.'));
// string(4) "1,00"
?>

Since it took me a while to figure it out, I hope this will save somebody's time.

Greetings !!
up
7
liviu andrei (bls)
2 years ago
To prevent the rounding that occurs when next digit after last significant decimal is 5 (mentioned by several people below):

<?php
function fnumber_format($number, $decimals='', $sep1='', $sep2='') {

        if ((
$number * pow(10 , $decimals + 1) % 10 ) == 5//if next not significant digit is 5
           
$number -= pow(10 , -($decimals+1));

        return
number_format($number, $decimals, $sep1, $sep2);

}

$t=7.15;
echo
$t . " | " . number_format($t, 1, '.', ',') .  " | " . fnumber_format($t, 1, '.', ',') . "\n\n";
//result is: 7.15 | 7.2 | 7.1

$t=7.3215;
echo
$t . " | " . number_format($t, 3, '.', ',') .  " | " . fnumber_format($t, 3, '.', ',') . "\n\n";
//result is: 7.3215 | 7.322 | 7.321
} ?>

have fun!
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2
rlerne at gmail dot com
1 year ago
I came into a need to show two decimal places, but the desire to drop the decimal portion off if it is zero. This function is a direct replacement for number_format:

<?PHP
function number_format_clean($number,$precision=0,$dec_point='.',$thousands_sep=',')
    {
    RETURN
trim(number_format($number,$precision,$dec_point,$thousands_sep),'0'.$dec_point);
    }
?>

Example:

<?PHP
echo number_format_clean(25.00,2);
echo
number_format_clean(25.52,2);
echo
number_format_clean(50.10,2);
echo
number_format_clean(05.50,2);
?>

Outputs:
25
25.52
50.1
5.5

Good for weight conversions (1 oz vs. 1.00 oz). Feels less "automated."

The above will trim all insignificant zeros from both ends of the string, though I'm not sure I've ever seen leading zeros returned.
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2
ted at qtis dot co dot nz
7 years ago
I use the following to get around the negative zero problem:

<?php
function currency_format($amount, $precision = 2, $use_commas = true, $show_currency_symbol = false, $parentheses_for_negative_amounts = false)
{
   
/*
    **    An improvement to number_format.  Mainly to get rid of the annoying behaviour of negative zero amounts.   
    */
   
$amount = (float) $amount;
   
// Get rid of negative zero
   
$zero = round(0, $precision);
    if (
round($amount, $precision) == $zero) {
       
$amount = $zero;
    }
   
    if (
$use_commas) {
        if (
$parentheses_for_negative_amounts && ($amount < 0)) {
           
$amount = '('.number_format(abs($amount), $precision).')';
        }
        else {
           
$amount = number_format($amount, $precision);
        }
    }
    else {
        if (
$parentheses_for_negative_amounts && ($amount < 0)) {
           
$amount = '('.round(abs($amount), $precision).')';
        }
        else {
           
$amount = round($amount, $precision);
        }
    }
   
    if (
$show_currency_symbol) {
       
$amount = '$'.$amount// Change this to use the organization's country's symbol in the future
   
}
    return
$amount;
}
?>
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2
MarcM
8 years ago
For Zero fill - just use the sprintf() function

$pr_id = 1;
$pr_id = sprintf("%03d", $pr_id);
echo $pr_id;

//outputs 001
-----------------

$pr_id = 10;
$pr_id = sprintf("%03d", $pr_id);
echo $pr_id;

//outputs 010
-----------------

You can change %03d to %04d, etc.
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3
Theo Diem
11 years ago
formatting numbers may be more easy if u use number_format function.

I also wrote this :
function something($number)
{
    $locale = localeconv();
    return number_format($number,
       $locale['frac_digits'],
        $locale['decimal_point'],
        $locale['thousands_sep']);
}

hope this helps =)
[]'s
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3
Svein Tjonndal (sveint at yahoo dot com)
10 years ago
If you use space as a separator, it will break on that space in HTML tables...

Furthermore, number_format doesn't like '&nbsp;' as a fourth parameter. I wrote the following function to display the numbers in an HTML table.

  function numberfix($number)
  {
    $number = number_format($number,0,","," ");
    return str_replace(" ", "&nbsp;", $number);
  }

For use in:
<table><tr><td><?php echo $number; ?></td></tr></table>
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1
isedc at yahoo dot com
4 years ago
Some programmers may have scripts that use the number_format function twice on a variable.  However, if a number is 4 or more digits, using the function twice with only the decimals parameter will lose part of the value that follows the thousands separator.

<?php
$var
= number_format(2234,2);
$var = number_format($var,2);
echo
$var;
# Expected Output: 2,234.00
# Actual Output: 2.00
?>

To fix, remove the thousands separator by setting the decimal point and thousands separator parameters like so:

<?php
$var
= number_format(2234,2,'.','');
$var = number_format($var,2,'.','');
echo
$var;
# Expected Output: 2234.00
# Actual Output: 2234.00
?>

If it's 3 digits or less, then it works normally with only the decimals parameter since there is no thousands separator.

<?php
$var
= number_format(123,2);
$var = number_format($var,2);
echo
$var;
# Expected Output: 123.00
# Actual Output: 123.00
?>
up
1
mikesabatino at gmail dot com
8 years ago
<?php
# Function to represent a number like '2nd', '10th', '101st' etc
function text_number($n)
{
   
# Array holding the teen numbers. If the last 2 numbers of $n are in this array, then we'll add 'th' to the end of $n
   
$teen_array = array(11, 12, 13, 14, 15, 16, 17, 18, 19);
   
   
# Array holding all the single digit numbers. If the last number of $n, or if $n itself, is a key in this array, then we'll add that key's value to the end of $n
   
$single_array = array(1 => 'st', 2 => 'nd', 3 => 'rd', 4 => 'th', 5 => 'th', 6 => 'th', 7 => 'th', 8 => 'th', 9 => 'th', 0 => 'th');
   
   
# Store the last 2 digits of $n in order to check if it's a teen number.
   
$if_teen = substr($n, -2, 2);
   
   
# Store the last digit of $n in order to check if it's a teen number. If $n is a single digit, $single will simply equal $n.
   
$single = substr($n, -1, 1);
   
   
# If $if_teen is in array $teen_array, store $n with 'th' concantenated onto the end of it into $new_n
   
if ( in_array($if_teen, $teen_array) )
    {
       
$new_n = $n . 'th';
    }
   
# $n is not a teen, so concant the appropriate value of it's $single_array key onto the end of $n and save it into $new_n
   
elseif ( $single_array[$single] )
    {
       
$new_n = $n . $single_array[$single];   
    }
   
   
# Return new
   
return $new_n;
}
?>
up
1
keyg at auralplanet dot com
9 years ago
if you want &nbsp; as a separator and use windows charset this piece of code may help:

<?php
$number
=number_format($number,2,'.',chr(0xA0));
?>
up
3
info at daniel-marschall dot de
5 years ago
In my function my_number_format() [shown below] there was a bug.

If a negative number which is smaller than 1 was entered (-0,...), then the result was wrongly positive because +0 is equal to -0 (the content of $tmp[0] which was interpretet as numeric value).

Here is the corrected version:

<?php

function my_number_format($number, $dec_point, $thousands_sep)
{
   
$was_neg = $number < 0; // Because +0 == -0
   
$number = abs($number);

   
$tmp = explode('.', $number);
   
$out = number_format($tmp[0], 0, $dec_point, $thousands_sep);
    if (isset(
$tmp[1])) $out .= $dec_point.$tmp[1];

    if (
$was_neg) $out = "-$out";

    return
$out;
}

?>

Thanks to Federico Cassinelli for the bug report.



[EDIT BY danbrown AT php DOT net: The original note follows.]

Let's say we got the number $inp = 1234.56

By using

<?php
return number_format($inp, 2, ',', '.');
?>

you can get the German format 1.234,56. (Comma as decimal separator and point as thousand separator)

But I have a problem with that: I want to add commas as thousand separators and change the decimal-separator (this could also be done with str_replace), but I do not want to change the amount of fractional digits!

But since the 2nd argument of number_format is necessary to enter the 3rd and 4th argument, this cannot be done with number_format. You have to change the fractional digits with this function.

But I want that 1234.56 changes into 1.234,56 and 1234.567890123456 changes into 1.234,567890123456

So, I created following function, that doesn't change the amount of fractional digits:

<?php
function my_number_format($number, $dec_point, $thousands_sep)
{
 
$tmp = explode('.', $number);
 
$out = number_format($tmp[0], 0, $dec_point, $thousands_sep);
  if (isset(
$tmp[1])) $out .= $dec_point.$tmp[1];

  return
$out;
}
?>
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2
IMSoP
5 years ago
I'm not sure if this is the right place anyway, but "ben at last dot fm"'s ordinal function can be simplified further by removing the redundant "floor" (the result of floor is still a float, it's the "%" that's converting to int) and outer switch.

Note that this version also returns the number with the suffix on the end, not just the suffix.

<?php
function ordinal($num)
{
   
// Special case "teenth"
   
if ( ($num / 10) % 10 != 1 )
    {
       
// Handle 1st, 2nd, 3rd
       
switch( $num % 10 )
        {
            case
1: return $num . 'st';
            case
2: return $num . 'nd';
            case
3: return $num . 'rd'
        }
    }
   
// Everything else is "nth"
   
return $num . 'th';
}
?>
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3
sgj at dr dot com
11 years ago
Just an observation:
The number_format rounds the value of the variable.

$val1 = 1.233;
$val2 = 1.235;
$val3 = 1.237;

echo number_format($val1,2,",","."); // returns: 1,23
echo number_format($val2,2,",","."); // returns: 1,24
echo number_format($val3,2,",","."); // returns: 1,24
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1
robmann at gmx dot li
3 years ago
Here a function to filter exponential notation like 6e-06. Turn it to 0,000006 for comfortable reading. Supporting various number of decimals!

<?php
function easy_number_format($number, $dec_point, $thousands_sep)
{
   
$number = rtrim(sprintf('%f', $number), "0");
    if (
fmod($nummer, 1) != 0) {                     
       
$array_int_dec = explode('.', $number);
    } else {
       
$array_int_dec= array(strlen($nummer), 0);
    }
    (
strlen($array_int_dec[1]) < 2) ? ($decimals = 2) : ($decimals = strlen($array_int_dec[1]));
    return
number_format($number, $decimals, $dec_point, $thousands_sep);
}
?>

The maximum accuracy depends on sprintf('%f', $number). In this case 6 decimals. Expand it to 10 with '%.10f'.
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1
uliciadrian01 at yahoo dot com
6 years ago
A simple funtion to format american dollars.

<?php
function formatMoney($money) {
    if(
$money<1) {
       
$money='¢'.$money*100;
    }
    else {
       
$dollars=intval($money);
       
$cents=$money-$dollars;
       
$cents=$cents*100;
       
$money='$'.$dollars.' and ¢'.$cents;
    }
    return
$money;
}
echo
formatmoney('52.342');
?>
This will output: "   $52 and ¢34.2  ".
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1
woodynadobhar at hotmail dot com
9 years ago
What do you do if some of your numbers have decimal places, and some don't?  You can switch between functions, but if you're building it in a loop, that's not a good solution.  Instead, we have the same as below, with a slight change:

function number_format_unlimited_precision($number,$decimal = '.'){
    $broken_number = explode($decimal,$number);
    if($broken_number[1]==0){
        return number_format($broken_number[0]);
    }else{
        return number_format($broken_number[0]).$decimal.$broken_number[1];
    };
};
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0
Anonymous
8 months ago
One-liner to add filesizes and print a human readable result:

seq 1 500 | php -r '$t=0;while(1){$a=rtrim(fgets(STDIN));if(feof(STDIN))break;$t+=$a+0;} $p=floor(log($t, 1024)); printf("%.0f%s\n", $t/pow(1024,$p),substr("BKMGT",$p,1));'

-- Ren
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1
stm555 at hotmail dot com
9 years ago
I ran across an issue where I wanted to keep the entered precision of a real value, without arbitrarily rounding off what the user had submitted.

I figured it out with a quick explode on the number before formatting. I could then format either side of the decimal.

<?php
     
function number_format_unlimited_precision($number,$decimal = '.')
      {
          
$broken_number = explode($decimal,$number);
           return
number_format($broken_number[0]).$decimal.$broken_number[1];
      }
?>
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1
chandu at chandu dot org
10 years ago
People here in India are more used to counting money in Lakhs & Crores .. so here is the code for formatting the commas with thousands for the first time and then with hundred multiples from there after.

Ex: 1234567  ->  12,34,567

<?php

function makecomma($input)
{
   
// This function is written by some anonymous person - I got it from Google
   
if(strlen($input)<=2)
    { return
$input; }
   
$length=substr($input,0,strlen($input)-2);
   
$formatted_input = makecomma($length).",".substr($input,-2);
    return
$formatted_input;
}

function
formatInIndianStyle($num){
   
// This is my function
   
$pos = strpos((string)$num, ".");
    if (
$pos === false) { $decimalpart="00";}
    else {
$decimalpart= substr($num, $pos+1, 2); $num = substr($num,0,$pos); }

    if(
strlen($num)>3 & strlen($num) <= 12){
               
$last3digits = substr($num, -3 );
               
$numexceptlastdigits = substr($num, 0, -3 );
               
$formatted = makecomma($numexceptlastdigits);
               
$stringtoreturn = $formatted.",".$last3digits.".".$decimalpart ;
    }elseif(
strlen($num)<=3){
               
$stringtoreturn = $num.".".$decimalpart ;
    }elseif(
strlen($num)>12){
               
$stringtoreturn = number_format($num, 2);
    }

    if(
substr($stringtoreturn,0,2)=="-,"){$stringtoreturn = "-".substr($stringtoreturn,2 );}

    return
$stringtoreturn;
}

$num = 1234567;
echo 
formatInIndianStyle($num);

?>
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0
vgurudev at nikshepa dot com
2 years ago
<?php

   
function convertNumberToWordsForIndia($number){
       
//A function to convert numbers into Indian readable words with Cores, Lakhs and Thousands.
       
$words = array(
       
'0'=> '' ,'1'=> 'one' ,'2'=> 'two' ,'3' => 'three','4' => 'four','5' => 'five',
       
'6' => 'six','7' => 'seven','8' => 'eight','9' => 'nine','10' => 'ten',
       
'11' => 'eleven','12' => 'twelve','13' => 'thirteen','14' => 'fouteen','15' => 'fifteen',
       
'16' => 'sixteen','17' => 'seventeen','18' => 'eighteen','19' => 'nineteen','20' => 'twenty',
       
'30' => 'thirty','40' => 'fourty','50' => 'fifty','60' => 'sixty','70' => 'seventy',
       
'80' => 'eighty','90' => 'ninty');
       
       
//First find the length of the number
       
$number_length = strlen($number);
       
//Initialize an empty array
       
$number_array = array(0,0,0,0,0,0,0,0,0);       
       
$received_number_array = array();
       
       
//Store all received numbers into an array
       
for($i=0;$i<$number_length;$i++){    $received_number_array[$i] = substr($number,$i,1);    }

       
//Populate the empty array with the numbers received - most critical operation
       
for($i=9-$number_length,$j=0;$i<9;$i++,$j++){ $number_array[$i] = $received_number_array[$j]; }
       
$number_to_words_string = "";       
       
//Finding out whether it is teen ? and then multiplying by 10, example 17 is seventeen, so if 1 is preceeded with 7 multiply 1 by 10 and add 7 to it.
       
for($i=0,$j=1;$i<9;$i++,$j++){
            if(
$i==0 || $i==2 || $i==4 || $i==7){
                if(
$number_array[$i]=="1"){
                   
$number_array[$j] = 10+$number_array[$j];
                   
$number_array[$i] = 0;
                }       
            }
        }
       
       
$value = "";
        for(
$i=0;$i<9;$i++){
            if(
$i==0 || $i==2 || $i==4 || $i==7){    $value = $number_array[$i]*10; }
            else{
$value = $number_array[$i];    }           
            if(
$value!=0){ $number_to_words_string.= $words["$value"]." "; }
            if(
$i==1 && $value!=0){    $number_to_words_string.= "Crores "; }
            if(
$i==3 && $value!=0){    $number_to_words_string.= "Lakhs ";    }
            if(
$i==5 && $value!=0){    $number_to_words_string.= "Thousand "; }
            if(
$i==6 && $value!=0){    $number_to_words_string.= "Hundred &amp; "; }
        }
        if(
$number_length>9){ $number_to_words_string = "Sorry This does not support more than 99 Crores"; }
        return
ucwords(strtolower("Indian Rupees ".$number_to_words_string)." Only.");
    }

    echo
convertNumberToWordsForIndia("987654321");
   
   
//Output ==> Indian Rupees Ninty Eight Crores Seventy Six Lakhs Fifty Four Thousand Three Hundred & Twenty One Only.
?>
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0
before_i_sleep at hotmail dot co dot uk
2 years ago
As many people state the number_format function will round. Now if you're like me and you don't want stuff to round (and the functions below do not work for you) you can try a little regex:

<?php

function convert_size_human($size){
   
$unit=array('','KB','MB','GB','TB','PB');
   
$byte_size = $size/pow(1024,($i=floor(log($size,1024))));

    if(
is_really_int($byte_size)){
        return
$byte_size.' '.$unit[$i];
    }else{
       
preg_match('/^[0-9]+\.[0-9]{2}/', $byte_size, $matches);
        return
$matches[0].' '.$unit[$i];
    }
}

?>

The regex used when the number is not an int ensures that 3.99887 GB comes out as 3.99 GB instead of 4GB as it does from number_format or the functions below.
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info at swedishboy dot se
3 years ago
There has been some suggestions around on how to keep trailing zeros. Best way is to use the example for currency provided by the php-crew in the sprintf function help section.

That is:
<?php
$money1
= 68.75;
$money2 = 54.35;
$money = $money1 + $money2;

// echo $money will output "123.1";

$formatted = sprintf("%01.2f", $money); // << this does the trick!

// echo $formatted will output "123.10"

?>
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Ali Okan YKSEL
3 years ago
function formats numbers of datetime type,

<?php
$_GET
["zaman"]="1983-8-28 5:5:5";

function
_parseDatetimeToList($datetimeStr) { //datetime format: Y-m-d H-i-s
   
$datetimeArray=explode(" ", $datetimeStr);
   
$dateArray=explode("-",$datetimeArray[0]);
   
$year=str_pad($dateArray[0], 2, "0", STR_PAD_LEFT);
   
$month=str_pad($dateArray[1], 2, "0", STR_PAD_LEFT);
   
$day=str_pad($dateArray[2], 2, "0", STR_PAD_LEFT);
   
$timeArray=explode(":",$datetimeArray[1]);
   
$hour=str_pad($timeArray[0], 2, "0", STR_PAD_LEFT);
   
$minute=str_pad($timeArray[1], 2, "0", STR_PAD_LEFT);
   
$second=str_pad($timeArray[2], 2, "0", STR_PAD_LEFT);
    return array(
$year, $month, $day, $hour, $minute, $second);
}

list(
$year, $month, $day, $hour, $minute, $second) = _parseDatetimeToList($_GET["zaman"]);  // 1983-1-28 5:5:5
?>
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Ricky *@* Mataka [com]
3 years ago
Hey Guys, dont know if this is the best way but it worked for me as i faced a problem where I had to split any large number > then 10K into into to exact split amounts.. so i wrote this this to do the trick.. hope it helps some one out there!

<?php
function divide22($num)
{
 
$valone = intval($num / 2);
 
$valtwo = $valone;
  if ((
$num % 2) > 0) $valtwo++;
  return array(
$valone, $valtwo);
}
function
split2vals($num,$split_amount)

 
$store=array();
 
$times = round(($num/$split_amount));
 
$amount= $num/$times;  
  for(
$i=0;$i<$times;$i++)
  {
    
$store[]=round($amount);
  }
  foreach(
$store as $index=>$value)
  {
    if(
$value>$split_amount)
    {
      
$get_splits=divide22($value);
      
//unset the split
      
unset($store[$index]);
      
$store[]=$get_splits[0];
      
$store[]=$get_splits[1];
    }
  }
 
$sum=array_sum($store);

  if(
$sum > $num){
   
$sub=$sum-$num;
     
$end=end($store);
   
array_pop($store);
   
$store[]=$end-$sub;
  }
  if(
$sum < $num){
   
$store[]=($num-$sum); 
  }
  return
$store;
}

//USAGE

$check_amount=50567.83;
echo
'Input Split = '.$check_amount.'<br><br>';
$store=split2vals($check_amount,10000);
print_r($store);
$sum=array_sum($store);
echo
'<br><br>Should Be Exact ='. $sum;
exit();
?>
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dipu dot ashok dot 17 at gmail dot com
4 years ago
function to convert numbers to words
indian: thousand,lakh,crore
Note: function can only convert nos upto 99 crores

<?php
$words
= array('0'=> '' ,'1'=> 'one' ,'2'=> 'two' ,'3' => 'three','4' => 'four','5' => 'five','6' => 'six','7' => 'seven','8' => 'eight','9' => 'nine','10' => 'ten','11' => 'eleven','12' => 'twelve','13' => 'thirteen','14' => 'fouteen','15' => 'fifteen','16' => 'sixteen','17' => 'seventeen','18' => 'eighteen','19' => 'nineteen','20' => 'twenty','30' => 'thirty','40' => 'fourty','50' => 'fifty','60' => 'sixty','70' => 'seventy','80' => 'eighty','90' => 'ninty','100' => 'hundred &','1000' => 'thousand','100000' => 'lakh','10000000' => 'crore');
function
no_to_words($no)
{    global
$words;
    if(
$no == 0)
        return
' ';
    else {          
$novalue='';$highno=$no;$remainno=0;$value=100;$value1=1000;       
            while(
$no>=100)    {
                if((
$value <= $no) &&($no  < $value1))    {
               
$novalue=$words["$value"];
               
$highno = (int)($no/$value);
               
$remainno = $no % $value;
                break;
                }
               
$value= $value1;
               
$value1 = $value * 100;
            }       
          if(
array_key_exists("$highno",$words))
              return
$words["$highno"]." ".$novalue." ".no_to_words($remainno);
          else {
            
$unit=$highno%10;
            
$ten =(int)($highno/10)*10;            
             return
$words["$ten"]." ".$words["$unit"]." ".$novalue." ".no_to_words($remainno);
           }
    }
}
echo
no_to_words(999978987);

?>
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ben at last dot fm
5 years ago
Writing a function to get English ordinals for numbers is a problem every computer science student will face. Here's my solution - nice, short and simple:

<?php
   
function st($i) {
        switch(
floor($i/10) % 10 ) {
            default:
                switch(
$i % 10 ) {
                    case
1: return 'st';
                    case
2: return 'nd';
                    case
3: return 'rd';  
                }
            case
1:
        }
        return
'th';
    }
?>
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Barbara
5 years ago
I was looking for a SIMPLE way to format currency and account for negative values while not losing the calculation properties of my number.  Here's my function - it's not rocket science, but maybe can help someone along the way.

<?php
function wims_currency($number) {
   if (
$number < 0) {
    
$print_number = "($ " . str_replace('-', '', number_format ($number, 2, ".", ",")) . ")";
    } else {
    
$print_number = "$ " number_format ($number, 2, ".", ",") ;
   }
   return
$print_number;
}
?>
Sample use:

<?php
$pur_po_total
=  ($pur_po_total + $pur_item_total);
$print_pur_po_total = wims_currency($pur_po_total);
?>

Returns (for example)    $ 44,561.00 or, if a negative ($ 407,250.00)

This way, I use my 1st variable for calculations and my 2nd variable for output.  I'm sure there are better ways to do it,  but this got me back on track.
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thomas at weblizards dot de
5 years ago
It's not explicitly documented; number_format also rounds:

<?php
$numbers
= array(0.001, 0.002, 0.003, 0.004, 0.005, 0.006, 0.007, 0.008, 0.009);
foreach (
$numbers as $number)
    print
$number."->".number_format($number, 2, '.', ',')."<br>";
?>

0.001->0.00
0.002->0.00
0.003->0.00
0.004->0.00
0.005->0.01
0.006->0.01
0.007->0.01
0.008->0.01
0.009->0.01
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nospam at nospam dot com
5 years ago
Simple function to show money as only dollars if no cents, but will show 2 decimals if cents exist.

The 'cents' flag can force to never or always show 2 decimals

<?php

// formats money to a whole number or with 2 decimals; includes a dollar sign in front
function formatMoney($number, $cents = 1) { // cents: 0=never, 1=if needed, 2=always
 
if (is_numeric($number)) { // a number
   
if (!$number) { // zero
     
$money = ($cents == 2 ? '0.00' : '0'); // output zero
   
} else { // value
     
if (floor($number) == $number) { // whole number
       
$money = number_format($number, ($cents == 2 ? 2 : 0)); // format
     
} else { // cents
       
$money = number_format(round($number, 2), ($cents == 0 ? 0 : 2)); // format
     
} // integer or decimal
   
} // value
   
return '$'.$money;
  }
// numeric
} // formatMoney

$a = array(1, 1234, 1.5, 1.234, 2.345, 2.001, 2.100, '1.000', '1.2345', '12345', 0, '0.00');

// show cents if needed ($cents=1)
foreach ($a as $b) echo ('<br />'.$b.' = '.formatMoney($b, 1));
1 = $1
1234
= $1,234
1.5
= $1.50
1.234
= $1.23
2.345
= $2.35
2.001
= $2.00
2.1
= $2.10
1.000
= $1
1.2345
= $1.23
12345
= $12,345
0
= $0
0.00
= $0

// never show cents ($cents=0)
foreach ($a as $b) echo ('<br />'.$b.' = '.formatMoney($b, 0));
1 = $1
1234
= $1,234
1.5
= $2
1.234
= $1
2.345
= $2
2.001
= $2
2.1
= $2
1.000
= $1
1.2345
= $1
12345
= $12,345
0
= $0
0.00
= $0

// always show cents ($cents=2)
foreach ($a as $b) echo ('<br />'.$b.' = '.formatMoney($b, 2));
1 = $1.00
1234
= $1,234.00
1.5
= $1.50
1.234
= $1.23
2.345
= $2.35
2.001
= $2.00
2.1
= $2.10
1.000
= $1.00
1.2345
= $1.23
12345
= $12,345.00
0
= $0.00
0.00
= $0.00

?>

Cheers :)

And remember to always contribute custom functions if they might be useful to the rest of us or future versions of the php language.
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samuelpeixoto at gmail dot com
5 years ago
Exemplo: Example:

<?php
$number
= 1234567.896;
echo
'1: '.number_format($number, 2, ',', '').'<br>';
echo
'2: '.number_format($number, 2, '.', '').'<br>';
echo
'3: '.number_format($number, 2, ',', '.').'<br>';
echo
'4: '.number_format($number, 2, '.', ',').'<br>';
echo
'5: '.number_format($number, 2, ',', ' ').'<br>';
echo
'6: '.number_format($number, 2, ',', "'").'<br>';
echo
'7: '.number_format($number, 2, '', '').'<br>';
?>

Resultado: Result:

1: 1234567,90   -> Decimal separado por ,
2: 1234567.90   -> Decimal separado por .
3: 1.234.567,90 -> Moeda Brasil, Alemanha
4: 1,234,567.90 -> Inglês, USA
5: 1 234 567,90 -> França
6: 1'234'567,90 -> Suíça
7: 123456790    -> Sem decimal
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isapoetra at gmail dot com
6 years ago
here is the code to convert number to Indonesian text, this code has limitation as is number_format function. sorry for this.
/*
* Created : Iwan Sapoetra - Jun 13, 2008
* Project : Web
* Package : cgaf
*
*/
function terbilang( $num ,$dec=4){
    $stext = array(
        "Nol",
        "Satu",
        "Dua",
        "Tiga",
        "Empat",
        "Lima",
        "Enam",
        "Tujuh",
        "Delapan",
        "Sembilan",
        "Sepuluh",
        "Sebelas"
    );
    $say  = array(
        "Ribu",
        "Juta",
        "Milyar",
        "Triliun",
        "Biliun", // remember limitation of float
        "--apaan---" ///setelah biliun namanya apa?
    );
    $w = "";

    if ($num <0 ) {
        $w  = "Minus ";
        //make positive
        $num *= -1;
    }

    $snum = number_format($num,$dec,",",".");
    die($snum);
    $strnum =  explode(".",substr($snum,0,strrpos($snum,",")));
    //parse decimalnya
    $koma = substr($snum,strrpos($snum,",")+1);

    $isone = substr($num,0,1)  ==1;
    if (count($strnum)==1) {
        $num = $strnum[0];
        switch (strlen($num)) {
            case 1:
            case 2:
                if (!isset($stext[$strnum[0]])){
                    if($num<19){
                        $w .=$stext[substr($num,1)]." Belas";
                    }else{
                        $w .= $stext[substr($num,0,1)]." Puluh ".
                            (intval(substr($num,1))==0 ? "" : $stext[substr($num,1)]);
                    }
                }else{
                    $w .= $stext[$strnum[0]];
                }
                break;
            case 3:
                $w .=  ($isone ? "Seratus" : terbilang(substr($num,0,1)) .
                    " Ratus").
                    " ".(intval(substr($num,1))==0 ? "" : terbilang(substr($num,1)));
                break;
            case 4:
                $w .=  ($isone ? "Seribu" : terbilang(substr($num,0,1)) .
                    " Ribu").
                    " ".(intval(substr($num,1))==0 ? "" : terbilang(substr($num,1)));
                break;
            default:
                break;
        }
    }else{
        $text = $say[count($strnum)-2];
        $w = ($isone && strlen($strnum[0])==1 && count($strnum) <=3? "Se".strtolower($text) : terbilang($strnum[0]).' '.$text);
        array_shift($strnum);
        $i =count($strnum)-2;
        foreach ($strnum as $k=>$v) {
            if (intval($v)) {
                $w.= ' '.terbilang($v).' '.($i >=0 ? $say[$i] : "");
            }
            $i--;
        }
    }
    $w = trim($w);
    if ($dec = intval($koma)) {
        $w .= " Koma ". terbilang($koma);
    }
    return trim($w);
}
//example
echo terbilang(999999999999)."\n";
/**
* result : Sembilan Ratus Sembilan Puluh Sembilan Milyar Sembilan Ratus Sembilan Puluh Sembilan Juta Sembilan Ratus Sembilan Puluh Sembilan Ribu Sembilan Ratus Sembilan Puluh Sembilan
*/
echo terbilang(9999999999999999);
/**
* todo : fix this bug pleasese
* problem : number_format(9999999999999999) <--- 10.000.000.000.000.000,0000
* Result : Sepuluh Biliun
*/
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gabrielu at gmail dot com
6 years ago
Using the number_format I'm having some unexpected results.  30% of 14.95 (14.95 * .3) = 4.485.  Now 4.485 rounded to two decimal places should give me 4.49.

Example:
<?php
echo number_format(14.95 * .3, 2, '.', '') . "\n";
echo
number_format(4.485, 2, '.', '') . "\n";
?>

Unexpected Results:
4.48
4.49
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www.produkte24.com
6 years ago
I have to verify price data from several formats, eg:
- 12.345,67 (German)
- 12,345.67 (English)
- 12 345,67 (French)
- 12'345,67 (Swiss)

Here is a quick function which helps me out of all this format mess, but please not the I only check for:
- positive values
- max 2 digits on the right side (.12)

function mk_price_to_float($price){
    $price = trim($price);
    if(preg_match("~^([0-9]+|(?:(?:[0-9]{1,3}([.,' ]))+[0-9]{3})+)(([.,])[0-9]{1,2})?$~", $price, $r)){
        if(!empty($r['2'])){
            $pre = preg_replace("~[".$r['2']."]~", "", $r['1']);
        }else{
            $pre = $r['1'];
        }
        if(!empty($r['4'])){
            $post = ".".preg_replace("~[".$r['4']."]~", "", $r['3']);
        }else{
            $post = false;
        }
        $form_price = $pre.$post;
        return $form_price;
    }
    return false;
}

This code is used at http://www.produkte24.com/ and http://www.who-sells-it.com/ and works like a charm.
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eb1024 at gmail dot com
7 years ago
To address the problems number_format has when dealing with big numbers I've created my own Number_Format method, it acts the same way as number_format and takes the same arguments but deals with numbers as strings solving the problems above referred.

(The other methods are available at http://www.alixaxel.com/wordpress/2007/05/19/php-math-library/)

function Number_Format($number, $decimal_precision = 0, $decimals_separator = '.', $thousands_separator = ',')
{
if ($this->Is_Negative($number))
{
    $negative = true;

    $number = str_replace('-', '', $number);
}

$number = explode('.', str_replace(' ', '', $number));

$number[0] = str_split(strrev($number[0]), 3);

$total_segments = count($number[0]);

for ($i = 0; $i < $total_segments; $i++)
{
    $number[0][$i] = strrev($number[0][$i]);
}

$number[0] = implode($thousands_separator, array_reverse($number[0]));

if ($negative === true)
{
    $number[0] = '-' . $number[0];
}

if (!empty($number[1]))
{
    $number[1] = $this->Round($number[1], $decimal_precision);
}

$number = implode($decimals_separator, $number);

return $number;
}

I hope this is useful for someone!
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alx at inbox dot lv
7 years ago
enjoy the PHP!
<?php
function FormatPrice($price) {
   
$price = preg_replace("/[^0-9\.]/", "", str_replace(',','.',$price));
    if (
substr($price,-3,1)=='.') {
       
$sents = '.'.substr($price,-2);
       
$price = substr($price,0,strlen($price)-3);
    } elseif (
substr($price,-2,1)=='.') {
       
$sents = '.'.substr($price,-1);
       
$price = substr($price,0,strlen($price)-2);
    } else {
       
$sents = '.00';
    }
   
$price = preg_replace("/[^0-9]/", "", $price);
    return
number_format($price.$sents,2,'.','');
}
?>
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zulisse at email dot it
7 years ago
simpler function to convert a number in bytes, kilobytes....

<?php

function bytes($a) {
   
$unim = array("B","KB","MB","GB","TB","PB");
   
$c = 0;
    while (
$a>=1024) {
       
$c++;
       
$a = $a/1024;
    }
    return
number_format($a,($c ? 2 : 0),",",".")." ".$unim[$c];
}

?>

you may also add others units over PeraBytes when the hard disks will reach 1024 PB :)
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webmaster at WWW.ELLESSEWEB.NET
7 years ago
This is a simple and useful function to convert a byte number in a KB  or MB:

<?
function filesize_format ($bytes) {
  $bytes=(float)$bytes;
  if ($bytes<1024){
  $numero=number_format($bytes, 0, ',', '.')." Byte";
  return $numero;
  }
  if ($bytes<1048576){
      $numero=number_format($bytes/1024, 2, ',', '.')." KByte";
  return $numero;
  }
  if ($bytes>=1048576){
      $numero=number_format($bytes/1048576, 2, ',', '.')." MByte";
  return $numero;
  }
}
?>
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giovanni dot cappellini at gmail dot com
7 years ago
About the function of j-a-n at gmx dot de: it's useful, but the argument of the function is $number while the logic of the function requires it to be $in.
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j-a-n at gmx dot de
8 years ago
This function formats an decimal number to a String.
But it does'n use an fixed count of decimals but calculates the needed count of decimals.

<?
function formatNumber( $number, $decimals=2, $dec_point=".", $thousands_sep=",") {
    $nachkomma = abs($in - floor($in));
    $strnachkomma = number_format($nachkomma , $decimals, ".", "");

    for ($i = 1; $i <= $decimals; $i++) {
        if (substr($strnachkomma, ($i * -1), 1) != "0") {
            break;
        }
    }
   
    return number_format($in, ($decimals - $i +1), $dec_point, $thousands_sep);
}
?>
Example:

formatNumber( 100.00 );
--> 100
formatNumber( 100.50 );
--> 100.5
formatNumber( 100.1234 );
--> 100.12
formatNumber( 100.12, 4 );
--> 100.12
formatNumber( 100.12345, 4 );
--> 100.1234
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Anonymous
8 years ago
The modification to number_format below does what I actually want it to do, with currency, for example. I want it to show $1.40 and not $1.4 or $1.400 - except in the rare case where I have $1.435 for something, in which case I *don't* want it to round. The ugliness below serves my purpose.

function nof($number,$decimals) {
if (number_format($number,$decimals,'.',',') != $number) {
        return $number;
} else {
        return number_format($number,$decimals,'.',',');
        }
}
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rudie at jouwmoeder dot nl
8 years ago
number_format is pretty fast. It's much slower than calculation though:
<?php

$start
= microtime(true);

echo
"<pre>";
for (
$i=0;$i<100000;$i++)
{
    echo
number_format(microtime(true)-$start,25)."\n";
}
echo
"<hr />Parsetime: ".(microtime(true)-$start);

?>
This takes 1.03 seconds all the time. Without the -$start in the number_format cmd, it takes exactly as long (I ran it about 20 times).
The simple calculation inside number_format takes relatively no time. Defining the number before entering it into number_format also gives no change:
{
    $num = microtime(true)-$start;
    echo number_format($num,25)."\n";
}

Which concludes it takes about .01 sec to do a thousand number_format.
If you'd do the same routine without the number_format, it'd take .75 seconds -> number_format very fast!
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0
Jeroen de Bruijn [NL]
8 years ago
If you want to display a number ending with ,- (like 200,-) when there are no decimal characters and display the decimals when there are decimal characters i use:

function DisplayDouble($value)
  {
  list($whole, $decimals) = split ('[.,]', $value, 2);
  if (intval($decimals) > 0)
    return number_format($value,2,".",",");
  else
    return number_format($value,0,".",",") .",-";
  }
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0
marc dot vanwoerkom at fernuni-hagen dot de
9 years ago
See also the documentation for localeconv, which will provide values for decimal point and thousands separator from the C standard library.

Of course localeconv features many more locale information, like indicating to put the negative sign behind the value for some locale settings which can't be used to customize present number_format.
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0
venimus777 at yahoo dot com
9 years ago
You could use the following regular expression to divide
a number into parts:

$1-number without fractal part
$2-fractal part
$3-first 2 digits of the fractal part
$4-rest of the fractal part

the regex removes any leading and trailing symbols and leading zeros. It doesnt validate the number, so 12 41 is considered to be correct input!

english notation:
/^.*?[0]*([\d\s]+)(([\.][\d]{0,2})([\d]*))?.*?$/

french notation:
/^.*?[0]*([\d\s]+)(([\,][\d]{0,2})([\d]*))?.*?$/

<?php
// truncate the fractal part up to 2 digits of an "english number":
$number = '01,234.50789';
$trunc = preg_replace(
   
'/^.*?[0]*([\d\,]+)(([\.][\d]{0,2})([\d]*))?.*?$/',
   
'$1$3',
   
$number
);
echo
$trunc;
?>

Outputs:
1,234.50

$number='e00012 41.100001e-4fasfd';
would output:
12 41.10
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0
php at mijav dot dk
9 years ago
A bug was issued that -0,00 is invalid output from number_format(), but the bug was rejected since the number "-0.0000000000000000001E-999 is about -0". And the developer felt this was correct output.

Please beware of negative numbers close to zero, as they might produce this unusable (and in my opinion incorrect/off-description) output.
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0
brandonprudent at yahoo dot com
9 years ago
To convert numbers to thier textual representations, you can use an adapted version of the Number::Spell Perl module. The PHP conversion can be found here: http://pear.php.net/package/Numbers_Words
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0
drew at zitnay dot com
10 years ago
A more reliable and concise way of doing what S. Rahmel was trying to do below is as follows:

<?php
$field_inhalt
= str_replace(array(".", ","), array("", "."), $field_inhalt);
?>

The str_replace() call will first replace all dots with blanks, and then replace all commas with dots.  That way, it doesn't break down when you try a number over one million (i.e. 1.010.453,21).

Drew
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0
S. Rahmel
10 years ago
if you converted a number to a German format with number_format() and want to save it in mySQL, you first have to change the number format back to an English format.

For example
10.453,21 >>>> 10453.21

Here is an example how to do this:

    $field_array=explode(".", $field_inhalt);
    $field_inhalt=$field_array[0].$field_array[1];
    $foeld_array=explode(",", $field_inhalt);
    $field_inhalt=$field_array[0].".".$feld_array[1];
    $field_inhalt=sprintf($field_inhalt, 2);

$field_inhalt is the variable of the actual number you want to change to the english format.
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0
cruzf_AT_fibertel.com.ar
10 years ago
You could add padding zeros like this:

<?
$number="129";
$number=sprintf("%08d",$number);
?>
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andrew at crucible dot co dot nz
12 years ago
Remember that number_format returns a string, so you shouldn't run a number_format on a variable that's already a product of number_format (it will only take the first token of the string)...

eg. echo number_format("123,456.00", 2);
produces: 123.00
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-1
tomislav at firmus-grupa dot hr
1 year ago
When apply number_format on number with separator on thousands, result is wrong. This function accept number of any format
<?php
function format_price($number,$decPlaces,$decSep,$thouSep){
       
   
//$number - number for format
    //$decPlaces - number of decimal places
    //$decSep - separator for decimals
    //$thouSep - separator for thousands
   
    //first remove all white spaces
   
$number=preg_replace('/\s+/', '',$number);
   
//split string into array
   
$numberArr = str_split($number);
   
//reverse array and not preserve key, keys will help to find decimal place
   
$numberArrRev=array_reverse($numberArr);
   
   
//find first occurrence of non number character, that will be a decimal place
    //store $key into variable $decPointIsHere
   
foreach ($numberArrRev as $key => $value) {
        if(!
is_numeric($value)){
            if(
$decPointIsHere==""){
               
$decPointIsHere=$key;
            }           
        }
    }
   
   
//decimal comma or whatever it is replace with dot
    //$decPointIsHere is the key of the element that will contain decimal separator dot
   
if($decPointIsHere!=""){
       
$numberArrRev[$decPointIsHere]=".";
    }
   
   
//again check through array for non numerical characters but skipping allready processed keys
    //if is not number remove from array
   
   
foreach ($numberArrRev as $key => $value) {
        if(!
is_numeric($value) && $key>$decPointIsHere){
            unset(
$numberArrRev[$key]);           
        }
    }
   
   
//reverse back, at the start reversed array $numberArrRev to $numberArr
   
$numberArr=array_reverse($numberArrRev);   
   
   
//create string from array
   
$numberClean=implode("",$numberArr);
       
   
// apply php number_format function
   
return number_format($numberClean,$decPlaces,$decSep,$thouSep);
   
}

echo
format_price("1 225 552, 55",2,',',' ')."<br>";
echo
format_price("1.225.552, 55",2,',',' ')."<br>";
echo
format_price("1'225'552. 55",2,',',' ')."<br>";
echo
format_price("1225552.55",2,',',' ')."<br>";
?>
all results are: 1 225 552,55
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-1
sctemplarknight at hotmail dot com
12 years ago
number_format($number,$precision,".","") should be used when setting the value of form elements because if you read the number into a double upon submission, it will only store digits before the comma.
<p>
ie. <input type="text" value="<?php echo(number_format(2.5343,2,".","")">
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-1
Cody G.
4 years ago
Sometimes, I'm sure, you guys are looking for a way to do the exact opposite of this function: convert a comma-filled number back to normal decimal.
Here's a quick code that popped into my head today:

<?php
$mynumstr
= "100,000,000.75";
$mynum = doubleval(str_replace(",","",$mynumstr));
?>

This is especially useful when validating user input. Some people like to include comma's with their numbers.
Some also like to include the dollar-sign when entering prices. Here's a modification:

<?php
$mynumstr
= '$100,000,000.25';
$arr1 = array(',','$');
$arr2 = array('','');
$mynum = doubleval(str_replace($arr1,$arr2,$mynumstr));
//The arrays had to be defined in a
//  variable to shorten statement.
?>

Okay, that takes care of it, I use the PHP4 array compatibility update to remove several characters.
Don't forget to either use single-quotes or escape the dollar-sign!

~Cody G.
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-1
mike at phpeeb dot com
9 years ago
Since number_format returns a string, you must perform all mathmatical functions on the number before applying number_format:

<?
$total = 100;
$total = number_format($total, 2);
$shipping = 20.00;
$grand_total = $total + $shipping;

echo number_format($grand_total, 2);

/* The above will return 21.00 because $total is now a string, and no longer an integer or float. Since a string will have a value of 1,  the addition of the two will return 21 and not 120. */

$total = 100;
$shipping = 20.00;
$grand_total = $total + $shipping;

echo number_format($grand_total, 2);

/* This works, and will return 120.00 as intended */

?>
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-2
Peter de Pijd
5 years ago
If you want to use nbsp as decimal/thousand delimiter with UTF-8 you have to replace the whitespace after using number_format:

<?php
$number
= number_format(1000, 0, ".", " "); // normal space
echo str_replace(" ", utf8_encode("\xA0"), $number);
// or
echo str_replace(" ", html_entity_decode("&nbsp;", ENT_COMPAT, "UTF-8"), $number);
?>
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-3
user at example dot net
7 years ago
The following function converts a string into Float or Integer while taking the given or locale number format into account.

<?php

   
function strtonumber( $str, $dec_point=null, $thousands_sep=null )
    {
        if(
is_null($dec_point) || is_null($thousands_sep) ) {
           
$locale = localeconv();
            if(
is_null($dec_point) ) {
               
$dec_point = $locale['decimal_point'];
            }
            if(
is_null($thousands_sep) ) {
               
$thousands_sep = $locale['thousands_sep'];
            }
        }
       
$number = (float) str_replace($dec_point, '.', str_replace($thousands_sep, '', $str));
        if(
$number == (int) $number ) {
            return (int)
$number;
        } else {
            return
$number;
        }
    }

?>
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-3
GeekPrices Dot Com
9 years ago
this also works as well

$number = "29346.99"; //value
echo "$" .number_format($number, 2, '.', ',');

produces $29,346.99
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