chdir

(PHP 4, PHP 5, PHP 7)

chdir디렉토리 변경

설명

bool chdir ( string $directory )

PHP의 현재 디렉토리를 directory로 변경합니다.

인수

directory

새 현재 디렉토리

반환값

성공 시 TRUE를, 실패 시 FALSE를 반환합니다.

예제

Example #1 chdir() 예제

<?php

// 현재 디렉토리
echo getcwd() . "\n";

chdir('public_html');

// 현재 디렉토리
echo getcwd() . "\n";

?>

위 예제의 출력 예시:

/home/vincent
/home/vincent/public_html

주의

Note: 안전 모드를 활성화했을 경우, PHP는 작업하려는 디렉토리가 실행중인 스크립트와 같은 UID(owner)를 가지고 있는지 확인합니다.

참고

  • getcwd() - 현재 작업 디렉토리를 얻음

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User Contributed Notes 3 notes

up
5
herwin at snt dot utwente dot nl
10 years ago
When using PHP safe mode and trying to change to a dir that is not accessible due to the safe mode restrictions, the function simply fails without generating any kind of error message.

(Tested in PHP 4.3.10-16, Debian Sarge default)
up
0
php dot duke at qik dot nl
7 years ago
When changing dir's under windows environments:

<?php
$path
="c:\temp"';
chdir($path);
/* getcwd() gives you back "c:\temp" */

$path="c:\temp\"'
;
chdir($path);
/* getcwd() gives you back "c:\temp\" */
?>

to work around this inconsistency
doing a chdir('.') after the chdir always gives back "c:\temp"
up
-40
andy dot clark at dial dot pipex dot com
10 years ago
This only changes the directory for PHP, the output directory stays the same. If you are trying to access images from a relative path and you use the following then it will fail to render the image:

chdir ('images');
if (file_exists('php.gif'))
{
echo '<html>';
echo '<body>';
echo '<img src="php.gif">';
echo '</body></html>';
}

//However, it is possible to use the <base> tag in the header to change the directory for the resulting HTML, as you can see however this requires you to put the full path in place.

chdir ('images');
if (file_exists('php.gif'))
{
echo '<html>';
echo '<head><base href = "http://uk.php.net/images/"></head>';
echo '<body>';
echo '<img src="php.gif">';
echo '</body></html>';
}
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