PHP Australia Conference 2015

array_uintersect

(PHP 5)

array_uintersectComputes the intersection of arrays, compares data by a callback function

Opis

array array_uintersect ( array $array1 , array $array2 [, array $ ... ], callable $data_compare_func )

Computes the intersection of arrays, compares data by a callback function.

Parametry

array1

The first array.

array2

The second array.

data_compare_func

The comparison function must return an integer less than, equal to, or greater than zero if the first argument is considered to be respectively less than, equal to, or greater than the second.

int callback ( mixed $a, mixed $b )

Zwracane wartości

Returns an array containing all the values of array1 that are present in all the arguments.

Przykłady

Przykład #1 array_uintersect() example

<?php
$array1 
= array("a" => "green""b" => "brown""c" => "blue""red");
$array2 = array("a" => "GREEN""B" => "brown""yellow""red");

print_r(array_uintersect($array1$array2"strcasecmp"));
?>

Powyższy przykład wyświetli:

Array
(
    [a] => green
    [b] => brown
    [0] => red
)

Zobacz też:

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User Contributed Notes 1 note

up
0
Nate at RuggFamily dot com
7 years ago
I want to stress that in the user function, you do need to return either a 1 or a -1 properly; you cannot simply return 0 if the results are equal and 1 if they are not. 

The following code is incorrect:

<?php
function myfunction($v1,$v2)
{
if (
$v1===$v2)
    {
    return
0;
    }
return
1;
}

$a1=array(1, 2, 4);
$a2=array(1, 3, 4);
print_r(array_uintersect($a1,$a2,"myfunction"));
?>

This code is correct:

<?php
function myfunction($v1,$v2)
{
if (
$v1===$v2)
    {
    return
0;
    }
if (
$v1 > $v2) return 1;
return -
1;
}
$a1=array(1, 2, 4);
$a2=array(1, 3, 4);
print_r(array_uintersect($a1,$a2,"myfunction"));
?>
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