array_uintersect

(PHP 5)

array_uintersectComputes the intersection of arrays, compares data by a callback function

Descrierea

array array_uintersect ( array $array1 , array $array2 [, array $... ], callable $value_compare_func )

Computes the intersection of arrays, compares data by a callback function.

Parametri

array1

The first array.

array2

The second array.

value_compare_func

Funcția de comparare trebuie să întoarcă un întreg mai mic, egal cu sau mai mare decât zero dacă primul argument este considerat respectiv mai mic, egal cu sau mai mare decât al doilea argument.

int callback ( mixed $a, mixed $b )

Valorile întoarse

Returns an array containing all the values of array1 that are present in all the arguments.

Exemple

Example #1 array_uintersect() example

<?php
$array1 
= array("a" => "green""b" => "brown""c" => "blue""red");
$array2 = array("a" => "GREEN""B" => "brown""yellow""red");

print_r(array_uintersect($array1$array2"strcasecmp"));
?>

Exemplul de mai sus va afișa:

Array
(
    [a] => green
    [b] => brown
    [0] => red
)

Vedeți de asemenea

add a note add a note

User Contributed Notes 1 note

up
0
Nate at RuggFamily dot com
7 years ago
I want to stress that in the user function, you do need to return either a 1 or a -1 properly; you cannot simply return 0 if the results are equal and 1 if they are not. 

The following code is incorrect:

<?php
function myfunction($v1,$v2)
{
if (
$v1===$v2)
    {
    return
0;
    }
return
1;
}

$a1=array(1, 2, 4);
$a2=array(1, 3, 4);
print_r(array_uintersect($a1,$a2,"myfunction"));
?>

This code is correct:

<?php
function myfunction($v1,$v2)
{
if (
$v1===$v2)
    {
    return
0;
    }
if (
$v1 > $v2) return 1;
return -
1;
}
$a1=array(1, 2, 4);
$a2=array(1, 3, 4);
print_r(array_uintersect($a1,$a2,"myfunction"));
?>
To Top