microtime
It seems mktime() doesn't return negative timestamps on Linux systems with a version of glibc <= 2.3.3.
mktime
(PHP 4, PHP 5)
mktime — Obține timestamp-ul Unix pentru o dată și oră
Descrierea
int mktime
([ int
$hour = date("H")
[, int $minute = date("i")
[, int $second = date("s")
[, int $month = date("n")
[, int $day = date("j")
[, int $year = date("Y")
[, int $is_dst = -1
]]]]]]] )Întoarce timestamp-ul Unix ce corespunde argumentelor furnizate. Acest timestamp este un integer lung conținând numărul de secunde între Epoca Unix (1 Ianuarie 1970 00:00:00 GMT) și timpul specificat.
Argumentele pot fi omise unul după altul de la dreapta spre atânga; orice argument omis va fi stabilit la valoarea curentă în corespundere cu data și ora locale.
Note
Notă:
Începând cu PHP 5.1, când este apelat fără argumente, mktime() aruncă o notificare
E_STRICT: utilizați funcția time() în loc.
Parametri
-
hour -
Numărul orei relativ cu începutul zilei determinat de
month,dayșiyear. Valorile negative se referă la ora înainte de miezul nopții a zilei în cauză. Valorile mai mari decât 23 se referă la ora corespunzătoare a zilei (zilelor) următoare. -
minute -
Numărul minutului relativ cu începutul orei determinat de
hour. Valorile negative se referă la minutul orei precedente. Valorile mai mari decât 59 se referă la minutul corespunzător a orei (orelor) următoare. -
second -
Numărul de secunde relativ cu începutul minutului determinat de
minute. Valorile negative se referă la secunda minutului precedent. Valorile mai mari decât 59 se referă la secunda corespunzătoare ale minutului (minutelor) următoare. -
month -
Numărul lunii relativ cu sfârșitul anului precedent. Valorile de la 1 până la 12 se referă la lunile normale ale anului în cauză. Valorile mai mici decât 1 (inclusiv valorile negative) se referă la lunile anului precedent în ordine inversă, deci 0 este Decembrie, -1 este Noiembrie, etc. Valorile mai mari decât 12 se referă la luna corespunzătoare a anului (anilor) următor.
-
day -
Numărul zilei relativ cu sfârșitul lunii precedente. Valorile de la 1 până la 28, 29, 30 sau 31 (în dependență de lună) se referă la zilele normale ale lunii în cauză. Valorile mai mici decât 1 (inclusiv valorile negative) se referă la zilele lunii precedente, deci 0 este ultima zi a lunii precedente, -1 este penultima zi, etc. Valorile mai mari decât numărul de zile din luna respectivă se referă la ziua corespunzătoare din luna (lunile) următoare.
-
year -
Numărul anului. Poate fi format din două sau din patru cifre. Valorile 0-69 corespund anilor 2000-2069, iar 70-100 corespund 1970-2000. Pe sistemele unde time_t este un întreg pe 32 biți cu semn, cum este pe majoritatea sistemelor contemporane, domeniul valid pentru
yeareste între 1901 și 2038. Însă înainte de PHP 5.1.0 acest domeniu era limitat între 1970 și 2038 pe unele sisteme (de ex. Windows). -
is_dst -
Acest parametru poate fi stabilit în 1 dacă este în efect timpul de vară (daylight savings time (DST)), 0 dacă nu, sau -1 (valoarea implicită) dacă nu se cunoaște dacă este în efect timpul de vară. Dacă nu se cunoaște, PHP încearcă singur să determine acest lucru. Aceasta poate cauza rezultate neașteptate (dar nu neapărat incorecte). Unele ore nu sunt valide dacă DST este activat pe sistemul unde rulează PHP, sau dacă parametrul
is_dsteste stabilit în 1. Dacă DST este activat de ex. la 2:00, toate orele între 2:00 și 3:00 sunt invalide și mktime() întoarce o valoare nedefinită (de obicei negativă). Unele sisteme (de ex. Solaris 8) activează DST la miezul nopții, de aceea ora 0:30 în ziua când DST este activat este evaluată ca 23:30 a zilei precedente.Notă:
Începând cu PHP 5.1.0, acest parametru a devenit dezaprobat. În rezultat noile facilități de gestiune a fusului orar trebuie utilizate în loc.
Valorile întoarse
mktime() întoarce timestamp-ul Unix al argumentelor
furnizate. Dacă argumentele nu sunt valide, funcția întoarce FALSE (înainte
de PHP 5.1 întorcea -1).
Erori/Excepții
Fiecare apel al unei funcții de dată/oră va genera o E_NOTICE
dacă zona orară nu este validă și/sau un mesaj E_STRICT
sau E_WARNING dacă se utilizează setările
sistemului sau variabila de mediu TZ. Vedeți de asemenea
date_default_timezone_set()
Istoria schimbărilor
| Versiunea | Descriere |
|---|---|
| 5.3.0 |
mktime() acum emite o notificare
E_DEPRECATED dacă este utilizat parametrul
is_dst.
|
| 5.1.0 |
Parametrul is_dst a devenit dezapreciat.
Funcția a fost modificată să întoarcă FALSE în caz de eroare, în loc
de -1. Funcția a fost modificată să accepte anul,
luna și ziua cu valorile zero.
|
| 5.1.0 |
Când este apelată fără argumente, mktime() aruncă o
notificare E_STRICT. Utilizați funcția
time() în loc.
|
| 5.1.0 | Acum generează erori ale zonei orare de tip
|
Exemple
Example #1 Exemplu simplu mktime()
<?php
// Stabilește fusul orar implicit pentru a fi utilizat. Disponibil începând cu PHP 5.1
date_default_timezone_set('UTC');
// Afișează: July 1, 2000 is on a Saturday
echo "July 1, 2000 is on a " . date("l", mktime(0, 0, 0, 7, 1, 2000));
// Afișează ceva de felul: 2006-04-05T01:02:03+00:00
echo date('c', mktime(1, 2, 3, 4, 5, 2006));
?>
Example #2 Exemple mktime()
mktime() este utilă pentru a face operații aritmetice și de validare a datelor, deoarece ea va calcula automat valoarea corectă pentru vlorile introduse din afara domeniului. De exemplu, fiecare rând ce urmează produce string-ul "Jan-01-1998".
<?php
echo date("M-d-Y", mktime(0, 0, 0, 12, 32, 1997));
echo date("M-d-Y", mktime(0, 0, 0, 13, 1, 1997));
echo date("M-d-Y", mktime(0, 0, 0, 1, 1, 1998));
echo date("M-d-Y", mktime(0, 0, 0, 1, 1, 98));
?>
Example #3 Ultima zi a lunii
Ultima zi a oricărei luni poate fi exprimată ca ziua "0" a lunii următoare, dar nu ziua -1. Ambele exemple ce urmează vor produce string-ul "Ultima zi din Februarie 2000 este: 29".
<?php
$lastday = mktime(0, 0, 0, 3, 0, 2000);
echo strftime("Ultima zi din Februarie 2000 este: %d", $lastday);
$lastday = mktime(0, 0, 0, 4, -31, 2000);
echo strftime("Ultima zi din Februarie 2000 este: %d", $lastday);
?>
Note
Precauţie
Înainte de PHP 5.1.0, timestamp-urile negative nu erau susținute în unele sisteme, inclusiv nici într-o versiune cunoscută Windows. De aceea domeniul valid al anilor era limitat între 1970 și 2038.
Vedeți de asemenea
- checkdate() - Validează o dată Gregoriană
- gmmktime() - Obține momentul de timp Unix pentru o dată GMT
- date() - Formatează o oră/dată
- time() - Întoarce timpul curent Unix
add a note
User Contributed Notes
mktime - [35 notes]
thomas_corthals at hotmail dot com ¶
5 years ago
rlz ¶
5 years ago
Finding out the number of days in a given month and year, accounting for leap years when February has more than 28 days.
<?php
function days_in_month($year, $month) {
return( date( "t", mktime( 0, 0, 0, $month, 1, $year) ) );
}
?>
Hope it helps a soul out there.
info at microweb dot lt ¶
2 years ago
Function to generate array of dates between two dates (date range array)
<?php
function dates_range($date1, $date2)
{
if ($date1<$date2)
{
$dates_range[]=$date1;
$date1=strtotime($date1);
$date2=strtotime($date2);
while ($date1!=$date2)
{
$date1=mktime(0, 0, 0, date("m", $date1), date("d", $date1)+1, date("Y", $date1));
$dates_range[]=date('Y-m-d', $date1);
}
}
return $dates_range;
}
echo '<pre>';
print_r(dates_range('2009-12-25', '2010-01-05'));
echo '</pre>';
?>
[EDIT BY danbrown AT php DOT net: Contains a bugfix submitted by (carlosbuz2 AT gmail DOT com) on 04-MAR-2011, with the following note: The first date in array is incorrect.]
ronnie dot kurniawan at gmail dot com ¶
4 years ago
Add (and subtract) unixtime:
<?php
function utime_add($unixtime, $hr=0, $min=0, $sec=0, $mon=0, $day=0, $yr=0) {
$dt = localtime($unixtime, true);
$unixnewtime = mktime(
$dt['tm_hour']+$hr, $dt['tm_min']+$min, $dt['tm_sec']+$sec,
$dt['tm_mon']+1+$mon, $dt['tm_mday']+$day, $dt['tm_year']+1900+$yr);
return $unixnewtime;
}
?>
joseph dot andrew dot hughes at gmail dot com ¶
5 years ago
Just a small thing to think about if you are only trying to pull the month out using mktime and date. Make sure you place a 1 into day field. Otherwise you will get incorrect dates when a month is followed by a month with less days when the day of the current month is higher then the max day of the month you are trying to find.. (Such as today being Jan 30th and trying to find the month Feb.)
PHPcoder at freemail dot ig3 dot net ¶
5 years ago
The maximum possible date accepted by mktime() and gmmktime() is dependent on the current location time zone.
For example, the 32-bit timestamp overflow occurs at 2038-01-19T03:14:08+0000Z. But if you're in a UTC -0500 time zone (such as EST in North America), the maximum accepted time before overflow (for older PHP versions on Windows) is 2038-01-18T22:14:07-0500Z, regardless of whether you're passing it to mktime() or gmmktime().
tom at chegg dot com ¶
2 years ago
I was using the following to get a list of month names.
for ($i=1; $i<13; $i++) {
echo date('F', mktime(0,0,0,$i) . ",";
}
Normally this outputs -
January,February,March,April,May,June,July,August,
September,October,November,December
However if today's date is the 31st you get instead:
January,March,March,May,May,July,July,August,October,
October,December,December
Why? Because Feb,Apr,June,Sept, and Nov don't have 31 days!
The fix, add the 5th parameter, don't let the day of month default to today's date:
echo date('F', mktime(0,0,0,$i,1) . ",";
Jacob Santos ¶
7 months ago
Please note that incrementing a date using mktime in a loop is not proper. You could do it, except that there is a far better method found in the DateTime PHP class. Look at the documentation for DateTime::modify, DateTime::add (when supported) and DateTime::sub (when supported).
Also, adding seconds to a time is, well it isn't as easy as it seems, "Hey I'll just add 3600 seconds or 86400 seconds or x seconds!". The phrase once bitten, twice shy is quite applicable with the usage of adding seconds. If you ever had to 'fix' a time by calculating midnight to add the correct number of seconds, then you are doing it wrong.
Luckily, knowing is not a requirement, because DateTime and friends exists, removing the complexity for you.
So if given a choice of
mktime($seconds, $minutes, $hours+1);
and
$datetime->modify('+1 hour');
or
$datetime->add('P1H');
I'll go with the second choice, but probably not the third, unless I was using DateInterval::createFromDateString, so that other developers knew my intent.
Stephen ¶
6 years ago
There are several warnings here about using mktime() to determine a date difference because of daylight savings time. However, nobody seems to have mentioned the other obvious problem, which is leap years.
Leap years mean that any effort to use mktime() and time() to determine the age (positive or negative) of some timestamp in years will be flawed. There are some years that are 366 days long, therefore you cannot say that there is a set number of seconds per year.
Timestamps are good for determining *real* time, which is not the same thing as *human calendar* time. The Gregorian calendar is only an approximation of real time, which is tweaked with daylight savings time and leap years to make it conform more to humans' expectations of how time should or ought to work. Timestamps are not tweaked and therefore are the only authoritative way of recording in computers a proper order of succession of events, but they cannot be integrated with a Gregorian system unless you take both leap years and DST into account. Otherwise, you may get the wrong number of years when you are approaching a value of exactly X years.
As for PHP, you could still use timestamps as a way of determining age if you took into account not only DST but also whether or not each year is a leap year and adjusted your calculations accordingly. However, this could become messy and inefficient.
There is an alternative approach to calculating days given the day, month and year of the dates to be compared. Compare the years first, and then compare the month and day - if the month and day have already passed (or, if you like, if they match the current month and day), then add 1 to the total for the years.
This solution works because it stays within the Gregorian system and doesn't venture into the world of timestamps.
There is also the issue of leap seconds, but this will only arise if you literally need to get the *exact* age in seconds. In that case, of course, you would also need to verify that your timestamps are exactly correct and are not delayed by script processing time, plus you would need to determine whether your system conforms to UTC, etc. I expect this will hardly be an issue for anybody using PHP, however if you are interested there is an article on this issue on Wikipedia:
http://en.wikipedia.org/wiki/Leap_second
ionut dot bodea at eydos dot ro ¶
4 years ago
Here is what I use to calculate age. It took me 30 minutes to write and it's quite accurate. What it has special is that it's calculating the number of days a year has (float number), by testing if a year is a leap one or not. This number is used to compute the age.
<?php
function get_age($date_start, $date_end) {
$t_lived = get_timestamp($date_end) - get_timestamp($date_start);
$seconds_one_year = get_days_per_year($date_start, $date_end) * 24 * 60 * 60;
$age = array();
$age['years_exact'] = $t_lived / $seconds_one_year;
$age['years'] = floor($t_lived / $seconds_one_year);
$seconds_remaining = $t_lived % $seconds_one_year;
$age['days'] = round($seconds_remaining / (24 * 60 * 60));
return $age;
}
function get_timestamp($date) {
list($y, $m, $d) = explode('-', $date);
return mktime(0, 0, 0, $m, $d, $y);
}
function get_days_per_year($date_start, $date_end) {
list($y1) = explode('-', $date_start);
list($y2) = explode('-', $date_end);
$years_days = array();
for($y = $y1; $y <= $y2; $y++) {
$years_days[] = date('L', mktime(0, 0, 0, 1, 1, $y)) ? 366 : 365;
}
return round(array_sum($years_days) / count($years_days), 2);
}
$date_birth = '1979-10-12';
$date_now = date('Y-m-d');
$age = get_age($date_birth, $date_now);
echo '<pre>';
print_r($age);
echo '</pre>';
?>
It will display something like this:
Array
(
[years_exact] => 28.972974329491
[years] => 28
[days] => 355
)
ooogla at hotmail dot com ¶
4 years ago
If you want to increment the day based on a variable when using a loop you can use this when you submit a form
1. Establish a start date and end date in two different variables
2. Get the number of days between a date
$ndays = (strtotime($_POST['edate']) - strtotime($_POST['sdate'])) / (60 * 60 * 24);
Then here is the string you slip in your loop
$nextday = date('Y-m-d', mktime(0, 0, 0, date("m", strtotime($_POST['sdate'])) , date("d", strtotime($_POST['sdate']))+ $count, date("Y", strtotime($_POST['sdate']))));
$count is incremented by the loop.
rga at merchantpal dot com ¶
6 years ago
You cannot simply subtract or add month VARs using mktime to obtain previous or next months as suggested in previous user comments (at least not with a DD > 28 anyway).
If the date is 03-31-2007, the following yeilds March as a previous month. Not what you wanted.
<?php
$dateMinusOneMonth = mktime(0, 0, 0, (3-1), 31, 2007 );
$lastmonth = date("n | F", $dateMinusOneMonth);
echo $lastmonth; //---> 3 | March
?>
mktime correctly gives you back the 3rd of March if you subtract 1 month from March 31 (there are only 28 days in Feb 07).
If you are just looking to do month and year arithmetic using mktime, you can use general days like 1 or 28 to do stuff like this:
<?php
$d_daysinmonth = date('t', mktime(0,0,0,$myMonth,1,$myYear)); // how many days in month
$d_year = date('Y', mktime(0,0,0,$myMonth,1,$myYear)); // year
$d_isleapyear = date('L', mktime(0,0,0,$myMonth,1,$myYear)); // is YYYY a leapyear?
$d_firstdow = date('w', mktime(0,0,0,$myMonth,'1',$myYear)); // FIRST falls on what day of week (0-6)
$d_firstname = date('l', mktime(0,0,0,$myMonth,'1',$myYear)); // FIRST falls on what day of week Full Name
$d_month = date('n', mktime(0,0,0,$myMonth,28,$myYear)); // month of year (1-12)
$d_monthname = date('F', mktime(0,0,0,$myMonth,28,$myYear)); // Month Long name (July)
$d_month_previous = date('n', mktime(0,0,0,($myMonth-1),28,$myYear)); // PREVIOUS month of year (1-12)
$d_monthname_previous = date('F', mktime(0,0,0,($myMonth-1),28,$myYear)); // PREVIOUS Month Long name (July)
$d_month_next = date('n', mktime(0,0,0,($myMonth+1),28,$myYear)); // NEXT month of year (1-12)
$d_monthname_next = date('F', mktime(0,0,0,($myMonth+1),28,$myYear)); // NEXT Month Long name (July)
$d_year_previous = date('Y', mktime(0,0,0,$myMonth,28,($myYear-1))); // PREVIOUS year
$d_year_next = date('Y', mktime(0,0,0,$myMonth,28,($myYear+1))); // NEXT year
$d_weeksleft = (52 - $d_weekofyear); // how many weeks left in year
$d_daysinyear = $d_isleapyear ? 366 : 365; // set correct days in year for leap years
$d_daysleft = ($d_daysinyear - $d_dayofyear); // how many days left in year
?>
zfowler at unomaha dot edu ¶
3 years ago
Proper way to convert Excel dates into PHP-friendly timestamps using mktime():
<?php
// The date 6/30/2009 is stored as 39994 in Excel
$days = 39994;
// But you must subtract 1 to get the correct timestamp
$ts = mktime(0,0,0,1,$days-1,1900);
// So, this would then match Excel's representation:
echo date("m/d/Y",$ts);
?>
Excel uses "number of days since Jan. 1, 1900" to store its dates. It also treats 1900 as a leap year when it wasn't, thus there is an extra day which must be accounted for in PHP (and the rest of the world). Subtracting 1 from Excel's number will fix this problem.
contact at phpmember dot com ¶
3 years ago
How many days have passed since the beginning of the year.... regardless of what year it is...
<?php
//Carlos Galindo
//phpmember.com
$days = floor((time()-mktime(null,null,null,1,0,date("Y")))/86400);
echo "$days days have passed";
//Good Luck
?>
cebleo at n-trance dot net ¶
3 years ago
to ADD or SUBSTRACT times NOTE that if you dont specify the UTC zone your result is the difference +- your server UTC delay.
if you are ina utc/GMT +1
<?php
$hours_diff = strtotime("20:00:00")-strtotime("19:00:00");
echo date('h:i', $hours_diff)." Hours";
?>
it shows: 02:00 Hours
but if you use a default UTC time:
<?php
date_default_timezone_set('UTC');
$hours_diff = strtotime("20:00:00")-strtotime("19:00:00");
echo "<br>". date('h:i', $hours_diff);
?>
it shows: 01:00 Hours.
Alan ¶
4 years ago
Do remember that, counter-intuitively enough, the arguments for month and day are inversed (or middle-endian). A common mistake for Europeans seems to be to feed the date arguments in the expected order (big endian or little endian).
It's clear to see where this weird order comes from (even with the date being big endian the order for all arguments would still be mixed - it's obviously based on the American date format with the time "prefixed" to allow an easier shorthand) and why this wasn't changed (passing the values in the wrong order produces a valid, though unexpected, result in most cases), but it continues to be a source of confusion for me whenever I come back to PHP from other languages or libraries.
yan ¶
4 years ago
caculate days between two date
<?php
// end date is 2008 Oct. 11 00:00:00
$_endDate = mktime(0,0,0,11,10,2008);
// begin date is 2007 May 31 13:26:26
$_beginDate = mktime(13,26,26,05,31,2007);
$timestamp_diff= $_endDate-$_beginDate +1 ;
// how many days between those two date
$days_diff = $timestamp_diff/86400;
?>
skinnepa at hotmail dot com ¶
2 months ago
Convert Excel whacky-time to timestamp
function exceltoepoch($whackyexceltime) {
if (is_numeric($whackyexceltime)) {
// intify
$int_portion = (int)$whackyexceltime;
// get the decimals
$dec_portion = $whackyexceltime - $int_portion;
// $int portion is days since Jan 1, 1900.
$epoch = new DateTime('1900-01-01');
// remove 2 seems to be the magic number of days to remove.
$epoch->add(new DateInterval("P".($int_portion - 2)."D"));
// get the seconds that are left
$sec = ceil(86400 * $dec_portion);
// add the second to the epoch
$epoch->add(new DateInterval("PT".$sec."S"));
$ret = $epoch->getTimestamp();
unset($epoch);
//echo date("D, d M Y H:i:s", $ret) ."\n\n";
return $ret;
} else {
// probably not a whacky timestamp, lets try to guess it to
// an epoch and pray
$ts = strtotime($whackyexceltime);
//echo date("D, d M Y H:i:s", $ts)."\n\n";
return $ts;
}
}
pascal dot bonderff at gmail dot com ¶
4 months ago
To calculate the number of days between two dates, do not take the integer part of the difference is due to the transition to daylight saving time. We must take rounding:
<?php
function dateDiff($start, $end) {
$start_ts = strtotime($start);
$end_ts = strtotime($end);
$diff = $end_ts - $start_ts;
return round($diff / 86400);
}
?>
If you use the floor() instead of round() function, the result will be one day less if the start date is before the summer time date and the end date between the summer time date and the winter time date. This is due to the fact that the summer time date is one hour less.
Saravanan Swaminathan ¶
4 months ago
Function for Convert Integer Params to Time
<?php
function getTimeByHourMinAndSec($hour=NULL, $min=NULL, $sec=NULL)
{
if(!empty($hour) && !empty($min) && !empty($sec))
{
if(is_int($hour) && is_int($min) && is_int($sec))
{
$min = $min + floor($sec/60);
$hour = $hour + floor($min/60);
$min = $min%60;
$sec = $sec%60;
return $hour.':'.$min.':'.$sec;
}
else
return 'NULL';
}
else if(!empty($hour) && !empty($min))
{
if(is_int($hour) && is_int($min))
{
$hour = $hour + floor($min/60);
$min = $min%60;
return $hour.':'.$min.':00';
}
else
return 'NULL';
}
else if(!empty($hour))
{
if(is_int($hour))
{
return $hour.':00:00';
}
else
return 'NULL';
}
else
return 'NULL';
}
?>
xr714 at yahoo dot com ¶
2 years ago
One of the many problems with Daylight Saving Time / Summer Time is the ambiguity when a specified local time value can refer to two different actual times! This happens when the local time value is within the relapse range caused by the clocks being set back to proper time. (eg. if the DST/ST bias is +1 hour, and DST/ST terminates at 02:00 local time, a local time value of 01:30 occurs twice in the same day!)
Because the mktime() function only returns one value, it silently chooses whether to return the time-stamp for the first iteration or the second iteration of a specified local time within this critical range.
To get both possible time-stamps for a local time, compatible with any system locale, time zone, and applicable DST/ST rules, the following function can be used:
<?php /*><!--*/
function LocalToUT($LocalYear, $LocalMonth, $LocalMonthDay, $LocalHour24, $LocalMinute, $LocalSecond) {
/* Converts local date/time to Universal Time values. Returns both
possible UT values when local time value is within relapse range
(due to Daylight Saving Time / Summer Time termination).
Notes:
Conversion based on TZ and DST/ST rules used by mktime() function.
UT time-stamps are number of UT seconds since midnight Jan 1, 1970 UTC.
UT does not have leap seconds; a UT second is "stretched" by 2x duration
to maintain synchronization with UTC when a UTC leap second elapses.
Inputs: All inputs are numeric; $LocalHour24 is in 24-hour format.
Returns: Array:
'initial' = UT time-stamp of first occurrence of specified local date/time
'relapse' = UT time-stamp of second occurrence, when local time relapses upon DST/ST termination
*/
$UTValue = mktime($LocalHour24, $LocalMinute, $LocalSecond, $LocalMonth, $LocalMonthDay, $LocalYear);
$ReturnData = array('initial' => $UTValue, 'relapse' => $UTValue);
//Test for DST/ST transition since prev day
$Bias = $UTValue - mktime($LocalHour24, $LocalMinute, $LocalSecond, $LocalMonth, $LocalMonthDay - 1, $LocalYear) - 86400; //(-) = DST/ST commence, (+) = DST/ST terminate
if ($Bias == 0) { //No DST/ST transition detected since prev day
//Test for DST/ST transition up to next day
$Bias = mktime($LocalHour24, $LocalMinute, $LocalSecond, $LocalMonth, $LocalMonthDay + 1, $LocalYear) - $UTValue - 86400; //(-) = DST/ST commence, (+) = DST/ST terminate
}
if ($Bias > 0) { //DST/ST termination detected
if (date('Z', $UTValue) !== date('Z', $UTValue + $Bias)) { //Local time occurred in relapse range; System assumed 1st iteration
$ReturnData['relapse'] = $UTValue + $Bias;
}
if (date('Z', $UTValue - $Bias) !== date('Z', $UTValue)) { //Local time occurred in relapse range; System assumed 2nd iteration
$ReturnData['initial'] = $UTValue - $Bias;
}
//Else local time is outside of relapse range
} //Else no DST/ST transition, or transition is commencement
return $ReturnData;
}
/*--></?php */?>
Do not be confused by the start and end tags; The interleaved PHP-comment and HTML-comment delimiters prevent PHP code containing ">" from appearing as literal text when viewing or editing an HTML file with embedded PHP code.
lucianoiw at hotmail dot com ¶
4 years ago
Convert timestamp to time();
<?php
function wp_mktime($_timestamp = ''){
if($_timestamp){
$_split_datehour = explode(' ',$_timestamp);
$_split_data = explode("-", $_split_datehour[0]);
$_split_hour = explode(":", $_split_datehour[1]);
return mktime ($_split_hour[0], $_split_hour[1], $_split_hour[2], $_split_data[1], $_split_data[2], $_split_data[0]);
}
}
?>
[NOTE BY danbrown AT php DOT net: See also (http://php.net/strtotime)]
admin at stipe dot info ¶
4 years ago
With combination of mktime and getDate and date() you can add hours / seconds / days / months / years to ANY timestamp. Use strtotime() function to convert any type of dates to timestamp
<?php
public function addMonthToDate($timeStamp, $totalMonths=1){
// You can add as many months as you want. mktime will accumulate to the next year.
$thePHPDate = getdate($timeStamp); // Covert to Array
$thePHPDate['mon'] = $thePHPDate['mon']+$totalMonths; // Add to Month
$timeStamp = mktime($thePHPDate['hours'], $thePHPDate['minutes'], $thePHPDate['seconds'], $thePHPDate['mon'], $thePHPDate['mday'], $thePHPDate['year']); // Convert back to timestamp
return $timeStamp;
}
public function addDayToDate($timeStamp, $totalDays=1){
// You can add as many days as you want. mktime will accumulate to the next month / year.
$thePHPDate = getdate($timeStamp);
$thePHPDate['mday'] = $thePHPDate['mday']+$totalDays;
$timeStamp = mktime($thePHPDate['hours'], $thePHPDate['minutes'], $thePHPDate['seconds'], $thePHPDate['mon'], $thePHPDate['mday'], $thePHPDate['year']);
return $timeStamp;
}
public function addYearToDate($timeStamp, $totalYears=1){
$thePHPDate = getdate($timeStamp);
$thePHPDate['year'] = $thePHPDate['year']+$totalYears;
$timeStamp = mktime($thePHPDate['hours'], $thePHPDate['minutes'], $thePHPDate['seconds'], $thePHPDate['mon'], $thePHPDate['mday'], $thePHPDate['year']);
return $timeStamp;
}
?>
Jonathan Woodard ¶
5 years ago
NB: one 'gotcha' with the implementation of mktime()'s parameters:
<?php
for( $i = 1 ; $i <= 12 ; $i++ )
{
echo "Month '$i' is: " . date( "F" , mktime( 0 , 0 , 0 , $i ) ) . "\n";
}
?>
Will output:
Month '1' is: January
Month '2' is: March
Month '3' is: March
Month '4' is: May
Month '5' is: May
Month '6' is: July
Month '7' is: July
Month '8' is: August
Month '9' is: October
Month '10' is: October
Month '11' is: December
Month '12' is: December
on the 31st day of every month.
Why? Because the 5th parameter "day" defaults to "right now," which will not work reliably for days after the 28th.
To make sure this doesn't happen, specify the first day of the month:
<?php
mktime( 0 , 0 , 0 , $i , 1 )
?>
mike at mike-griffiths dot co dot uk ¶
5 years ago
It may be useful to note that no E_WARNINGS or E_NOTICES are give if you specify a date <1901 or >2038 on systems where time_t is a 32bit signed integer.
If a date is specified outside of the allowed range you may get some unexpected results as no timestamp will be returned.
jsebfranck ¶
6 years ago
There are several notes for mktime which use the number 86400 to differentiate two days. However this technique may pose a problem in case there is a day where the hour change between the two dates to compare.
Consequently, if you want the timestamp difference between the day where the hour change and the next day, it will not be equals to 86400 but either 82800 in case its the winter change of hour day or 90000 for the summer change of hour day.
For example in 2006 :
<?php
echo mktime(0,0,0,10,29,2006) - mktime(0,0,0,10,30,2006); // -90 000
?>
colin dot horne at gmail dot com ¶
8 years ago
If the month is greater than 12, it goes into the next year. If it is less than 1, it goes into the previous year. Generally, it behaves as you'd expect it to :-)
Examples:
<?php
// January 1, 2005
print date ("F j, Y", mktime (0,0,0,13,1,2004));
// December 1, 2003
print date ("F j, Y", mktime (0,0,0,0,1,2004));
// February 1, 2005
print date ("F j, Y", mktime (0,0,0,14,1,2004));
// November 1, 2003
print date ("F j, Y", mktime (0,0,0,-1,1,2004));
?>
praas at NOSPAM dot ision dot nl ¶
9 years ago
Consider skipping months with mktime().
$nextmonth = date("M",mktime(0,0,0,date("n")+1,date("j"),date("Y")));
On any day in Januari you expect to get Feb, right?
But on January 30th you'll get Mar. It will try Feb 30th, which doesn't exist, and skips another month. Therefore in this case present a day value that will certainly be legal in any month, like day "1".
This will give you next month on any day of the year:
$nextmonth = date("M",mktime(0,0,0,date("n")+1,1,date("Y")));
trahma ¶
9 years ago
I think it is important to note that the timestamp returned is based upon the number of seconds from the epoch GMT, and then modified by the time zone settings on the server.
Thus...
mktime(0,0,0,1,1,1970) will not always return 0. For example with the US eastern time zone (GMT-5) will return 18000 (5 hours past the epoch) and the same function with the time zone set to the US pacific time zone (GMT-8) will return 28800 (8 hours past the epoch).
In an instance where you want time zone independence, you should use the function gmmktime()
laurie at oneuponedown dot com ¶
9 years ago
With regard to Example 1 and using mktime to correct out-of-range input.
It should be noted that mktime will implement day light saving amends. Consider the following:
<?php
print(date("d/m/Y H:i:s",mktime(0,0,0,3,(27 + 1),2004)));
?>
OUTPUT "28/03/2004 02:00:00"
<?php
print(date("d/m/Y H:i:s",(mktime(0,0,0,3,27,2004) + (((1 * 24) * 60) * 60))));
?>
OUTPUT "28/03/2004 00:00:00"
Dependent on your requirements this may or may be desirable
arthur dot nicoll at dundeecity dot gov dot uk ¶
8 months ago
I do a lot of work using dates and times.
I use mktime() a lot. One wee word of caution over excessive use of incrementing the day parameter. Something I do quite a lot and works great for reasonable ranges.
I recently found, however, that the function gave erroneous results when too many days were added (i.e. around 6 months worth).
Changed to using mktime for the basic date then adding the required seconds to the integer datetime value.
e.g. instead of
<?php
for ($i=0; $i<$no_of_four_week_periods,$i++)
{
$curdatetm = mktime(0,0,0,4,(1+($i*28)),$curyr);
}
?>
.. try something like ..
<?php
$basedatetm = mktime(0,0,0,4,1,$curyr);
for ($i=0; $i<$no_of_four_week_periods,$i++)
{
$cudatetm = $basedatetm + ($i*28*24*60*60);
}
?>
cheers
Alex K. ¶
8 months ago
HTML5 form output date like 2012-10-08 converted to timestamp.
<?php
/**
* Convert html 5 output like YYYY-MM-DD to timestamp
* @param str $v date
* @return int UNIX timestamp
*
*/
function prepareDate($v) {
$t=explode("-", $v);
return ($v) ? mktime(0,0,0,$t[1],$t[2],$t[0]):false;
}
?>
Maffu ¶
4 years ago
When calling mktime(), be sure that you use values without leading zeros. The date comes out wrong in the following example:
$endts = mktime(12, 00, 00, 12, 08, 2008, 0);
(note the 08 instead of just 8)
C's scanf() has a format specification where leading 0's can indicate an octal value - perhaps this is related?
p2409 at hotmail dot com ¶
3 years ago
How to get the first and last dates of the last quarter - useful for things like tax return dates etc. by Justin
<?php
function getLastQuarter() {
// Returns an array with a start and end date for the last quarter from todays date
// eg. If today is 23 Feb 2009, returns $x['start'] = 1 Oct 2008, $x[end] = 31 Dec 2008
$year = date("Y",mktime());
$month = date("m",mktime());
// Formula to get a quarter in the year from a month
$startmth = $month - 3 - (($month-1) % 3 );
// Fix up Jan - Feb to get LAST year's quarter dates (Oct - Dec)
if ($startmth == -2) {
$startmth+=12;
$year-=1;
}
$endmth = $startmth+2;
$last_quarter['start'] = mktime(0,0,0,$startmth,1,$year);
$last_quarter['end'] = mktime(0,0,0,$endmth,date("t",mktime(0,0,0,$endmth,1,$year)),$year);
return $last_quarter;
}
// Example - print first and last dates of last quarter.
echo "First day of last quarter was : " . date("d-M-Y",$lastquarter['start']) . "\n";
echo "Last day of last quarter was : " . date("d-M-Y",$lastquarter['end']) . "\n";
// For 2 August 2009, returns:
// First day of last quarter was : 01-Apr-2009
// Last day of last quarter was : 30-Jun-2009
//
?>