strrev
Generally speaking, linear searches are from start to end, not end to start - which makes sense from a human perspective. If you need to find strings in a string backwards, reverse your haystack and needle rather than manually chopping it up.
strripos
(PHP 5)
strripos — Find the position of the last occurrence of a case-insensitive substring in a string
Descrierea
int strripos
( string $haystack
, string $needle
[, int $offset = 0
] )
Find the numeric position of the last occurrence of needle in the haystack string.
Unlike the strrpos(), strripos() is case-insensitive.
Parametri
- haystack
-
The string to search in.
- needle
-
If needle is not a string, it is converted to an integer and applied as the ordinal value of a character.
- offset
-
If specified, search will start this number of characters counted from the beginning of the string. If the value is negative, search will instead start from that many characters from the end of the string, searching backwards.
Valorile întoarse
Returns the position where the needle exists relative to the beginnning of the haystack string (independent of search direction or offset). Also note that string positions start at 0, and not 1.
Returns FALSE if the needle was not found.
Avertizare
Această funcție poate întoarce valoarea Boolean FALSE, dar poate de asemenea întoarce o valoare non-Boolean care evaluează în FALSE, cum ar fi 0 sau "". Vă rugăm să citiți secțiunea despre tipul Boolean pentru mai multe informații. Utilizați operatorul === pentru a verifica valoarea întoarsă de această funcție.
Exemple
Example #1 A simple strripos() example
<?php
$haystack = 'ababcd';
$needle = 'aB';
$pos = strripos($haystack, $needle);
if ($pos === false) {
echo "Sorry, we did not find ($needle) in ($haystack)";
} else {
echo "Congratulations!\n";
echo "We found the last ($needle) in ($haystack) at position ($pos)";
}
?>
Exemplul de mai sus va afișa:
Congratulations! We found the last (aB) in (ababcd) at position (2)
Vedeți de asemenea
- strpos() - Find the position of the first occurrence of a substring in a string
- stripos() - Find the position of the first occurrence of a case-insensitive substring in a string
- strrpos() - Find the position of the last occurrence of a substring in a string
- strrchr() - Find the last occurrence of a character in a string
- stristr() - Case-insensitive strstr
- substr() - Return part of a string
add a note
User Contributed Notes
strripos
Anonymous
31-Aug-2010 01:05
admin at e-xxi dot net
08-Mar-2010 07:00
strripos() has very strange behaviour when you provide search position. For some reason it searches forward from the given position, instead of searching backward, that is more logical.
For example if you want to find instanse of $what, previous to the last, strripos($where, $what, $last_what_pos-1) will not wark as expected. It will return $last_what_pos again and again. And that has no sence at all.
To prevent this, I just used $prev_last_what_pos = strripos(substr($where,0,$last_what_pos), $what);
dimmav at in dot gr
25-Sep-2008 09:31
Suppose you just need a stripos function working backwards expecting that strripos does this job, you better use the following code of a custom function named strbipos:
<?php
function strbipos($haystack="", $needle="", $offset=0) {
// Search backwards in $haystack for $needle starting from $offset and return the position found or false
$len = strlen($haystack);
$pos = stripos(strrev($haystack), strrev($needle), $len - $offset - 1);
return ( ($pos === false) ? false : $len - strlen($needle) - $pos );
}
// Test
$body = "01234Xy7890XYz456xy90";
$str = "xY";
$len = strlen($body);
echo "TEST POSITIVE offset VALUES IN strbipos<br>";
for ($i = 0; $i < $len; $i++) {
echo "Search in [$body] for [$str] starting from offset [$i]: [" . strbipos($body, $str, $i) . "]<br>";
}
?>
Note that this function does exactly what it says and its results are different comparing to PHP 5 strripos function.
peev[dot]alexander at gmail dot com
20-Apr-2008 02:14
OK, I guess this will be the final function implementation for PHP 4.x versions ( my previous posts are invalid )
<?php
if(!function_exists("stripos")){
function stripos( $str, $needle, $offset = 0 ){
return strpos( strtolower( $str ), strtolower( $needle ), $offset );
}/* endfunction stripos */
}/* endfunction exists stripos */
if(!function_exists("strripos")){
function strripos( $haystack, $needle, $offset = 0 ) {
if( !is_string( $needle ) )$needle = chr( intval( $needle ) );
if( $offset < 0 ){
$temp_cut = strrev( substr( $haystack, 0, abs($offset) ) );
}
else{
$temp_cut = strrev( substr( $haystack, 0, max( ( strlen($haystack) - $offset ), 0 ) ) );
}
if( ( $found = stripos( $temp_cut, strrev($needle) ) ) === FALSE )return FALSE;
$pos = ( strlen( $haystack ) - ( $found + $offset + strlen( $needle ) ) );
return $pos;
}/* endfunction strripos */
}/* endfunction exists strripos */
?>
peev[dot]alexander at gmail dot com
23-Nov-2007 03:05
Oops, I forgot to return "false" if the needle is not found. Here is the proper function.
<?php
if(!function_exists("strripos")){
function strripos($haystack, $needle, $offset=0) {
if($offset<0){
$temp_cut = strrev( substr( $haystack, 0, abs($offset) ) );
}
else{
$temp_cut = strrev( substr( $haystack, $offset ) );
}
$pos = strlen($haystack) - (strpos($temp_cut, strrev($needle)) + $offset + strlen($needle));
if ($pos == strlen($haystack)) { $pos = 0; }
if(strpos($temp_cut, strrev($needle))===false){
return false;
}
else return $pos;
}/* endfunction strripos*/
}/* endfunction exists strripos*/
?>
peev[dot]alexander at gmail dot com
17-Oct-2007 05:23
I think you shouldn't underestimate the length of $needle in the search of THE FIRST POSITION of it's last occurrence in the string. I improved the posted function, with added support for offset. I think this is an exact copy of the real function:
<?php
if(!function_exists("strripos")){
function strripos($haystack, $needle, $offset=0) {
if($offset<0){
$temp_cut = strrev( substr( $haystack, 0, abs($offset) ) );
}
else{
$temp_cut = strrev( substr( $haystack, $offset ) );
}
$pos = strlen($haystack) - (strpos($temp_cut, strrev($needle)) + $offset + strlen($needle));
if ($pos == strlen($haystack)) { $pos = 0; }
return $pos;
}/* endfunction strripos*/
}/* endfunction exists strripos*/
?>
ElectroFox
02-Aug-2007 01:59
Sorry, I made that last post a bit prematurely. One more thing wrong with the simple php4 version is that it breaks if the string is not found. It should actually look like this:
<?php
if (function_exists('strripos') == false) {
function strripos($haystack, $needle) {
$pos = strlen($haystack) - strpos(strrev($haystack), strrev($needle));
if ($pos == strlen($haystack)) { $pos = 0; }
return $pos;
}
}
?>
Note, we now check to see if the $needle was found, and if it isn't, we return 0.
ElectroFox
02-Aug-2007 01:39
Actually, the above, "Simple way to implement this function in PHP 4" by Yanik Lupien, should be:
<?php
if (function_exists('strripos') == false) {
function strripos($haystack, $needle) {
return strlen($haystack) - strpos(strrev($haystack), strrev($needle));
}
}
?>
Note the reversal (<?php strrev($needle)?>) of the search string. This was left out in Yanik's example, and without it, you'll simply get the length of the haystack, as the forward string will not likely be found in the reversed haystack.
Thus; if we reverse the haystack, any instance of the search string ($needle) therein will also be reversed, so we must reverse it to look for it. :)
Yanik Lupien
03-Jul-2007 10:47
Simple way to implement this function in PHP 4
<?php
if (function_exists('strripos') == false) {
function strripos($haystack, $needle) {
return strlen($haystack) - strpos(strrev($haystack), $needle);
}
}
?>
aidan at php dot net
30-May-2004 10:36
This functionality is now implemented in the PEAR package PHP_Compat.
More information about using this function without upgrading your version of PHP can be found on the below link:
http://pear.php.net/package/PHP_Compat