PHP 5.4.36 Released

DateTime::sub

date_sub

(PHP 5 >= 5.3.0)

DateTime::sub -- date_sub Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object

Beschreibung

Objektorientierter Stil

public DateTime DateTime::sub ( DateInterval $interval )

Prozeduraler Stil

DateTime date_sub ( DateTime $object , DateInterval $interval )

Subtracts the specified DateInterval object from the specified DateTime object.

Parameter-Liste

object

Nur bei prozeduralem Aufruf: Ein von date_create() zurückgegebenes DateTime-Objekt. Diese Funktion verändert dieses Objekt.

interval

A DateInterval object

Rückgabewerte

Gibt das DateTime-Objekt für die Verkettung von Methoden zurück Im Fehlerfall wird FALSE zurückgegeben.

Beispiele

Beispiel #1 DateTime::sub() example

Objektorientierter Stil

<?php
$date 
= new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo 
$date->format('Y-m-d') . "\n";
?>

Prozeduraler Stil

<?php
$date 
date_create('2000-01-20');
date_sub($datedate_interval_create_from_date_string('10 days'));
echo 
date_format($date'Y-m-d');
?>

Die obigen Bespiele erzeugen folgende Ausgabe:

2000-01-10

Beispiel #2 Further DateTime::sub() examples

<?php
$date 
= new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo 
$date->format('Y-m-d H:i:s') . "\n";

$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo 
$date->format('Y-m-d H:i:s') . "\n";
?>

Das oben gezeigte Beispiel erzeugt folgende Ausgabe:

2000-01-19 13:59:30
1992-08-15 19:56:58

Beispiel #3 Beware when subtracting months

<?php
$date 
= new DateTime('2001-04-30');
$interval = new DateInterval('P1M');

$date->sub($interval);
echo 
$date->format('Y-m-d') . "\n";

$date->sub($interval);
echo 
$date->format('Y-m-d') . "\n";
?>

Das oben gezeigte Beispiel erzeugt folgende Ausgabe:

2001-03-30
2001-03-02

Anmerkungen

DateTime::modify() is an alternative when using PHP 5.2.

Siehe auch

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User Contributed Notes 3 notes

up
8
Anonymous
3 years ago
Note that the sub() and add() methods will modify the value of the object you're calling the method on! This is very untypical for a method that returns a value of its own type. You could misunderstand it that the method would return a new instance with the modified value, but in fact it modifies itself! This is undocumented here. (Only a side note on procedural style mentions it, but it obviously does not apply to object oriented style.)
up
2
itonohito
8 months ago
When trying to pass daylight saving state change time, sub() works incorrectly.

$t = new DateTime( '2014-03-30 02:00:00' );
$t->add( new DateInterval('PT1H') );
echo $->format('Y-m-d H:i:s');

output will be: '2014-03-30 04:00:00'.

Well, it's ok because at 3:00 a.m. daylight saving time begins in my country, so after  02:59:59 must be 04:00:00.

But if I try to subtract time:

$t = new DateTime( '2014-03-30 04:00:00' );
$t->sub( new DateInterval('PT1H') );
echo $->format('Y-m-d H:i:s');

output will be: '2014-03-30 04:00:00'.

Yes, completely the same, not '2014-03-30 02:00:00' as it should be.
up
0
php at keith tyler dot com
4 years ago
If you use diff() after sub(), the effects of the sub() will be repeated on the date object.

It doesn't matter if the object is the one diffed or doing the diffing (i.e. which object you call diff() from).

<?php
$today
= new DateTime();
$newdate = new DateTime();

print_r($newdate);
$newdate->sub(new DateInterval("PT1S"));
print_r($newdate);
$s = $newdate->diff($today);
print_r($newdate);
$s = $today->diff($newdate);
print_r($newdate);
$s = $today->diff($newdate);
print_r($newdate);
?>

Prints:

DateTime Object
(
    [date] => 2010-11-30 18:43:48
    [timezone_type] => 3
    [timezone] => America/Los_Angeles
)
DateTime Object
(
    [date] => 2010-11-30 18:43:47
    [timezone_type] => 3
    [timezone] => America/Los_Angeles
)
DateTime Object
(
    [date] => 2010-11-30 18:43:46
    [timezone_type] => 3
    [timezone] => America/Los_Angeles
)
DateTime Object
(
    [date] => 2010-11-30 18:43:45
    [timezone_type] => 3
    [timezone] => America/Los_Angeles
)
DateTime Object
(
    [date] => 2010-11-30 18:43:44
    [timezone_type] => 3
    [timezone] => America/Los_Angeles
)

Note that using add() instead of sub() does NOT have the same effect.

This is particularly undesirable -- in this example you make a datetime, use sub() to make it a relative time in the past, and then date->diff() to confirm the difference. But the diff() inadvertendly makes the difference 2x.
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