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ltrimEntfernt Leerraum (oder andere Zeichen) vom Anfang eines Strings


string ltrim ( string $str [, string $character_mask ] )

Entfernt Leerraum (oder andere Zeichen) vom Anfang eines Strings.



Die Eingabezeichenkette.


Sie können mittels des character_mask-Parameters eigene Zeichen angeben, die Sie entfernen lassen möchten. Führen Sie einfach alle zu löschenden Zeichen auf. Mittels .. können Sie einen Bereich von Zeichen benennen.


Diese Funktion gibt den String str zurück, von dessen Anfang alle Whitespaces entfernt wurden. Ohne den zweiten Parameter entfernt ltrim() diese Zeichen:

  • " " (ASCII 32 (0x20)), ein einfaches Leerzeichen.
  • "\t" (ASCII 9 (0x09)), ein Tabulator.
  • "\n" (ASCII 10 (0x0A)), ein Zeilenvorschub (line feed).
  • "\r" (ASCII 13 (0x0D)), ein Wagenrücklauf-Zeichen (carriage return).
  • "\0" (ASCII 0 (0x00)), das NUL-Byte.
  • "\x0B" (ASCII 11 (0x0B)), ein vertikaler Tabulator.


Beispiel #1 Beispiel zur Verwendung von ltrim()


"\t\tThese are a few words :) ...  ";
$binary "\x09Example string\x0A";
$hello  "Hello World";


$trimmed ltrim($text);

$trimmed ltrim($text" \t.");

$trimmed ltrim($hello"Hdle");

// entfernt die ASCII Steuerzeichen vom Beginn von $binary
// (von 0 bis einschließlich 31)
$clean ltrim($binary"\x00..\x1F");


Das oben gezeigte Beispiel erzeugt folgende Ausgabe:

string(32) "        These are a few words :) ...  "
string(16) "    Example string
string(11) "Hello World"

string(30) "These are a few words :) ...  "
string(30) "These are a few words :) ...  "
string(7) "o World"
string(15) "Example string

Siehe auch

  • trim() - Entfernt Whitespaces (oder andere Zeichen) am Anfang und Ende eines Strings
  • rtrim() - Entfernt Leerraum (oder andere Zeichen) vom Ende eines Strings

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User Contributed Notes 8 notes

dzek dot remove_this at dzek dot eu
4 years ago
Guys, if += 0 is producing wrong values sometimes, and preg_replace is cpu consuming, then just stick to the main function described on that page, and use:
= ltrim($value, '0');
should be the fastest and most reliable.
I think all those comments can be misleading for begginers checking this page - it's sort of using magic tricks to reinvent the wheel.
Usamah M dot Ali (usamah1228 at gmail dot com)
8 years ago
For those who use right-to-left languages such as Arabic, Hebrew, etc., it's worth mentioning that ltrim() (which stands for left trim) & rtrim() (which stands for right trim) DO NOT work contextually. The nomenclature is rather semantically incorrect. So in an RTL script, ltrim() will trim text from the right direction (i.e. beginning of RTL strings), and rtrim() will trim text from the left direction (i.e. end of RTL strings).
tavi undersc 10 from yahoocom
6 months ago
When using a $character_mask the trimming stops at the first character that is not on that mask.

So in the $string = "Hello world" example with $character_mask = "Hdle", ltrim($hello, $character_mask) goes like this:
1. Check H from "Hello world" => it is in the $character_mask, so remove it
2. Check e from "ello world" => it is in the $character_mask, so remove it
3. Check l from "llo world" => it is in the $character_mask, so remove it
4. Check l from "lo world" => it is in the $character_mask, so remove it
5. Check o from "o world" => it is NOT in the $character_mask, exit the function

Remaining string is "o world".

I hope it helps someone as I had a confusing moment with this function.
juan at ecogomera dot com
2 years ago
+=0 not valid for something like 0000-5. Result is 0
mroeling at exed dot nl
2 years ago

The problem is that the character mask (_stw in your case) isn't a literal string, but a character collection. So all characters within _stw are stripped. In your case this includes the w of weight also.
John Sherwood
9 years ago
To remove leading/trailing zeroes (example: "0123.4560"), doing a += 0 is easier than trim tricks.
scion4581 at mail dot ru
2 years ago
What i found and i can't get why:

$word = 'stw_weight';
echo ltrim($word, 'stw_');

output:  eight instead weight

If anybody know plz let me know
5 years ago
Keep in mind the amount of resources preg_replace() uses. 
I would suggest a simple if statement if you need to parse through large amounts of data. 
function remove_leading_zeros_from_number($number_string) {
$limit = 9000.1
= $number
(float) $temp;
  if (
$number < $limit) {
$number += 0;
  } else {

Code is untested, but probably sound.
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