SplFileObject::__construct

(PHP 5 >= 5.1.0)

SplFileObject::__constructConstruct a new file object.

Description

public SplFileObject::__construct ( string $filename [, string $open_mode = "r" [, bool $use_include_path = false [, resource $context ]]] )

Construct a new file object.

Parameters

filename

The file to read.

Tip

A URL can be used as a filename with this function if the fopen wrappers have been enabled. See fopen() for more details on how to specify the filename. See the Supported Protocols and Wrappers for links to information about what abilities the various wrappers have, notes on their usage, and information on any predefined variables they may provide.

open_mode

The mode in which to open the file. See fopen() for a list of allowed modes.

use_include_path

Whether to search in the include_path for filename.

context

A valid context resource created with stream_context_create().

Return Values

No value is returned.

Errors/Exceptions

Throws a RuntimeException if the filename cannot be opened.

Examples

Example #1 SplFileObject::__construct() example

This example opens the current file and iterates over its contents line by line.

<?php
$file 
= new SplFileObject(__FILE__);
foreach (
$file as $line_num => $line) {
    echo 
"Line $line_num is $line";
}
?>

The above example will output something similar to:

Line 0 is <?php
Line 1 is $file = new SplFileObject(__FILE__);
Line 2 is foreach ($file as $line_num => $line) {
Line 3 is     echo "Line $line_num is $line";
Line 4 is }
Line 5 is ?>

See Also

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User Contributed Notes 1 note

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0
majna
2 months ago
(PHP >= 5.3) If filename is a directory, a LogicException will be thrown: "Cannot use SplFileObject with directories"
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