Try this to know behavior:
<?php
function resource_test($resource, $name) {
echo
'[' . $name. ']',
PHP_EOL,
'(bool)$resource => ',
$resource ? 'TRUE' : 'FALSE',
PHP_EOL,
'get_resource_type($resource) => ',
get_resource_type($resource) ?: 'FALSE',
PHP_EOL,
'is_resoruce($resource) => ',
is_resource($resource) ? 'TRUE' : 'FALSE',
PHP_EOL,
PHP_EOL
;
}
$resource = tmpfile();
resource_test($resource, 'Check Valid Resource');
fclose($resource);
resource_test($resource, 'Check Released Resource');
$resource = null;
resource_test($resource, 'Check NULL');
?>
It will be shown as...
[Check Valid Resource]
(bool)$resource => TRUE
get_resource_type($resource) => stream
is_resoruce($resource) => TRUE
[Check Released Resource]
(bool)$resource => TRUE
get_resource_type($resource) => Unknown
is_resoruce($resource) => FALSE
[Check NULL]
(bool)$resource => FALSE
get_resource_type($resource) => FALSE
Warning: get_resource_type() expects parameter 1 to be resource, null given in ... on line 10
is_resoruce($resource) => FALSE
get_resource_type
(PHP 4 >= 4.0.2, PHP 5, PHP 7)
get_resource_type — Devuelve el tipo de recurso
Descripción
get_resource_type
( resource
$handle
) : stringEsta función obtiene el tipo del recurso dado.
Parámetros
-
handle -
El gestor de recurso evaluado.
Valores devueltos
Si el dado handle es un recurso esta función
devolverá una cadena que representa su tipo. Si el tipo no es identificado
por esta función, el valor de retorno será la cadena
Unknown.
Está función devolverá FALSE y generará un error si
handle no es un resource.
Ejemplos
Ejemplo #1 Ejemplo deget_resource_type()
<?php
// imprime: mysql link
$c = mysql_connect();
echo get_resource_type($c) . "\n";
// imprime: stream
$fp = fopen("foo", "w");
echo get_resource_type($fp) . "\n";
// imprime: domxml document
$doc = new_xmldoc("1.0");
echo get_resource_type($doc->doc) . "\n";
?>
add a note
User Contributed Notes 4 notes
CertaiN ¶
5 years ago
jdhawk _at_ gmail ¶
13 years ago
In PHP5 (on Linux), the above example identifies the "file" handler as a 'stream', not 'file'.
This can be particularly worrisome if you're trying to determine the type of stream using this function.
The alternative is to use <?php stream_get_meta_data() ?>, which returns an array containing "stream_type (string) - a label describing the underlying implementation of the stream."
hessodreamy at gmail dot com ¶
11 years ago
Furthermore, this function returns 'stream' on php 4.3 on windows & linux.
You if you want to differentiate between a file resource and other stream resources, as stated before stream_get_meta_data() gives you an array which, on my system, contains the following elements which might suggest a file handle:
[wrapper_type] => plainfile
[stream_type] => STDIO
However I've only compared this to a stream from a url, so I include this only as a suggestion.
avp200681 at gmail dot com ¶
7 years ago
This function will generate an error and return NULL instead FALSE in the next example:
<?php
$var = 3;
var_dump(get_resource_type($var));
?>
