It seems like pg_fetch_all() only works on version 4.3.x. I tried it with 4.2.2 and it does not recognize the function, so I assume it won't work on 4 => 4.2.x.
pg_fetch_all
(PHP 4 >= 4.3.0, PHP 5)
pg_fetch_all — Fetches all rows from a result as an array
Descripción
array pg_fetch_all
( resource
$result
)pg_fetch_all() returns an array that contains all rows (records) in the result resource.
Nota: Esta función define campos NULOS al valor
NULLde PHP.
Parámetros
-
result -
PostgreSQL query result resource, returned by pg_query(), pg_query_params() or pg_execute() (among others).
Valores devueltos
An array with all rows in the result. Each row is an array of field values indexed by field name.
FALSE is returned if there are no rows in the result, or on any
other error.
Ejemplos
Ejemplo #1 PostgreSQL fetch all
<?php
$conn = pg_pconnect("dbname=publisher");
if (!$conn) {
echo "An error occurred.\n";
exit;
}
$result = pg_query($conn, "SELECT * FROM authors");
if (!$result) {
echo "An error occurred.\n";
exit;
}
$arr = pg_fetch_all($result);
print_r($arr);
?>
El resultado del ejemplo sería algo similar a:
Array
(
[0] => Array
(
[id] => 1
[name] => Fred
)
[1] => Array
(
[id] => 2
[name] => Bob
)
)
Ver también
- pg_fetch_row() - Get a row as an enumerated array
- pg_fetch_array() - Fetch a row as an array
- pg_fetch_object() - Fetch a row as an object
- pg_fetch_result() - Returns values from a result resource
add a note
User Contributed Notes 7 notes
tasmanian at devil dot com ¶
10 years ago
strata_ranger at hotmail dot com ¶
4 years ago
Be aware that pg_fetch_all() is subject to the same limitations as pg_fetch_assoc(), in that if your query returns multiple columns with the same name (or alias) then only the rightmost one will be returned in the associative array, other ones will not.
A simple example:
<?php
$res = pg_query(
"SELECT a.*, b.* -- Fetch all columns from both tables
FROM table1 AS a
LEFT OUTER JOIN table2 as b
USING (column)"
);
$rows = pg_fetch_all($res);
?>
In this example, since we're selecting columns via *, if any columns from table2 share the same names as those in table1, they will be the ones returned despite that table2 (as the optional side of an outer join) may return NULL values.
This is not a bug, just a limitation of associative arrays in general, and is easy enough to avoid by structuring your queries carefully and using column aliases to avoid confusion.
prefer_not_to at say dot com ¶
4 years ago
For those wondering, this function returns a two-dimentional array, the first dimension being a 0-based indexed array, the second dimension an associative. So you might access the first authors surname using $authors[0]["surname"].
Certainly this is the case in PHP 5.2.9, I can't vouch for other versions though.
Anonymous ¶
10 years ago
Also for those who are trying to move off oracle, pg_fetch_all returns an array with rows and columns inverted in the sense of ocifetchall. You would need to transpose this result array before your code takes the first index a column name and the second index a row index.
php dot net at mechintosh dot com ¶
10 years ago
For versions of PHP that don't yet support the new names or newer functions I wrote a couple functions like this one
if (! function_exists("pg_fetch_all")) {
function pg_fetch_all($res, $kind="assoc") {
$i = 0; // this is needed for the row integer in the looped pg_fetch_array
if ($kind == "assoc") {
while ($row = pg_fetch_array($res, $i, PGSQL_ASSOC)) {
$array_out[] = $row;
$i++;
}else{
while ($row = pg_fetch_array($res)) {
$array_out[] = $row;
}
}
return $array_out;
}
}
jcomeau at whatisthewww dot com ¶
11 years ago
pg_fetch_all, despite the app note, accepts only one argument, the resultset. It does exactly what is expected, returning a two-dimensional array of the resultset. I suspect the app note given was just copied from pg_fetch_array, which is what you want to use for a single row.
