as noted by guilhermeblanco at php dot net,
<?php
// fact.php
namespace foo;
class fact {
public function create($class) {
return new $class();
}
}
?>
<?php
// bar.php
namespace foo;
class bar {
...
}
?>
<?php
// index.php
namespace foo;
include('fact.php');
$foofact = new fact();
$bar = $foofact->create('bar'); // attempts to create \bar
// even though foofact and
// bar reside in \foo
?>
La commande namespace et la constante __NAMESPACE__
Utilisation des espaces de noms : introduction
[edit] Last updated: Fri, 14 Jun 2013
Utilisation des espaces de noms : introduction
[edit] Last updated: Fri, 14 Jun 2013
Espaces de noms et langage dynamique
(PHP 5 >= 5.3.0)
L'implémentation des espaces de noms de PHP est influencée par sa nature dynamique de langage de programmation. Par conséquent, pour convertir du code tel que le code de l'exemple suivant, en un espace de noms :
Exemple #1 Accès dynamique aux éléments
example1.php:
<?php
class classname
{
function __construct()
{
echo __METHOD__,"\n";
}
}
function funcname()
{
echo __FUNCTION__,"\n";
}
const constname = "global";
$a = 'classname';
$obj = new $a; // affiche classname::__construct
$b = 'funcname';
$b(); // affiche funcname
echo constant('constname'), "\n"; // affiche global
?>
Exemple #2 Accès dynamique à des espaces de noms
<?php
namespace nomdelespacedenoms;
class classname
{
function __construct()
{
echo __METHOD__,"\n";
}
}
function funcname()
{
echo __FUNCTION__,"\n";
}
const constname = "namespaced";
include 'example1.php';
$a = 'classname';
$obj = new $a; // affiche classname::__construct
$b = 'funcname';
$b(); // affiche funcname
echo constant('constname'), "\n"; // affiche global
/* Note que si vous utilisez des guillemets doubles, "\\nomdelespacedenoms\\classname" doit être utilisé */
$a = '\nomdelespacedenoms\classname';
$obj = new $a; // affiche nomdelespacedenoms\classname::__construct
$a = 'nomdelespacedenoms\classname';
$obj = new $a; // affiche aussi nomdelespacedenoms\classname::__construct
$b = 'nomdelespacedenoms\funcname';
$b(); // affiche nomdelespacedenoms\funcname
$b = '\nomdelespacedenoms\funcname';
$b(); // affiche aussi nomdelespacedenoms\funcname
echo constant('\nomdelespacedenoms\constname'), "\n"; // affiche namespaced
echo constant('nomdelespacedenoms\constname'), "\n"; // affiche aussi namespaced
?>
Il est recommandé de lire la note au sujet de la protection des espaces de noms dans les chaînes.
La commande namespace et la constante __NAMESPACE__
Utilisation des espaces de noms : introduction
[edit] Last updated: Fri, 14 Jun 2013
Utilisation des espaces de noms : introduction
[edit] Last updated: Fri, 14 Jun 2013
add a note
User Contributed Notes
Espaces de noms et langage dynamique - [3 notes]
scott at intothewild dot ca ¶
3 years ago
guilhermeblanco at php dot net ¶
4 years ago
Please be aware of FQCN (Full Qualified Class Name) point.
Many people will have troubles with this:
<?php
// File1.php
namespace foo;
class Bar { ... }
function factory($class) {
return new $class;
}
// File2.php
$bar = \foo\factory('Bar'); // Will try to instantiate \Bar, not \foo\Bar
?>
To fix that, and also incorporate a 2 step namespace resolution, you can check for \ as first char of $class, and if not present, build manually the FQCN:
<?php
// File1.php
namespace foo;
function factory($class) {
if ($class[0] != '\\') {
echo '->';
$class = '\\' . __NAMESPACE__ . '\\' . $class;
}
return new $class();
}
// File2.php
$bar = \foo\factory('Bar'); // Will correctly instantiate \foo\Bar
$bar2 = \foo\factory('\anotherfoo\Bar'); // Wil correctly instantiate \anotherfoo\Bar
?>
Alexander Kirk ¶
1 year ago
When extending a class from another namespace that should instantiate a class from within the current namespace, you need to pass on the namespace.
<?php // File1.php
namespace foo;
class A {
public function factory() {
return new C;
}
}
class C {
public function tell() {
echo "foo";
}
}
?>
<?php // File2.php
namespace bar;
class B extends \foo\A {}
class C {
public function tell() {
echo "bar";
}
}
?>
<?php
include "File1.php";
include "File2.php";
$b = new bar\B;
$c = $b->factory();
$c->tell(); // "foo" but you want "bar"
?>
You need to do it like this:
When extending a class from another namespace that should instantiate a class from within the current namespace, you need to pass on the namespace.
<?php // File1.php
namespace foo;
class A {
protected $namespace = __NAMESPACE__;
public function factory() {
$c = $this->namespace . '\C';
return new $c;
}
}
class C {
public function tell() {
echo "foo";
}
}
?>
<?php // File2.php
namespace bar;
class B extends \foo\A {
protected $namespace = __NAMESPACE__;
}
class C {
public function tell() {
echo "bar";
}
}
?>
<?php
include "File1.php";
include "File2.php";
$b = new bar\B;
$c = $b->factory();
$c->tell(); // "bar"
?>
(it seems that the namespace-backslashes are stripped from the source code in the preview, maybe it works in the main view. If not: fooA was written as \foo\A and barB as bar\B)