PHP Unconference Europe 2015

get_included_files

(PHP 4, PHP 5)

get_included_files Restituisce una matrice con i nomi dei file inclusi o richiesti

Descrizione

array get_included_files ( void )

Restituisce una matrice contenente i nomi di tutti i file che sono stati includi tramite le funzioni include, include_once, require oppure require_once.

Lo script originario viene considerato come 'file incluso', pertanto sarà elencato insieme agli altri file referenziati da include e simili.

File che sono inclusi più volte saranno elencati soltanto una volta sola

Nota:

File inclusi tramite la direttiva auto_prepend_file non saranno inseriti nella matrice.

Example #1 Esempio di uso di get_included_files() del file (abc.php)

<?php

include 'test1.php';
include_once 
'test2.php';
require 
'test3.php';
require_once 
'test4.php';

$included_files get_included_files();

foreach (
$included_files as $filename) {
    echo 
"$filename\n";
}

?>

l'esempio visualizzerà:

abc.php
test1.php
test2.php
test3.php
test4.php

Nota:

In PHP 4.0.1pl2 e nelle versioni precedenti get_included_files() assumeva che i file inclusi avessero come estensione .php; file con altre estensioni erano ignorati. La matrice restituita da get_included_files() era una matrice associativa e riportava soltanto i file inclusi con include e include_once.

Vedere anche include, include_once, require, require_once e get_required_files().

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User Contributed Notes 5 notes

up
1
RPaseur at NationalPres dot org
8 years ago
As is often the case, YMMV.  I tried the __FILE__ and SCRIPT_FILENAME comparison and found this:

SCRIPT_FILENAME: /var/www/cgi-bin/php441
__FILE__: /raid/home/natpresch/natpresch/RAY_included.php

As an alternative:

count(get_included_files());

Gives one when the script is standalone and always more than one when the script is included.
up
1
donikuntoro at integraasp dot com
3 years ago
This function aims to perform filtering of files that have been included :

<?php
function setIncludeFiles($arrayInc = array()){
   
$incFiles = get_included_files();
    if((
count($arrayInc)>0)&&(count($incFiles)>0)){
       
$aInt = array_intersect($arrayInc,$incFiles);
        if(
count($aInt)>0){
            return
false;
       }elseif(
count($aInt)<1) {
        foreach(
$arrayInc as $inc){
            if(
is_file($inc))
                include(
$inc);
            else{
                return
false;
            }
        }
       }   
    }else{
        return
false;
    }
}
?>

Usage :

<?php
$toBeInclude
= array('/data/your_include_files_1.php',
'/data/your_include_files_2.php',
'/data/your_include_files_3.php',
);
setIncludeFiles($toBeInclude);
?>

Return false if something goes wrong.
up
1
yarco dot w at gmail dot com
7 years ago
If you have a MAIN php script which you don't want to be included by other scripts, you could use this function. For example:

main.php:
<?php
function blockit()
{
 
$buf = get_included_files();
  return
$buf[0] != __FILE__;
}

blockit() and exit("You can not include a MAIN file as a part of your script.");

print
"OK";
?>

So other script couldn't include main.php to modify its internal global vars.
up
0
indigohaze at gmail dot com
8 years ago
Something that's not noted in the docs, if a file is included remotely and you do a get_included_files() in the include itself it will *not* return the document that included it.

ie:
test2.php (server 192.168.1.14):
<?php

include("http://192.168.1.11/test/test3.php");

?>

test3.php (server 192.168.1.11):

<?php

$files
= get_included_files();

print_r($files);
?>

returns:

Array ( [0] => /var/www/localhost/htdocs/test/test3.php )

Which means you can use get_included_files() to help intercept and prevent XSS-style attacks against your code.
up
0
keystorm :at: gmail dotcom
10 years ago
As of PHP5, this function seems to return an array with the first index being the script all subsequent scripts are included to.
If index.php includes b.php and c.php and calls get_included_files(), the returned array looks as follows:

index.php
a.php
b.php

while in PHP<5 the array would be:

a.php
b.php

If you want to know which is the script that is including current script you can use $_SERVER['SCRIPT_FILENAME'] or any other similar server global.

If you also want to ensure current script is being included and not run independently you should evaluate following expression:

__FILE__ != $_SERVER['SCRIPT_FILENAME']

If this expression returns TRUE, current script is being included or required.
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