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zip_entry_name

(PHP 4 >= 4.1.0, PHP 5 >= 5.2.0, PECL zip >= 1.0.0)

zip_entry_nameRetorna o nome do arquivo

Descrição

string zip_entry_name ( resource $zip_entry )

Retorna o nome do arquivo especificado.

Parâmetros

zip_entry

A lista de entrada retornada pela zip_read().

Valor Retornado

O nome do diretório de entrada.

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User Contributed Notes 2 notes

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0
kevyn at opsone dot net
5 years ago
Big note for filename with accents.

Some Zip softwares encode accents with CP850.

So use iconv for keeping your accents SAFE !
up
0
leandro_dealmeida at hotmail dot com
11 years ago
If you want to get the real name of the file without the directory name, you can just use the function basename() as the follow:

<?
$zip_dir = "./import/";
$zip = zip_open($zip_dir."import.zip");
if ($zip) {
    while ($zip_entry = zip_read($zip)) {

        $file = basename(zip_entry_name($zip_entry));
        $fp = fopen($zip_dir.basename($file), "w+");
       
        if (zip_entry_open($zip, $zip_entry, "r")) {
            $buf = zip_entry_read($zip_entry, zip_entry_filesize($zip_entry));
            zip_entry_close($zip_entry);
        }
       
           fwrite($fp, $buf);
        fclose($fp);
       
        echo "The file ".$file." was extracted to dir ".$zip_dir."\n<br>";
    }
    zip_close($zip);
}
?>

Thefore you can extract files without concern with the directory that is set inside the zip source.

Remember to give write permission (w) on that directory.

Hello from Brazil.
Leandro
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