How to easy recalculate carry over points:
<?php
class DateIntervalEnhanced extends DateInterval {
public function recalculate()
{
$from = new DateTime;
$to = clone $from;
$to = $to->add($this);
$diff = $from->diff($to);
foreach ($diff as $k => $v) $this->$k = $v;
return $this;
}
}
$di = new DateIntervalEnhanced('PT3600S');
echo "Instead of " . $di->format('%h:%i:%s') . " it outputs " . $di->recalculate()->format('%h:%i:%s');
# output will be: "Instead of 0:0:3600 it outputs 1:0:0"
DateInterval::format
(PHP 5 >= 5.3.0, PHP 7)
DateInterval::format — Zaman aralığını biçimler
Açıklama
public string DateInterval::format
( string
$biçem
)Zaman aralığını biçimlendirir.
Değiştirgeler
-
biçem -
biçemdizgesinde tanınan karakterler aşağıda listelenmiştir. Her biçem karakterinin başına bir yüzde (%) işareti konmalıdır.Karakter Açıklama Örnek değerler % % iminin kendisi % Y Başına 0 getirilerek iki haneli yıl 01, 03 y 0 ile öncelenmeksizin yıl 1, 3 M Başına 0 getirilerek iki haneli ay 01, 03, 12 m 0 ile öncelenmeksizin ay 1, 3, 12 D Başına 0 getirilerek iki haneli ayın günü 01, 03, 31 d 0 ile öncelenmeksizin ayın günü 1, 3, 31 a Toplam gün sayısı 4, 18, 8123 H Başına 0 getirilerek iki haneli saat 01, 03, 23 h 0 ile öncelenmeksizin saat 1, 3, 23 I Başına 0 getirilerek iki haneli dakika 01, 03, 59 i 0 ile öncelenmeksizin dakika 1, 3, 59 S Başına 0 getirilerek iki haneli saniye 01, 03, 57 s 0 ile öncelenmeksizin saniye 1, 3, 57 R Negatifse "-", pozitifse "+" imi -, + r Negatifse "-", pozitifse boş dizge -,
Dönen Değerler
Biçimlendirilmiş zaman aralığını bir dizge olarak döndürür.
Notlar
Bilginize:
DateInterval::format() yöntemi ne zaman dizgelerinde ne de tarih bölümlerinde tehir edilen kısımları yeniden hesaplar. Bunun sebebi "32 gün" gibi büyük değerlerin olanaksız oluşudur. Olanaklı olsaydı böyle bir değer "1 ay 4 gün" ile "1 ay 1 gün" arasında bir değer olarak yorumlanabilirdi.
Örnekler
Örnek 1 - DateInterval örneği
<?php
$interval = new DateInterval('P2Y4DT6H8M');
echo $interval->format('%d gün');
?>
Yukarıdaki örneğin çıktısı:
4 gün
Örnek 2 - DateInterval ve büyük değerler
<?php
$interval = new DateInterval('P32D');
echo $interval->format('%d gün');
?>
Yukarıdaki örneğin çıktısı:
32 gün
Örnek 3 - DateInterval ve DateTime::diff() ile %a ve %d değiştiricileri
<?php
$january = new DateTime('2010-01-01');
$february = new DateTime('2010-02-01');
$interval = $february->diff($january);
// %a toplam gün sayısını çıktılar.
echo $interval->format('toplam %a gün')."\n";
// %d ise aya dahil olmayan gün sayısını çıktılar.
echo $interval->format('%m ay, %d gün');
?>
Yukarıdaki örneğin çıktısı:
toplam 31 gün 1 ay, 0 gün
add a note
User Contributed Notes 11 notes
glavic at gmail dot com ¶
4 years ago
balaclark at gmail dot com ¶
6 years ago
Be aware that your default timezone can sometimes alter the result of a diff so that the returned months/days are incorrect.
There is a bug report at: http://bugs.php.net/bug.php?id=52480
baptiste dot place at utopiaweb dot fr ¶
8 years ago
With php 5.3, DateTime is sweet !
Here is one quick example :
<?php
/**
* A sweet interval formatting, will use the two biggest interval parts.
* On small intervals, you get minutes and seconds.
* On big intervals, you get months and days.
* Only the two biggest parts are used.
*
* @param DateTime $start
* @param DateTime|null $end
* @return string
*/
public function formatDateDiff($start, $end=null) {
if(!($start instanceof DateTime)) {
$start = new DateTime($start);
}
if($end === null) {
$end = new DateTime();
}
if(!($end instanceof DateTime)) {
$end = new DateTime($start);
}
$interval = $end->diff($start);
$doPlural = function($nb,$str){return $nb>1?$str.'s':$str;}; // adds plurals
$format = array();
if($interval->y !== 0) {
$format[] = "%y ".$doPlural($interval->y, "year");
}
if($interval->m !== 0) {
$format[] = "%m ".$doPlural($interval->m, "month");
}
if($interval->d !== 0) {
$format[] = "%d ".$doPlural($interval->d, "day");
}
if($interval->h !== 0) {
$format[] = "%h ".$doPlural($interval->h, "hour");
}
if($interval->i !== 0) {
$format[] = "%i ".$doPlural($interval->i, "minute");
}
if($interval->s !== 0) {
if(!count($format)) {
return "less than a minute ago";
} else {
$format[] = "%s ".$doPlural($interval->s, "second");
}
}
// We use the two biggest parts
if(count($format) > 1) {
$format = array_shift($format)." and ".array_shift($format);
} else {
$format = array_pop($format);
}
// Prepend 'since ' or whatever you like
return $interval->format($format);
}
?>
kuzb ¶
7 years ago
Quick class to allow you to input a time in any unit, and have it recalculate in to different denominations (for example, seconds to hours, minutes and seconds):
<?php
class DateIntervalEnhanced extends DateInterval
{
/* Keep in mind that a year is seen in this class as 365 days, and a month is seen as 30 days.
It is not possible to calculate how many days are in a given year or month without a point of
reference in time.*/
public function to_seconds()
{
return ($this->y * 365 * 24 * 60 * 60) +
($this->m * 30 * 24 * 60 * 60) +
($this->d * 24 * 60 * 60) +
($this->h * 60 * 60) +
($this->i * 60) +
$this->s;
}
public function recalculate()
{
$seconds = $this->to_seconds();
$this->y = floor($seconds/60/60/24/365);
$seconds -= $this->y * 31536000;
$this->m = floor($seconds/60/60/24/30);
$seconds -= $this->m * 2592000;
$this->d = floor($seconds/60/60/24);
$seconds -= $this->d * 86400;
$this->h = floor($seconds/60/60);
$seconds -= $this->h * 3600;
$this->i = floor($seconds/60);
$seconds -= $this->i * 60;
$this->s = $seconds;
}
}
// Example usage
$di = new DateIntervalEnhanced('PT3600S');
$di->recalculate();
// outputs 1:0:0 instead of 0:0:3600 now!
echo $di->format('%H:%i:%s');
?>
kulakov74 at yandex dot ru ¶
4 years ago
glavic, this does not eliminate the problem of "32 days", if you use your class for normalizing intervals of days, because the result will depend on the current month which is used for DateTime by default. And if that does not matter (because the interval is not that long) you don't have to call diff() to get the same recalculation:
$DT=new DateTime('0000-01-01'); $DT->add($oInt); echo($DT->format('Y-m-d H:i:s'));
zell1285 at gmail dot com ¶
2 years ago
I was doing this: $endDate->diff($startDate)->format('%a’)
to get the number of the days between the end date and the start date. This is correct, but if I subtract 2016-04-23 00:00:00 to 2016-04-02 09:39:01 (note that in only one of the datetime values we have the time) the result is 21 (and not 20 as I expected). This is because the result of the diff is 20 days AND 14 hours, 20 mins and 59 secs. If you use the %a to get the days from a dateinterval, it will round the days (and if the hours are greater than 12, it will round days up).
So, DO NOT USE the %a formatting to get the difference in days between 2 datetime unless you are 100% sure that both the Datetime objects don't have the time.
You can solve easily with $valueDate->diff($startDate)->days that will return only the days in a dateinterval (without the fuc***g rounding).
thflori at gmail dot com ¶
2 months ago
The fact that $dateTime->diff(new DateTime()) returns a DateInterval and the interval is something where you don't get any useful number is somebit annoying.
<?php
$longTimeAgo = new DateTime('1999-10-23 16:29:21')
// easy workaround:
var_dump((float)$longTimeAgo->format('U.u') - (float)(new DateTime())->format('U.u'));
// or in seconds if you are not that precise
var_dump($longTimeAgo->getTimestamp() - (new DateTime())-getTimestamp());
// this function can help you if you want to stick with DateInterval objects
function interval_to_float(DateInterval $interval) {
$seconds = 0;
$days = (int)$interval->days;
if ($days === false || $days === -99999) { //php5.5 compatibility
$days = floor($interval->y * 365.2525);
$days += $interval->m * 30; // that's totally inaccurate
// or: $days += floor($interval->m * 30.4167);
$days += $interval->d;
}
return ($days * 24 * 60 * 60 +
$interval->h * 60 * 60 +
$interval->i * 60 +
$interval->s) * ($interval->invert ? -1 : 1) +
$interval->f / 1000000; // you may wonder but they are negativ and not affected by invert
}
me at unreal4u dot com ¶
2 years ago
If you want the difference between two timestamps in HOURS, do not forget to add the number of days:
<?php
// Bad example
$lastEntryDate = new \DateTime('2015-05-23 00:10:20', new \DateTimeZone('UTC'));
$dateDifference = $lastEntryDate->diff(new \DateTime('2015-05-25 02:35:45', new \DateTimeZone('UTC')));
var_dump((int)$dateDifference->format('%H'));
// Returns 2
if ((int)$dateDifference->format('%H') > 24) {
// Will never enter here, (int)$dateDifference->format('%H') will contain 0-23 ONLY
}
?>
Instead, sum the days:
<?php
// Bad example
$lastEntryDate = new \DateTime('2015-05-23 00:10:20', new \DateTimeZone('UTC'));
$dateDifference = $lastEntryDate->diff(new \DateTime('2015-05-25 02:35:45', new \DateTimeZone('UTC')));
var_dump(($dateDifference->days * 24 + (int)$dateDifference->format('%H')));
// Returns 50
if (($dateDifference->days * 24 + (int)$dateDifference->format('%H')) > 24) {
// Will enter here now :)
}
?>
Hope this saves somebody some time and possible bugs :)
pankajs7590 at gmail dot com ¶
11 months ago
public function getTotalInterval($interval, $type){
switch($type){
case 'years':
return $interval->format('%Y');
break;
case 'months':
$years = $interval->format('%Y');
$months = 0;
if($years){
$months += $years*12;
}
$months += $interval->format('%m');
return $months;
break;
case 'days':
return $interval->format('%a');
break;
case 'hours':
$days = $interval->format('%a');
$hours = 0;
if($days){
$hours += 24 * $days;
}
$hours += $interval->format('%H');
return $hours;
break;
case 'minutes':
$days = $interval->format('%a');
$minutes = 0;
if($days){
$minutes += 24 * 60 * $days;
}
$hours = $interval->format('%H');
if($hours){
$minutes += 60 * $hours;
}
$minutes += $interval->format('%i');
return $minutes;
break;
case 'seconds':
$days = $interval->format('%a');
$seconds = 0;
if($days){
$seconds += 24 * 60 * 60 * $days;
}
$hours = $interval->format('%H');
if($hours){
$seconds += 60 * 60 * $hours;
}
$minutes = $interval->format('%i');
if($minutes){
$seconds += 60 * $minutes;
}
$seconds += $interval->format('%s');
return $seconds;
break;
case 'milliseconds':
$days = $interval->format('%a');
$seconds = 0;
if($days){
$seconds += 24 * 60 * 60 * $days;
}
$hours = $interval->format('%H');
if($hours){
$seconds += 60 * 60 * $hours;
}
$minutes = $interval->format('%i');
if($minutes){
$seconds += 60 * $minutes;
}
$seconds += $interval->format('%s');
$milliseconds = $seconds * 1000;
return $milliseconds;
break;
default:
return NULL;
}
}
pekka at gmx dot de ¶
7 years ago
Note that `%a` is broken on Windows on VC6 builds. http://bugs.php.net/bug.php?id=51184
beowolve at gmail dot com ¶
4 years ago
German Version of formatDateDiff:
function formatDateDiff($start, $end=null) {
if(!($start instanceof DateTime)) {
$start = new DateTime($start);
}
if($end === null) {
$end = new DateTime();
}
if(!($end instanceof DateTime)) {
$end = new DateTime($start);
}
$interval = $end->diff($start);
$doPlural = function($nb,$str){
if ($nb > 1) {
switch ($str) {
case 'Jahr':
case 'Monat':
case 'Tag':
return $str.'e';
case 'Stunde':
case 'Minute':
case 'Sekunde':
return $str.'n';
}
} else
return $str;
}; // adds plurals
$format = array();
if($interval->y !== 0) {
$format[] = "%y ".$doPlural($interval->y, "Jahr");
}
if($interval->m !== 0) {
$format[] = "%m ".$doPlural($interval->m, "Monat");
}
if($interval->d !== 0) {
$format[] = "%d ".$doPlural($interval->d, "Tag");
}
if($interval->h !== 0) {
$format[] = "%h ".$doPlural($interval->h, "Stunde");
}
if($interval->i !== 0) {
$format[] = "%i ".$doPlural($interval->i, "Minute");
}
if($interval->s !== 0) {
$format[] = "%s ".$doPlural($interval->s, "Sekunde");
}
if(count($format)==0 || (count($format)==1 && $interval->s !== 0)) {
return "weniger als eine Minute";
}
// We use the two biggest parts
if(count($format) > 1) {
$format = array_shift($format).", ".array_shift($format);
} else {
$format = array_pop($format);
}
// Prepend 'since ' or whatever you like
return $interval->format($format);
}
