PHP 8.3.4 Released!

dbase_create

(PHP 5 < 5.3.0, dbase 5, dbase 7)

dbase_createCreates a database

说明

dbase_create(string $path, array $fields, int $type = DBASE_TYPE_DBASE): resource

dbase_create() creates a dBase database with the given definition. If the file already exists, it is not truncated. dbase_pack() can be called to force truncation.

注意:

此函数受 open_basedir 影响。

参数

path

The path of the database. It can be a relative or absolute path to the file where dBase will store your data.

fields

An array of arrays, each array describing the format of one field of the database. Each field consists of a name, a character indicating the field type, and optionally, a length, a precision and a nullable flag. The supported field types are listed in the introduction section.

注意:

The fieldnames are limited in length and must not exceed 10 chars.

type

The type of database to be created. Either DBASE_TYPE_DBASE or DBASE_TYPE_FOXPRO.

返回值

Returns a database resource if the database is successfully created, or false if an error occurred.

更新日志

版本 说明
dbase 7.0.0 The type parameter has been added.
dbase 7.0.0 The return value is now a resource instead of an int.

示例

示例 #1 Creating a dBase database file

<?php

// database "definition"
$def = array(
array(
"date", "D"),
array(
"name", "C", 50),
array(
"age", "N", 3, 0),
array(
"email", "C", 128),
array(
"ismember", "L")
);

// creation
if (!dbase_create('/tmp/test.dbf', $def)) {
echo
"Error, can't create the database\n";
}

?>

参见

add a note

User Contributed Notes 1 note

up
-2
denvolin
6 years ago
There is no third param in this function.
According to latest pecl package "dbase-pecl-php7", there are only 2 params.
To Top