getmyuid

(PHP 4, PHP 5, PHP 7, PHP 8)

getmyuid — 获取 PHP 脚本所有者的 UID

说明

getmyuid(): int|false

获取当前脚本的用户 ID。

参数

此函数没有参数。

返回值

返回当前脚本的用户 ID，或在错误时返回 false。

参见

getmygid() - 获取当前 PHP 脚本拥有者的 GID
getmypid() - 获取 PHP 进程的 ID
get_current_user() - 获取当前 PHP 脚本所有者名称
getmyinode() - 获取当前脚本的索引节点（inode）
getlastmod() - 获取页面最后修改的时间

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用户贡献的备注 2 notes

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bozo_z_clown at yahoo dot com ¶

17 years ago

Note that this function really does what the description says, it returns the numeric user id of the user who *owns the file* containing the current script not the effective user id of user *running* the current script.  Most applications will want the latter which is provided by posix_getuid().

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-1

divinity76+spam at gmail dot com ¶

2 years ago

warning, at least 7.4-8.1 returns the owner of the initial entrypoint file rather the currently executing file,
meaning, if you have a.php owned by 1 containing 
<?php var_dump(getmyuid());require_once("b.php"); ?>
and b.php owned by 2 containing 
<?php var_dump(getmyuid());require_once("a.php"); ?>
running "php a.php" will get you int(1) int(1), and running "php b.php" will get you int(2) int(2), you won't get "int(1) int(2)"