PHP 5.4.36 Released

pg_field_name

(PHP 4 >= 4.2.0, PHP 5)

pg_field_name返回字段的名字

说明

string pg_field_name ( resource $result , int $field_number )

pg_field_name() 返回给定 PostgreSQL result 资源中的 field_number 所代表的字段名。字段编号从 0 开始。

Example #1 获取字段信息

<?php
    $dbconn 
pg_connect("dbname=publisher") or die("Could not connect");
    
$res pg_query($dbconn"select * from authors where author = 'Orwell'");
    
$i pg_num_fields($res);
    for (
$j 0$j $i$j++) {
        echo 
"column $j\n";
        
$fieldname pg_field_name($res$j);
        echo 
"fieldname: $fieldname\n";
        echo 
"printed length: ".pg_field_prtlen($res$fieldname)." characters\n";
        echo 
"storage length: ".pg_field_size($res$j)." bytes\n";
        echo 
"field type: ".pg_field_type($res$j)." \n\n";
}
?>

上例的输出如下:

column 0
fieldname: author
printed length: 6 characters
storage length: -1 bytes
field type: varchar

column 1
fieldname: year
printed length: 4 characters
storage length: 2 bytes
field type: int2

column 2
fieldname: title
printed length: 24 characters
storage length: -1 bytes
field type: varchar

Note:

本函数以前的名字为 pg_fieldname()

参见 pg_field_num()

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User Contributed Notes 2 notes

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0
Anonymous
10 years ago
In fact you can extract the size of the varchar field, by simply sending the following query:
"select a.atttypmod,a.attrelid from pg_attribute as a, pg_class as c where c.relname='$table' AND a.attrelid=c.oid AND a.attname='$field'"

here is a simple function that does that:

function get_field_size($table, $field, $link) {
               
        $result = pg_query($link, "select a.atttypmod,a.attrelid from pg_attribute as a, pg_class as c where c.relname='$table' AND a.attrelid=c.oid AND a.attname='$field'");                
       
        $data = pg_fetch_object($result);
       
        return ($data->atttypmod - 4);       
   
}

returned value is a size of a given field (also varchar)
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0
ccasal at compuserve dot com
13 years ago
The pg_fieldname function only returns the unqualified name from the select statement. example:

select c.name, con.name from customer c, contacts con where con.customer_id = c.id;

pg_fieldname will return "name" for both fields instead of c.name and con.name.

This is a PostgreSQL limitation, not a PHP limitation.

if you need different field names you should use :

select c.name as customer_name, con.name as contact_name from customer c, contacts con where con.customer_id = c.id;

then pg_fieldname will return "customer_name" and "contact_name"
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