strval

    (PHP 4, PHP 5, PHP 7, PHP 8)

    strval — Ermittelt die String-Repräsentation einer Variable

    Beschreibung

    strval(mixed $value): string

    Gibt die String-Repräsentation einer Variablen zurück. Lesen Sie die Dokumentation über den Typ string, um weitere Informationen über das Konvertieren in Strings zu erhalten.

    Diese Funktion führt keine Formatierung auf dem zurückgegebenen Wert durch. Wenn Sie nach einem Weg suchen, einen numerischen Wert als String zu formatieren, lesen Sie bitte die Dokumentation zu sprintf() oder number_format().

    Parameter-Liste

    value

    Die nach string zu konvertierende Variable.

    var darf jeder skalare Datentyp oder null sein oder ein Objekt, das die Methode __toString implementiert. strval() kann nicht auf Arrays oder Objekte angewandt werden, welche nicht die Methode __toString implementieren.

    Rückgabewerte

    Die String-Repräsentation des Wertes von value.

    Beispiele

    Beispiel #1 strval()-Beispiel für die Verwendung der magischen __toString-Methode

    <?php
    class StrValTest
    {
    public function     __toString()
    {
    return     __CLASS__;
    }
    }

    // Gibt 'StrValTest' aus
    echo strval(new StrValTest);
    ?>

    Siehe auch

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    User Contributed Notes 7 notes

    up
    19
    Mark Clements
    8 years ago
    Some notes about how this function has changed over time, with regards the following statement:

    > You cannot use strval() on arrays or on objects that
    > do not implement the __toString() method.

    == Arrays ==

    In PHP 5.3 and below, strval(array(1, 2, 3)) would return the string "Array" without any sort of error occurring.

    From 5.4 and above, the return value is unchanged but you will now get a notice-level error: "Array to string conversion".

    == Objects ==

    For objects that do not implement __toString(), the behaviour has varied:

    PHP 4: "Object"
    PHP 5 < 5.2: "Object id #1" (number obviously varies)
    PHP >= 5.2: Catchable fatal error: Object of class X could not be converted to string
    up
    17
    Hayley Watson
    17 years ago
    As of PHP 5.2, strval() will return the string value of an object, calling its __toString() method to determine what that value is.
    up
    19
    Tom Nicholson
    20 years ago
    If you want to convert an integer into an English word string, eg. 29 -> twenty-nine, then here's a function to do it.

    Note on use of fmod()
    I used the floating point fmod() in preference to the % operator, because % converts the operands to int, corrupting values outside of the range [-2147483648, 2147483647]

    I haven't bothered with "billion" because the word means 10e9 or 10e12 depending who you ask.

    The function returns '#' if the argument does not represent a whole number.

    <?php
    $nwords     = array( "zero", "one", "two", "three", "four", "five", "six", "seven",
    "eight", "nine", "ten", "eleven", "twelve", "thirteen",
    "fourteen", "fifteen", "sixteen", "seventeen", "eighteen",
    "nineteen", "twenty", 30 => "thirty", 40 => "forty",
    50 => "fifty", 60 => "sixty", 70 => "seventy", 80 => "eighty",
    90 => "ninety" );

    function     int_to_words($x) {
    global     $nwords;

    if(!    is_numeric($x))
    $w = '#';
    else if(    fmod($x, 1) != 0)
    $w = '#';
    else {
    if(    $x < 0) {
    $w = 'minus ';
    $x = -$x;
    } else
    $w = '';
    // ... now $x is a non-negative integer.

    if($x < 21) // 0 to 20
    $w .= $nwords[$x];
    else if(    $x < 100) { // 21 to 99
    $w .= $nwords[10 * floor($x/10)];
    $r = fmod($x, 10);
    if(    $r > 0)
    $w .= '-'. $nwords[$r];
    } else if(    $x < 1000) { // 100 to 999
    $w .= $nwords[floor($x/100)] .' hundred';
    $r = fmod($x, 100);
    if(    $r > 0)
    $w .= ' and '. int_to_words($r);
    } else if(    $x < 1000000) { // 1000 to 999999
    $w .= int_to_words(floor($x/1000)) .' thousand';
    $r = fmod($x, 1000);
    if(    $r > 0) {
    $w .= ' ';
    if(    $r < 100)
    $w .= 'and ';
    $w .= int_to_words($r);
    }
    } else {     // millions
    $w .= int_to_words(floor($x/1000000)) .' million';
    $r = fmod($x, 1000000);
    if(    $r > 0) {
    $w .= ' ';
    if(    $r < 100)
    $word .= 'and ';
    $w .= int_to_words($r);
    }
    }
    }
    return     $w;
    }

    ?>

    Usage:
    <?php
    echo 'There are currently '. int_to_words($count) . ' members logged on.';
    ?>
    up
    13
    php at ianco dot co dot uk
    19 years ago
    I can't help being surprised that

    (string)"0" == (string)"0.00"

    evaluates to true. It's the same with strval and single quotes.
    === avoids it.

    Why does it matter? One of my suppliers, unbelievably, uses 0 to mean standard discount and 0.00 to mean no discount in their stock files.
    up
    9
    kendsnyder+phpnet at gmail dot com
    17 years ago
    The only way to convert a large float to a string is to use printf('%0.0f',$float); instead of strval($float); (php 5.1.4).

    // strval() will lose digits around pow(2,45);
    echo pow(2,50); // 1.1258999068426E+015
    echo (string)pow(2,50); // 1.1258999068426E+015
    echo strval(pow(2,50)); // 1.1258999068426E+015

    // full conversion
    printf('%0.0f',pow(2,50)); // 112589906846624
    echo sprintf('%0.0f',pow(2,50)); // 112589906846624
    up
    -1
    NyctoFixer at gmail dot com
    17 years ago
    As of PHP 5.1.4 (I have not tested it in later versions), the strval function does not attempt to invoke the __toString method when it encounters an object. This simple wrapper function will handle this circumstance for you:

    <?

    /**
    * Returns the string value of a variable
    *
    * This differs from strval in that it invokes __toString if an object is given
    * and the object has that method
    */
    function stringVal ($value)
    {
    // We use get_class_methods instead of method_exists to ensure that __toString is a public method
    if (is_object($value) && in_array("__toString", get_class_methods($value)))
    return strval($value->__toString());
    else
    return strval($value);
    }

    ?>
    up
    -1
    Steve Ball
    19 years ago
    It seems that one is being treated as an unsigned large int (32 bit), and the other as a signed large int (which has rolled over/under).

    2326201276 - (-1968766020) = 4294967296.
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