ArrayIterator::getArrayCopy

(PHP 5, PHP 7, PHP 8)

ArrayIterator::getArrayCopy — Obtener copia de un array

Descripción

public ArrayIterator::getArrayCopy(): array

Obtiene una copia de un array.

Advertencia

Esta función no está documentada actualmente, solamente se encuentra disponible la lista de parámetros.

Parámetros

Esta función no tiene parámetros.

Valores devueltos

Una copia de un array, o un array de las propiedades públicas si ArrayIterator hace referencia a un objeto.

Ver también

ArrayIterator::valid() - Comprueba si un array contiene más entradas

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User Contributed Notes 2 notes

down

irvine L ¶

6 years ago

Just in case some of you out there do NOT know this: 

(a). 'getArrayCopy()', returns a copy of the ORIGINAL array - iterator object. Therefore, using (for example) 'LimitIterator' on an array-object, and then calling 'getArrayCopy' afterwards, might not return the current (adjusted) object. 

(b). Instead, use the 'iterator_to_array' function, in order to access, or return, the current state of the array-object-iterator (whatever). Using the example above (in '(a)'); passing the 'LimitIterator' object into 'iterator_to_array', should return the CURRENT, and NOT ORIGINAL state of your array (iterator object).

down

lenye01 at gmail dot com ¶

13 years ago

the difference of this method and the direct assign the object to a value is as follows:

<?php
$b = array('name'=>'mengzhi','age'=>'12','city'=>'shanghai');
$a = new ArrayIterator($b);
$a->append(array('home'=>'china','work'=>'developer'));
$c = $a->getArrayCopy();
var_dump($a);
var_dump($c);
?>
result:
object(ArrayIterator)#1 (1) { ["storage":"ArrayIterator":private]=> array(4) { ["name"]=> string(7) "mengzhi" ["age"]=> string(2) "12" ["city"]=> string(8) "shanghai" [0]=> array(2) { ["home"]=> string(5) "china" ["work"]=> string(9) "developer" } } } 

array(4) { ["name"]=> string(7) "mengzhi" ["age"]=> string(2) "12" ["city"]=> string(8) "shanghai" [0]=> array(2) { ["home"]=> string(5) "china" ["work"]=> string(9) "developer" } }

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