PHP Conference Nagoya 2025

ArrayObject::offsetUnset

(PHP 5, PHP 7, PHP 8)

ArrayObject::offsetUnsetDestruye el valor para el índice especificado

Descripción

public ArrayObject::offsetUnset(mixed $index): void

Destruir el valor para el índice especificado.

Parámetros

index

El índice a ser destruido.

Valores devueltos

No devuelve ningún valor.

Ejemplos

Ejemplo #1 Ejemplo de ArrayObject::offsetUnset()

<?php
$arrayobj
= new ArrayObject(array(0=>'cero',2=>'dos'));
$arrayobj->offsetUnset(2);
var_dump($arrayobj);
?>

El resultado del ejemplo sería:

object(ArrayObject)#1 (1) {
  [0]=>
  string(4) "cero"
}

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User Contributed Notes 2 notes

up
3
pvenakis at efront dot gr
16 years ago
When traversing recursively nested arrays using an RecursiveIteratorIterator, you cannot offsetUnset() or offsetSet() sub-array values, unless they are *all* declared as ArrayObject.
up
0
oalexandrino at yahoo dot com dot br
17 years ago
Be careful when you are working with collections. This method works with the reference of an array instead of its retrieved value.

So, you can do a mistake.

In order to understand have a look at code as follow:

<?php
class Employee
{
public function
__construct()
{
}
}

class
Company
{
private
$arrEmployee;

public function
__construct()
{
}

public function
AddEmployee(Employee $oEmployee)
{
$this->arrEmployee[] = $oEmployee;

}

public function
getEmployeeList()
{
return
$this->arrEmployee;

}

}
?>

<?php

// first, creates the Company object
$oCompany = new Company();

// second, add 10 elements in
foreach( range(0, 9) as $index )
{
$oCompany->AddEmployee( new Employee() );
}

// get them
$arrEmployee = $oCompany->getEmployeeList();

// creates an ArrayObject from "$arrEmployee"
$arrayobject = new ArrayObject($arrEmployee);

// unsets its firt five elements
foreach( range(0, 4) as $index )
{
$arrayobject->offsetUnset($index);
}

// get them again
$arrEmployee = $oCompany->getEmployeeList();

// it shows just 5 elements, they were removed as reference via "offsetUnset" method
print_r($arrEmployee) ;

?>
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