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    imageopenpolygon

    (PHP 7 >= 7.2.0, PHP 8)

    imageopenpolygon — Draws an open polygon

    Descripción

    Signature as of PHP 8.0.0 (not supported with named arguments)

    imageopenpolygon(GdImage $image, array $points, int $color): bool

    Alternative signature (deprecated as of PHP 8.1.0)

    imageopenpolygon(
        GdImage $image,
        array $points,
        int $num_points,
        int $color
    ): bool

    imageopenpolygon() draws an open polygon on the given image. Contrary to imagepolygon(), no line is drawn between the last and the first point.

    Parámetros

    image

    Un recurso image, es devuelto por una de las funciones de creación de imágenes, como imagecreatetruecolor().

    points

    An array containing the polygon's vertices, e.g.:

    points[0] = x0
    points[1] = y0
    points[2] = x1
    points[3] = y1

    num_points

    Total number of points (vertices), which must be at least 3.

    If this parameter is omitted as per the second signature, points must have an even number of elements, and num_points is assumed to be count($points)/2.
    color

    Un identificador de color creato con imagecolorallocate().

    Valores devueltos

    Devuelve true en caso de éxito o false en caso de error.

    Historial de cambios

    Versión Descripción
    8.1.0 The parameter num_points has been deprecated.
    8.0.0 image expects a GdImage instance now; previously, a valid gd resource was expected.

    Ejemplos

    Ejemplo #1 imageopenpolygon() example

    <?php
    // Create a blank image
    $image = imagecreatetruecolor(400, 300);

    // Allocate a color for the polygon
    $col_poly = imagecolorallocate($image, 255, 255, 255);

    // Draw the polygon
    imageopenpolygon($image, array(
    0, 0,
    100, 200,
    300, 200
    ),
    3,
    $col_poly);

    // Output the picture to the browser
    header('Content-type: image/png');

    imagepng($image);
    imagedestroy($image);
    ?>

    El resultado del ejemplo sería algo similar a:

    Output of example : imageopenpolygon()

    Ver también

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    User Contributed Notes 1 note

    up
    0
    marco at oostende dot nl
    6 years ago
    In case you want to use an open polygon but are stuck with a PHP version prior to 7.2, a solution may be to 'backplot' your array to its original start. Say you have an array of pixels (below seperated by commas)

    <?php
    $arr     = array();
    for (    $i = 0; $i < count($pixels); $i++) {
    $pixel = explode(',', $pixels[$i]);
    if ((    $pixel[0] > 0) && ($pixel[1] > 0)) {
    $arr[] = $pixel[0];
    $arr[] = $pixel[1];
    }
    }
    imagepolygon($im, $arr, (count($arr) / 2), $otcolor);
    ?>

    you can replace this by something like

    <?php
    $arr     = array();
    for (    $i = 0; $i < count($pixels); $i++) {
    $pixel = explode(',', $pixels[$i]);
    $arr[] = $pixel[0];
    $arr[] = $pixel[1];
    }
    // imageopenpolygon($im, $arr, (count($arr) / 2), $otcolor) is not possible, so...
    for ($i = (count($pixels)-1); $i >= 0; $i--) {
    $pixel = explode(',', $pixels[$i]);
    $arr[] = $pixel[0];
    $arr[] = $pixel[1];
    }
    imagepolygon($im, $arr, (count($arr) / 2), $otcolor);
    ?>
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