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    jdtofrench

    (PHP 4, PHP 5, PHP 7, PHP 8)

    jdtofrench — ユリウス積算日をフランス革命暦(共和暦)に変換する

    説明

    jdtofrench(int $julian_day): string

    ユリウス積算日をフランス革命暦に変換します。

    パラメータ

    julian_day

    ユリウス積算日を表す整数値。

    戻り値

    フランス革命暦の日付を "月/日/年" 形式の文字列で返します。

    参考

    • frenchtojd() - フランス革命暦をユリウス積算日に変換する
    • cal_from_jd() - ユリウス積算日からサポートされるカレンダーに変換する

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    User Contributed Notes 4 notes

    up
    1
    pieterc dot depraetere at ugent dot be
    14 years ago
    If you want to convert a date later than September 22nd 1806, you could use this function. It's a bit crude and due to the fact the original function terminates in the middle of 1806, it uses 1805 as it's 'terminus post quem'.
    <?php
    function extended_jdtofrench ($juliandate) {
    if (    $juliandate > 2380945) {
    // jdtofrench () only accepts dates until september 1806
    $gregorian_date = jdtogregorian ($juliandate);
    $temp = explode ('/', $gregorian_date);
    $year = $temp[2];
    $juliandate = gregoriantojd ($temp[0], $temp[1], 1805);
    $republican_date = jdtofrench ($juliandate);
    $republican_date = explode ('/', $republican_date);
    $diff = $year - 1805;
    $republican_date[2] = $republican_date[2] + $diff;
    } else {
    $republican_date = jdtofrench ($juliandate);
    }
    return     $republican_date;
    }
    ?>
    up
    1
    squenz at titania dot bottoms-dream dot de
    18 years ago
    Here is a small piece of code to obtain the string data for a correctly converted gregorian date:

    <?php
    $arDateFrench     = gregorian2FrenchDateArray(11, 9, 1799) ;

    echo     $arDateFrench[1] . " " . $arDateFrench[0] . " " . $arDateFrench[2] ;

    /* the output will be:
    18 Brumaire VIII

    */

    function gregorian2FrenchDateArray($m, $d, $y)
    {

    $julian_date = gregoriantojd($m, $d, $y);
    $french = jdtofrench($julian_date);
    if(    $french == "0/0/0")
    return     "" ;

    $arD = split("/", $french) ;

    // get the month name
    $monthname = FrenchMonthNames($arD[0]) ;

    /* convert the year number to roman digits (as most historians do and documents of the time did */
    $stryear = decrom($arD[2]) ;
    return array(    $monthname, $arD[1], $stryear ) ;
    }

    function     FrenchMonthNames($mo)
    {
    /* The names have been invented by Fabre d'Églantine, a second or rather third rank poet
    of primarily pastoral poems, with each name referring to the respective period in the agricultural year; e.g. "Vendémiaire" (approx. September) is derived from "vendange" ("harvest"), "Brumaire" (Ocotober/November) from "brume" ("fog") and so on ... */


    $arMo = array("Vendémiaire",
    "Brumaire",
    "Frimaire",
    "Nivôse",
    "Pluviôse",
    "Ventôse",
    "Germinal",
    "Floréal",
    "Prairial",
    "Messidor",
    "Thermidor",
    "Fructidor",
    "Sansculottide") ;

    if(    $mo < count($arMo)+1)
    return     $arMo[$mo-1] ;

    }

    function     decrom($dec){
    $digits=array(
    1 => "I",
    4 => "IV",
    5 => "V",
    9 => "IX",
    10 => "X",
    40 => "XL",
    50 => "L",
    90 => "XC",
    100 => "C",
    400 => "CD",
    500 => "D",
    900 => "CM",
    1000 => "M"
    );
    krsort($digits);
    $retval="";
    foreach(    $digits as $key => $value){
    while(    $dec>=$key){
    $dec-=$key;
    $retval.=$value;
    }
    }
    return     $retval;
    }
    ?>
    up
    0
    popy-dev
    6 years ago
    Also note that there are few date converters handling French calendar outside the jdtofrench covered range.
    up
    -3
    serged at noos dot fr
    21 years ago
    Very limited function:

    (extract from source of 4.3.3)
    These routines only convert dates in years 1 through 14 (Gregorian dates 22 September 1792 through 22 September 1806). This more than covers the period when the calendar was in use.

    Pour les fran?ais :
    Ces routines ne converitssent les dates que de l'an 1 ? 14 (du 22 septembre 1792 au 22 septembre 1806). Cela couvre plus que la p?riode pendant laquelle le calendrier ? ?t? utilis?.
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