date_sub

(PHP 5 >= 5.3.0)

date_subAlias de DateTime::sub()

Description

Cette fonction est un alias de : DateTime::sub()

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User Contributed Notes 3 notes

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2
vitkor dot kruglikov at gmail dot com
2 months ago
It can be unclear for someone how to use this function.
Here is the example:

$date=date_create("2013-03-15");
date_sub($date,date_interval_create_from_date_string("40 days"));
echo date_format($date,"Y-m-d");
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-1
Thomas LEDUC
6 months ago
To glue to the OOP, it's better to use it with DateInterval::createFromDateString

<?php
$dateB
= new DateTime('2020-12-20');
$dateA = $dateB->sub(DateInterval::createFromDateString('10 days'));
?>

more detail here :
<?php
public static function createFromDateString ($time) {}
?>
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-4
Jonathan Poissant
4 years ago
You cannot replace date_sub('2000-01-20') by DateTime::sub('2000-01-20') because DateTime::sub is not static. You have to create the DateTime object first.

Example:

<?php $dateA = date_sub('2000-01-20', date_interval_create_from_date_string('10 days')); ?>

will be replace by
<?php
$dateB
= new DateTime('2000-01-20');
$dateA = $dateB->sub(date_interval_create_from_date_string('10 days'));
?>
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