PHP 5.5.16 is released

ftp_site

(PHP 4, PHP 5)

ftp_siteInvia al server un comando SITE

Descrizione

bool ftp_site ( resource $ftp_stream , string $cmd )

La funzione ftp_site() invia al server FTP il comando specificato dal parametro cmd. I comandi SITE non sono standardizzati e sono diversi da server a server. They are Sono utili per operare, ad esempio, sui permessi dei file o sull'appartenenza a gruppi.

Example #1 Invio di un comando SITE ad un server ftp

<?php
/* Connessione al server FTP */
$conn ftp_connect('ftp.example.com');
if (!
$conn) die('Impossibile connettersi a ftp.example.com');

/* Collegarsi come "user" con password "pass" */
if (!ftp_login($conn'user''pass')) die('Errore nel collegamento come "user" a ftp.example.com');

/* Invio: comando "SITE CHMOD 0600 /home/user/privatefile" al server ftp */
if (ftp_site($conn'CHMOD 0600 /home/user/privatefile')) {
   echo 
"Comando eseguito correttamente.\n";
} else {
   die(
'Errore nell'esecuzione del comando.');
}
?>

Restituisce TRUE in caso di successo, FALSE in caso di fallimento.

Vedere anche: ftp_raw()

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User Contributed Notes 6 notes

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1
Marc
11 years ago
Use ftp_raw() (PHP 5+) instead of ftp_site() if you need the results of the remote command.
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1
to at mail dot isec dot pt
11 years ago
Hya,
  Recently I had to work with FTP over PHP, since I didn't found any help about this topic I decided to post this here. If you need to chmod one file, I tested this on the ftp server using a ftp client and after I knew that the ftp server supported chmod I used the following commands:
$upload = ftp_put($conn_id, "/home/to/public_html/index.php", $source_file, FTP_ASCII);
$ch=@ftp_site($conn_id,"chmod 755 /home/to/public_html/index.php");

Hope this help!

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1
Anonymous
13 years ago
site commands are extra-functionality provided by some ftp servers, and depend on the server :
e.g. trying "ftp> site help" (with an interactive ftp client) on a proftp server would give :

214-The following SITE extensions are recognized:
RATIO -- show all ratios in effect
The following SITE commands are recognized (* =>'s unimplemented).
HELP    CHMOD
214 Direct comments to admin@ftp.blahblah.fr

while with wu-ftpd on can typically get :

214-The following SITE commands are recognized (* =>'s unimplemented).
   UMASK           GROUP           INDEX           GROUPS
   IDLE            GPASS           EXEC            CHECKMETHOD
   CHMOD           NEWER           ALIAS           CHECKSUM
   HELP            MINFO           CDPATH                  
214 blabla

Unfortunately, ftp_site only returns true or false. It would be nice to have a way to get the server's reply in full : ftp_site('help') return 1, which pretty much useless.

Hope that helps,

Ivan
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0
www.bossftp.com
5 years ago
To send a SITE command and get the result, you can try this:

<?php
function ftpsite($conn, $cmd) {
    return
ftp_raw($conn, "SITE $cmd");
}
?>
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0
webmaster at beezm dot net
11 years ago
I wrote some functions for an ftp server for windows called GuildFTPd.

Here they are, they are pretty much so self explanitory:
<?
function guildftpd_adduser($ftp_stream,$group,$username,$password){
    ftp_site($ftp_stream,"SITE ADDUSER $group $username $password");
}
function guildftpd_addgroup($ftp_stream,$groupname){
    ftp_site($ftp_stream,"SITE ADDGROUP $groupname");
}
function guildftpd_deluser($ftp_stream,$username){
    ftp_site($ftp_stream,"SITE DELUSER $username");
}
function guildftpd_addpath($ftp_stream,$username,$path,$vpath){
    ftp_site($ftp_stream,"SITE ADDPATH $username $path $vpath");
}
function guildftpd_delpath($ftp_stream,$username,$path,$vpath){
    ftp_site($ftp_stream,"SITE DELPATH $username $path $vpath");
}
function guildftpd_anon($ftp_stream){
    ftp_site($ftp_stream,"SITE ANON ALLOW");
}
function guildftpd_anond($ftp_stream){
    ftp_site($ftp_stream,"SITE ANON DENY");
}
function guildftpd_chpass($ftp_stream,$user,$pass){
    ftp_site($ftp_stream,"SITE CHPASS $user $pass");
}
function guildftpd_disable($ftp_stream,$user){
    ftp_site($ftp_stream,"SITE DISABLE $user");
}
function guildftpd_enable($ftp_stream,$user){
    ftp_site($ftp_stream,"SITE ENABLE $user");
}
function guildftpd_who($ftp_stream){
    $who = ftp_site($ftp_stream,"SITE WHO");
}
function guildftpd_kick($ftp_stream,$user);
    ftp_site($ftp_stream,"SITE KICK $user");
}
function guildftpd_msg($ftp_stream,$text);
    ftp_site($ftp_stream,"SITE MSG $text");
}
?>
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0
daemorhedron
11 years ago
I'd like to follow up with Ivan's observation there. Unless I am missing the obvious, which is entirely possible of course, this command is quite useless unless it returns the data from the SITE <foo> request.

Besides the obvious SITE HELP command, another one that would require catching the feedback would be the SITE LOCATE | SITE SEARCH commands. I completely recognize that SITE <foo> commands are indeed insanely proprietary, but the fact still remains that changing this to return the results, or at least having the option to do so (such as exec() and the like) would be vastly preferred to the current method of returning true/false values.

Thanks.
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