PHP 5.6.0 released

ftp_size

(PHP 4, PHP 5)

ftp_sizeRestituisce le dimensioni del file specificato

Descrizione

int ftp_size ( resource $ftp_stream , string $remote_file )

La funzione ftp_size() restituisce le dimensioni del file remote_file in bytes. Se si verifica un errore, se il file specificato non esiste, o se e' una directory, viene restituito -1. Non tutti i server supportano questa caratteristica.

Restituisce le dimensioni del file in caso di successo, o -1 in caso di errore.

Example #1 Esempio di funzione ftp_size()

<?php

$file 
'somefile.txt';

// stabilisce la connessione
$conn_id ftp_connect($ftp_server);

// si collega come username e password
$login_result ftp_login($conn_id$ftp_user_name$ftp_user_pass);

// recupera le dimensioni di $file
$res ftp_size($conn_id$file);

if (
$res != -1) {
    echo 
"le dimensioni del file $file sono di $res bytes";
} else {
    echo 
"impossibile stabilire le dimensioni";
}

// chiude la connessione
ftp_close($conn_id);

?>

Vedere anche ftp_rawlist().

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User Contributed Notes 11 notes

up
1
gerben at gerbs dot net
2 years ago
To overcome the 2 GB limitation, the ftp_raw solution below is probably the nicest. You can also perform this command using regular FTP commands:

<?php
$response
ftp_raw($ftpConnection, "SIZE $filename");
$filesize = floatval(str_replace('213 ', '', $response[0]));
?>

[However, this] is insufficient for use on directories. As per RFC 3659 (http://tools.ietf.org/html/rfc3659#section-4.2), servers should return error 550 (File not found) if the command is issued on something else than a file, or if some other error occurred. For example, Filezilla indeed returns this string when using the ftp_raw command on a directory:

array(1) {
  [0]=>
  string(18) "550 File not found"
}

RFC 959 (http://tools.ietf.org/html/rfc959) dictates that the returned string always consists of exactly 3 digits, followed by 1 space, followed by some text. (Multi-line text is allowed, but I am ignoring that.) So it is probably better to split the string with substr, or even a regular expression.

<?php
$response
= ftp_raw($ftp, "SIZE $filename");
$responseCode = substr($response[0], 0, 3);
$responseMessage = substr($response[0], 4);
?>

Or with a regular expression:

<?php
$response
= ftp_raw($ftp, "SIZE $filename");
if (
preg_match("/^(\\d{3}) (.*)$/", $response[0], $matches) == 0)
    throw new
Exception("Unable to parse FTP reply: ".$response[0]);
list(
$response, $responseCode, $responseMessage) = $matches;
?>

You could then decide to assume that response code '550' means that it's a directory. I guess that's just as 'dangerous' as assuming that ftp_size -1 means that it's a directory.
up
1
bluerain [at] telenet [dot] be
5 years ago
To overcome the 2GB file size limit, you can open your own socket to get the file size of a large file. Quick and dirty script:

<?php
$socket
=fsockopen($hostName, 21);
$t=fgets($socket, 128);
fwrite($socket, "USER $myLogin\r\n");
$t=fgets($socket, 128);
fwrite($socket, "PASS $myPass\r\n");
$t=fgets($socket, 128);
fwrite($socket, "SIZE $fileName\r\n");
$t=fgets($socket, 128);
$fileSize=floatval(str_replace("213 ","",$t));
echo
$fileSize;
fwrite($socket, "QUIT\r\n");
fclose($socket);
?>
up
1
chuck at t8design dot com
8 years ago
note that project_t4 at hotmail dot com's example above doesn't work in general, though it works on his Win2K/Apache server; as far as I can tell there is no way to check over ftp whether a directory exists.  This function's behavior given a directory name seems to be at least somewhat dependent on your OS, web server, or ftp server, I don't know which.
up
0
ibeono at gmail dot com
3 years ago
If you experience troubles with size of large file then you can use ftp_rawlist function and parse it result
up
0
miccots at gmail dot com
6 years ago
2 adams[AT]techweavers[DOT]net:
To get a size of large file (f. ex.: 3.2 Gb) you have to format the result returned by ftp_size():

$size = sprintf ("%u", ftp_size($connection, $file_name));

So you can get the real size of big files. But this method is not good for checking is this a dir (when ftp_size() returns -1).
up
0
C_Muller
7 years ago
For checking if a certain folder exists try using ftp_nlist() function to get a directory list in array. By using in_array('foldername') you can find out if it is there or not.
up
0
adams[AT]techweavers[DOT]net
9 years ago
Well this function is nice but if you have files larger then 2.1Gb or 2.1 Billion Bytes you cannot get its size.
up
0
Anonymous
9 years ago
To get a dirsize recursive you can use this simple function:

<?php # copyright by fackelkind | codeMaster
   
function getRecDirSize ($connection, $dir){
       
$temp = ftp_rawlist ($connection, "-alR $dir");
        foreach (
$temp as $file){
            if (
ereg ("([-d][rwxst-]+).* ([0-9]) ([a-zA-Z0-9]+).* ([a-zA-Z0-9]+).* ([0-9]*) ([a-zA-Z]+[0-9: ]*[0-9]) ([0-9]{2}:[0-9]{2}) (.+)", $file, $regs)){ 
               
$isdir = (substr ($regs[1],0,1) == "d");
                if (!
$isdir)
                   
$size += $regs[5];
            }
        }
        return
$size;
    }
   
$dirSize = getRecDirSize ($conID, "/");
?>
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0
project_t4 at hotmail dot com
10 years ago
Just to let people out there know, on my windows 2000 server running Apache and php i was returned 0 not -1 for directories.

foreach ($dir_list as $item)
    {
      if(ftp_size($conn_id, $item) == "0")
      {
      echo "<br>Directory:: ".$item;
      } else {
      echo "<br>File:: ".$item;
      }
    }

This outputs a list of the remote directory and indicates which items are directories and which are files.
up
0
nicke_ at at_h9k dot com
10 years ago
This will return the filesize on remote host and the size if you download it in FTP_BINARY mode. If you are using FTP_ASCII in ftp_get() the size can be changed.
up
0
victor59 at yahoo dot com dot hk
11 years ago
$file= 'filename with space.txt';
$size = ftp_size($this->ftp, urldecode($file) );

this one can correctly return the size
otherwize, it always return -1
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