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is_dir

(PHP 4, PHP 5)

is_dirDiz se o caminho é um diretório

Descrição

bool is_dir ( string $filename )

Informa se o dado nome de arquivo é um diretório.

Parâmetros

filename

Caminho para o arquivo. Se filename é um nome de arquivo relativo, irá ser verificado relativamente ao atual diretório. Se filename é um link simbólico ou hard link então o link será resolvido e validado. Se o safe mode estiver habilitado ou o open_basedir, podem ser aplicadas mais restrições.

Valor Retornado

Retorna TRUE se o nome do arquivo existe e é um diretório, FALSE caso contrário.

Exemplos

Exemplo #1 Exemplo da is_dir()

<?php
var_dump
(is_dir('a_file.txt'));
var_dump(is_dir('bogus_dir/abc'));

var_dump(is_dir('..')); // um diretório acima
?>

O exemplo acima irá imprimir:

bool(false)
bool(false)
bool(true)

Erros

Upon failure, an E_WARNING is emitted.

Notas

Nota: Os resultados desta função são cacheados. Veja clearstatcache() para mais detalhes.

Dica

A partir do PHP 5.0.0, esta função também pode ser utilizada com alguns wrappers URL. Veja Supported Protocols and Wrappers para uma lista de quais wrappers são suportados pela família de funções stat().

Veja Também

  • chdir() - Muda o diretório
  • dir() - Retorna uma instância da classe Diretório
  • opendir() - Abre um manipulador de diretório
  • is_file() - Informa se o arquivo é um arquivo comum (não é diretório)
  • is_link() - Diz se o arquivo é um link simbólico (symbolic link)

add a note add a note

User Contributed Notes 15 notes

up
6
digitalaudiorock at gmail dot com
4 years ago
Just a note for anyone who encounters is_dir() returning false on CIFS mount points or directories within those mount points on 2.6.31 and newer kernels: Apparently in new kernels they've started using the CIFS serverino option by default.  With Windows shares this causes huge inode numbers and which apparently can cause is_dir() to return false.  Adding the noserverino option to the CIFS mount will prevent this.  This may only occur on 32 systems but I don't have a 64 bit install to test against.
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2
Anonymous
6 years ago
One note regarding checking for empty directories :
>>echo (count(glob("$dir/*")) === 0) ? 'Empty' : 'Not empty';
This does not work correctly on Linux.
The '.' and '..' will always be returned even if no files are present in the directory.
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1
puremango dot co dot uk at gmail dot com
9 years ago
this function bypasses open_basedir restrictions.
<?
function my_is_dir($dir)
{
    // bypasses open_basedir restrictions of is_dir and fileperms
    $tmp_cmd = `ls -dl $dir`;
    $dir_flag = $tmp_cmd[0];
    if($dir_flag!="d")
    {
        // not d; use next char (first char might be 's' and is still directory)
        $dir_flag = $tmp_cmd[1];
    }
    return ($dir_flag=="d");
}
?>

example:
<?
....
echo is_dir("/somewhere/i/dont/have/access/to");
?>
output:
Warning: open_basedir restriction in effect

<?
....
echo my_is_dir("/somewhere/i/dont/have/access/to");
?>
output:
true (or false, depending whether it is or not...)

---
visit puremango.co.uk for other such wonders
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1
Btx
5 years ago
<?php
public static function isEmptyDir($dir){
     return ((
$files = @scandir($dir)) && count($files) <= 2);
}
?>

better ;)
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1
niceuser at live dot com
1 year ago
PITFALL in sub dir processing

After struggeling with a sub-dir processing (some subdirs were skipped) AND reading the posts, I realized that virutally no-one clearly told what were wrong.

The common traverse dir code was:
-----------------------------------------

opendir("myphotos"); // Top dir to process from (example)

while (false !== ($fname = readdir($h_dir))) { // process current dir (read a directory entry)

   if ($fname{0} == '.') continue; // skip dirs . and .. by first char test

   if (is_dir($fname)) call_own_subdir_process;  // process this subdir by calling a routine

   }

PROBLEM IS :

The "is_dir()" must have the FULL PATH or it will skip some dirs. So the above code need to INSERT THE PATH before the filename. This would give this change in above...

   if (is_dir("myphotos\" . $fname)) call_own_subdir_process;  // skip subdirs

The pitfall really was, that without full path some subdirs were found...hope this clears all up
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0
vstoykov at consultant dot bg
5 years ago
When trying (no 'pear') to enumerate mounted drives on a win32  platform (Win XP SP3, Apache/2.2.11, PHP/5.2.9), I used:

<?php
function echo_win_drives() {

  for(
$c='A'; $c<='Z'; $c++)
    if(
is_dir($c . ':'))
      echo
$c . ': ';
}
?>

which yielded:
A: C: D: E: F: G: H: I:
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0
alanguir at detroitchamber dot com
5 years ago
When I run a scandir I always run a simple filter to account for file system artifacts (especially from a simple ftp folder drop) and the "." ".." that shows up in every directory:

<?php
   
if (is_dir($folder){
       
$contents = scandir($folder);
       
$bad = array(".", "..", ".DS_Store", "_notes", "Thumbs.db");
       
$files = array_diff($contents, $bad);
    }
?>
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0
jasoneisen at gee mail
6 years ago
An even better (PHP 5 only) alternative to "Davy Defaud's function":

<?php
function is_empty_dir($dir)
{
    if ((
$files = @scandir($dir)) && count($files) <= 2) {
        return
true;
    }
    return
false;
}
?>

NOTE: you should obviously be checking beforehand if $dir is actually a directory, and that it is readable, as only relying on this you would assume that in both cases you have a non-empty readable directory.
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0
danr at cvisual dot com dot com
7 years ago
Running PHP 5.2.0 on Apache Windows, I had a problem (likely the same one as described by others) where is_dir returned a False for directories with certain permissions even though they were accessible.

Strangely, I was able to overcome the problem with a more complete path. For example, this only displays "Works" on subdirectories with particular permissions (in this directory about 1 out of 3):

$d = opendir("./albums/mydir");
while(false !== ($f = readdir($d))) {
    echo "<hr />";
        if(is_dir($f)) {
            echo "<b>Works:" . $f . "</b>";
        }
}

However, this works properly for all directories:

$d = opendir("./albums/mydir");
while(false !== ($f = readdir($d))) {
    echo "<hr />";
        $dName = "./albums/mydir/" . $f;
        if(is_dir($dName)) {
            echo "<b>Works:" . $dName . "</b>";
        }
}

I don't understand the hit-and-miss of the first code, but maybe the second code can help others having this problem.
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0
tibard at gmail dot com
9 years ago
use this function to get all files inside a directory (including subdirectories)

<?php
function scan_Dir($dir) {
   
$arrfiles = array();
    if (
is_dir($dir)) {
        if (
$handle = opendir($dir)) {
           
chdir($dir);
            while (
false !== ($file = readdir($handle))) {
                if (
$file != "." && $file != "..") {
                    if (
is_dir($file)) {
                       
$arr = scan_Dir($file);
                        foreach (
$arr as $value) {
                           
$arrfiles[] = $dir."/".$value;
                        }
                    } else {
                       
$arrfiles[] = $dir."/".$file;
                    }
                }
            }
           
chdir("../");
        }
       
closedir($handle);
    }
    return
$arrfiles;
}

?>
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0
sly at noiretblanc dot org
10 years ago
This is the "is_dir" function I use to solve the problems :

function Another_is_dir ($file)
{
    if ((fileperms("$file") & 0x4000) == 0x4000)
        return TRUE;
    else
        return FALSE;
}

or, more simple :

function Another_is_dir ($file)
{
return ((fileperms("$file") & 0x4000) == 0x4000);
}

I can't remember where it comes from, but it works fine.
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-1
Victor
1 year ago
If you are using Mac, or others systems that store information about the directory layout and etc, the function:

   function empty_dir($dir) {
        if (($files = @scandir($dir)) && count($files) <= 3)
            return true;
        else
            return false;
    }

Must have the count($files) comparing with the number of hidden files!

For example, I'm using Mac and the empty directory shows me three files: ".", ".." and ".DS_Store", so if I am planning to put the website online on my Mac, I've to count in the ".DS_Store" file!
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-1
gecko4 at gmail dot com
7 years ago
Here is another way to test if a directory is empty, which I think is much simpler than those posted below:

<?php
$dir
= 'directory';
echo (
count(glob("$dir/*")) === 0) ? 'Empty' : 'Not empty';
?>
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-1
Eric
7 years ago
Ah ha!  Maybe this is a bug, or limitation to be more precise, of php. See http://bugs.php.net/bug.php?id=27792

A workaround is posted on the page (above) and seems to work for me:

function is_dir_LFS($path){
  return (('d'==substr(exec("ls -dl '$path'"),0,1))?(true):(false));
}

PS: I'm using PHP 4.3.10-16, posts report this problem up to 5.0
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-1
Anonymous
9 years ago
Unfortunately, the function posted by p dot marzec at bold-sg dot pl does not work.
The corrected version is:

// returns true if folder is empty or not existing
// false if folde is full

function is_empty_folder($dir) {
if (is_dir($dir)) {
   $dl=opendir($dir);
   if ($dl) {
       while($name = readdir($dl)) {
   if (!is_dir("$dir/$name")) { //<--- corrected here
       return false;
       break;
       }
   }
       closedir($dl);
       }
   return true;
   } else return true;
}
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