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(PHP 4, PHP 5, PHP 7)

substr_countВозвращает число вхождений подстроки


int substr_count ( string $haystack , string $needle [, int $offset = 0 [, int $length ]] )

substr_count() возвращает число вхождений подстроки needle в строку haystack. Заметьте, что параметр needle чувствителен к регистру.


Эта функция не подсчитывает перекрывающиеся подстроки. Смотрите пример ниже!

Список параметров


Строка, в которой ведется поиск


Искомая подстрока


Смещение начала отсчета


Максимальная длина строки в которой будет производится поиск подстроки после указанного смещения. Если сумма смещения и максимальной длины будет больше длины haystack, то будет выведено предупреждение.

Возвращаемые значения

Эта функция возвращает integer.

Список изменений

Версия Описание
5.1.0 Добавлены параметры offset и length


Пример #1 Пример использования substr_count()

'This is a test';
strlen($text); // 14

echo substr_count($text'is'); // 2

// строка уменьшается до 's is a test', поэтому вывод будет 1
echo substr_count($text'is'3);

// текст уменьшается до 's i', поэтому вывод будет 0
echo substr_count($text'is'33);

// генерирует предупреждение, так как  5+10 > 14
echo substr_count($text'is'510);

// выводит только 1, т.к. перекрывающиеся подстроки не учитываются
$text2 'gcdgcdgcd';

Смотрите также

  • count_chars() - Возвращает информацию о символах, входящих в строку
  • strpos() - Возвращает позицию первого вхождения подстроки
  • substr() - Возвращает подстроку
  • strstr() - Находит первое вхождение подстроки

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User Contributed Notes 10 notes

jrhodes at roket-enterprises dot com
7 years ago
It was suggested to use

substr_count ( implode( $haystackArray ), $needle );

instead of the function described previously, however this has one flaw.  For example this array:

array (
  0 => "mystringth",
  1 => "atislong"

If you are counting "that", the implode version will return 1, but the function previously described will return 0.
flobi at flobi dot com
9 years ago
Making this case insensitive is easy for anyone who needs this.  Simply convert the haystack and the needle to the same case (upper or lower).

substr_count(strtoupper($haystack), strtoupper($needle))
info at fat-fish dot co dot il
9 years ago
a simple version for an array needle (multiply sub-strings):

function substr_count_array( $haystack, $needle ) {
$count = 0;
     foreach (
$needle as $substring) {
$count += substr_count( $haystack, $substring);
tweston at bangordailynews dot com
1 year ago
To account for the case that jrhodes has pointed out, we can change the line to:

substr_count ( implode( ',', $haystackArray ), $needle );

This way:

array (
  0 => "mystringth",
  1 => "atislong"



Which brings the count for $needle = "that" to 0 again.
gigi at phpmycoder dot com
7 years ago
below was suggested a function for substr_count'ing an array, yet for a simpler procedure, use the following:

( implode( $haystackArray ), $needle );
4 months ago
It's worth noting this function is surprisingly fast. I first ran it against a ~500KB string on our web server. It found 6 occurrences of the needle I was looking for in 0.0000 seconds. Yes, it ran faster than microtime() could measure.

Looking to give it a challenge, I then ran it on a Mac laptop from 2010 against a 120.5MB string. For one test needle, it found 2385 occurrences in 0.0266 seconds. Another test needs found 290 occurrences in 0.114 seconds.

Long story short, if you're wondering whether this function is slowing down your script, the answer is probably not.
php at blink dot at
2 years ago
This will handle a string where it is unknown if comma or period are used as thousand or decimal separator. Only exception where this leads to a conflict is when there is only a single comma or period and 3 possible decimals (123.456 or 123,456). An optional parameter is passed to handle this case (assume thousands, assume decimal, decimal when period, decimal when comma). It assumes an input string in any of the formats listed below.

function toFloat($pString, $seperatorOnConflict="f")

    $pString=str_replace(" ", $thSeperator, $pString);

    $firstPeriod=strpos($pString, ".");
    $firstComma=strpos($pString, ",");
    if($firstPeriod!==FALSE && $firstComma!==FALSE) {
        if($firstPeriod<$firstComma) {
            $pString=str_replace(".", $thSeperator, $pString);
            $pString=str_replace(",", $decSeperator, $pString);
        else {
            $pString=str_replace(",", $thSeperator, $pString);
    else if($firstPeriod!==FALSE || $firstComma!==FALSE) {
        if(substr_count($pString, $seperator)==1) {
            $lastPeriodOrComma=strpos($pString, $seperator);
            if($lastPeriodOrComma==(strlen($pString)-4) && ($seperatorOnConflict!=$seperator && $seperatorOnConflict!="f")) {
                $pString=str_replace($seperator, $thSeperator, $pString);
            else {
                $pString=str_replace($seperator, $decSeperator, $pString);
        else {
            $pString=str_replace($seperator, $thSeperator, $pString);

function testFloatParsing() {
    $floatvals = array(
        "22 000",
        "123 456",
        "22 000,76",
        "-22 000,76",
        "-22 000",
    echo "<table>
            <th>dec. if period</th>
            <th>dec. if comma</th>
    foreach ($floatvals as $fval) {
        echo "<tr>";
        echo "<td>" . (string) $fval . "</td>";
        echo "<td>" . (float) toFloat($fval, "") . "</td>";
        echo "<td>" . (float) toFloat($fval, "f") . "</td>";
        echo "<td>" . (float) toFloat($fval, ".") . "</td>";
        echo "<td>" . (float) toFloat($fval, ",") . "</td>";
        echo "</tr>";
    echo "</table>";
XinfoX X at X XkarlX X-X XphilippX X dot X XdeX
12 years ago
Yet another reference to the "cgcgcgcgcgcgc" example posted by "chris at pecoraro dot net":

Your request can be fulfilled with the Perl compatible regular expressions and their lookahead and lookbehind features.

The example

$number_of_full_pattern = preg_match_all('/(cgc)/', "cgcgcgcgcgcgcg", $chunks);

works like the substr_count function. The variable $number_of_full_pattern has the value 3, because the default behavior of Perl compatible regular expressions is to consume the characters of the string subject that were matched by the (sub)pattern. That is, the pointer will be moved to the end of the matched substring.
But we can use the lookahead feature that disables the moving of the pointer:

$number_of_full_pattern = preg_match_all('/(cg(?=c))/', "cgcgcgcgcgcgcg", $chunks);

In this case the variable $number_of_full_pattern has the value 6.
Firstly a string "cg" will be matched and the pointer will be moved to the end of this string. Then the regular expression looks ahead whether a 'c' can be matched. Despite of the occurence of the character 'c' the pointer is not moved.
qeremy [atta] gmail [dotta] com
2 years ago
Unicode example with "case-sensitive" option;

function substr_count_unicode($str, $substr, $caseSensitive = true, $offset = 0, $length = null) {
    if (
$offset) {
$str = substr_unicode($str, $offset, $length);

$pattern = $caseSensitive
? '~(?:'. preg_quote($substr) .')~u'
: '~(?:'. preg_quote($substr) .')~ui';
preg_match_all($pattern, $str, $matches);

    return isset(
$matches[0]) ? count($matches[0]) : 0;

substr_unicode($str, $start, $length = null) {
join('', array_slice(
preg_split('~~u', $str, -1, PREG_SPLIT_NO_EMPTY), $start, $length));

$s = 'Ümit yüzüm gözüm...';
substr_count_unicode($s, 'ü');            // 3
print substr_count_unicode($s, 'ü', false);     // 4
print substr_count_unicode($s, 'ü', false, 10); // 1

print substr_count_unicode($s, 'üm');           // 2
print substr_count_unicode($s, 'üm', false);    // 3
chrisstocktonaz at gmail dot com
6 years ago
In regards to anyone thinking of using code contributed by zmindster at gmail dot com

Please take careful consideration of possible edge cases with that regex, in example:

$url = '';
$url = '';

This would cause a infinite loop and for example be a possible entry point for a denial of service attack. A correct fix would require additional code, a quick hack would be just adding a additional check, without clarity or performance in mind:

$i = 0;
while (substr_count($url, '../') && ++$i < strlen($url))

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