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Imagick::drawImage

(PECL imagick 2.0.0)

Imagick::drawImage把 ImagickDraw 对象渲染到当前图片上

说明

bool Imagick::drawImage ( ImagickDraw $draw )

把 ImagickDraw 对象渲染到当前图片上。

参数

draw

被渲染到图片上的 ImagickDraw 对象(在经过各种绘画操作之后的 ImagickDraw 对象)

返回值

成功时返回 TRUE

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User Contributed Notes 2 notes

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1
blah at blub dot com
8 years ago
If your imagick lib begins to say: "Non-conforming drawing primitive...", it could be that your locale are not correctly set. please locate all your setlocale and kill them temporary so you could check it that would solve the problem.
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0
sualk at lednew dot de
9 years ago
the ImagickDraw (v 2.2.0) seems to disharmonise with PHP-GTK2 (v 2.0.1).

The rendering of an ImagickDraw object on the current image fails (resp. results in a flat image without drawings), if php_gtk2.so is loaded.

Code to reproduce the failure:

#!/usr/bin/php5
<?php
dl
("php_gtk2.so"); // comment this for a second try

$string = "Hello world!";

$im = new Imagick();
$draw = new ImagickDraw();

$draw->setFillColor(new ImagickPixel('blue'));

$draw->setFontSize(28);

$metrix = $im->queryFontMetrics($draw, $string);

$draw->annotation(0,25,$string);

$im->newImage($metrix['textWidth'],$metrix['textHeight'], new ImagickPixel('white'));
$im->drawImage($draw);
$im->borderImage(new ImagickPixel('black'), 1, 1);
$im->setImageFormat('png');

$im->writeImage("./test.png");
?>
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