运算符优先级

运算符优先级指定了两个表达式绑定得有多“紧密”。例如,表达式 1 + 5 * 3 的结果是 16 而不是 18 是因为乘号(“*”)的优先级比加号(“+”)高。必要时可以用括号来强制改变优先级。例如:(1 + 5) * 3 的值为 18

如果运算符优先级相同,其结合方向决定着应该从右向左求值,还是从左向右求值——见下例。

下表按照优先级从高到低列出了运算符。同一行中的运算符具有相同优先级,此时它们的结合方向决定求值顺序。

运算符优先级
结合方向 运算符 附加信息
clone new clonenew
[ array()
++ -- ~ (int) (float) (string) (array) (object) (bool) @ 类型递增/递减
instanceof 类型
! 逻辑运算符
* / % 算术运算符
+ - . 算术运算符字符串运算符
<< >> 位运算符
== != === !== <> 比较运算符
& 位运算符引用
^ 位运算符
| 位运算符
&& 逻辑运算符
|| 逻辑运算符
? : 三元运算符
= += -= *= /= .= %= &= |= ^= <<= >>= => 赋值运算符
and 逻辑运算符
xor 逻辑运算符
or 逻辑运算符
, 多处用到

对具有相同优先级的运算符,左结合方向意味着将从左向右求值,右结合方向则反之。对于无结合方向具有相同优先级的运算符,该运算符有可能无法与其自身结合。举例说,在 PHP 中 1 < 2 > 1 是一个非法语句,而 1 <= 1 == 1 则不是。因为 T_IS_EQUAL 运算符的优先级比 T_IS_SMALLER_OR_EQUAL 的运算符要低。

Example #1 结合方向

<?php
$a 
5// (3 * 3) % 5 = 4
$a true true 2// (true ? 0 : true) ? 1 : 2 = 2

$a 1;
$b 2;
$a $b += 3// $a = ($b += 3) -> $a = 5, $b = 5

// mixing ++ and + produces undefined behavior
$a 1;
echo ++
$a $a++; // may print 4 or 5
?>
使用括号,即使在并不严格需要时,通常都可以增强代码的可读性。

Note:

尽管 = 比其它大多数的运算符的优先级低,PHP 仍旧允许类似如下的表达式:if (!$a = foo()),在此例中 foo() 的返回值被赋给了 $a

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User Contributed Notes 4 notes

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14
headden at karelia dot ru
5 years ago
Although example above already shows it, I'd like to explicitly state that ?: associativity DIFFERS from that of C++. I.e. convenient switch/case-like expressions of the form

$i==1 ? "one" :
$i==2 ? "two" :
$i==3 ? "three" :
"error";

will not work in PHP as expected
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9
Carsten Milkau
2 years ago
Beware the unusual order of bit-wise operators and comparison operators, this has often lead to bugs in my experience. For instance:

<?php if ( $flags & MASK  == 1) do_something(); ?>

will not do what you might expect from other languages. Use

<?php if (($flags & MASK) == 1) do_something(); ?>

in PHP instead.
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5
Antistone
8 months ago
BEWARE:  Addition, subtraction, and string concatenation have equal precedence!
<?
$x = 4;
echo "x minus one equals " . $x-1 . ", or so I hope";
?>
will print "-1, or so I hope"

(Concatenate the first string literal and the value of $x, then implicitly convert that to a number (zero) so you can subtract 1 from it, then concatenate the final string literal.)
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-1
leipie at gmail dot com
1 year ago
The precedence of the arrow operator (->) on objects seems to the highest of all, even higher then clone.

But you can't wrap (clone $foo)->bar() like this!
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