strrpos

(PHP 4, PHP 5, PHP 7, PHP 8)

strrpos — 文字列中に、ある部分文字列が最後に現れる場所を探す

説明

strrpos(string $haystack, string $needle, int $offset = 0): int|false

文字列 haystack の中で、 needle が最後に現れる位置を探します。

パラメータ

haystack

検索対象の文字列。

needle

検索する文字列。

PHP 8.0.0 より前のバージョンでは、needle が文字列でない場合、数値に変換され、文字の通常の値として扱われていました。この振る舞いは PHP 7.3.0 以降では推奨されないので、この機能を使用しないことを強く推奨します。意図した動作に依存する場合、 needle を string に明示的にキャストするか、明示的に chr() 関数を呼び出すべきでしょう。

offset

ゼロまたは正の値の場合、 haystack の最初の offset バイトをスキップし、左から右に検索が行われます。

負の値の場合、 haystack の最初ではなく、最後から offset バイトの箇所より検索を開始します。検索は右から左に行われ、検索を開始した箇所から needle が最初に現れる場所を探します。

注意:
この方が、最後の offset バイト、またはそれより前にある最後の needle を効率的に探せます。

戻り値

needle が見つかった位置を、 haystack 文字列の先頭 (offset の値とは無関係) からの相対位置で返します。

注意: 文字列の開始位置は 0 であり、1 ではありません。

needle が見つからない場合は false を返します。

変更履歴

バージョン	説明
8.0.0	`needle` は、空文字列を受け入れるようになりました。
8.0.0	`needle` に数値を渡すことはサポートされなくなりました。
7.3.0	`needle` に数値を渡すことは非推奨になりました。

例

例1 needle が haystack の中にあるかどうかの確認

"位置 0 に文字が見つかった" と "文字が見つからなかった" 場合の戻り値は混同しやすいです。この違いを見分ける方法を以下に示します。

<?php

$pos = strrpos($mystring, "b");
if ($pos === false) { // 注意: 等号が 3 つ並んでいます
    // 見つからない...
}

?>

例2 オフセットつきの検索

<?php
$foo = "0123456789a123456789b123456789c";

// Looking for '0' from the 0th byte (from the beginning)
var_dump(strrpos($foo, '0', 0));

// Looking for '0' from the 1st byte (after byte "0")
var_dump(strrpos($foo, '0', 1));

// Looking for '7' from the 21th byte (after byte 20)
var_dump(strrpos($foo, '7', 20));

// Looking for '7' from the 29th byte (after byte 28)
var_dump(strrpos($foo, '7', 28));

// Looking for '7' right to left from the 5th byte from the end
var_dump(strrpos($foo, '7', -5));

// Looking for 'c' right to left from the 2nd byte from the end
var_dump(strrpos($foo, 'c', -2));

// Looking for '9c' right to left from the 2nd byte from the end
var_dump(strrpos($foo, '9c', -2));
?>

上の例の出力は以下となります。

int(0)
bool(false)
int(27)
bool(false)
int(17)
bool(false)
int(29)

参考

strpos() - 文字列内の部分文字列が最初に現れる場所を見つける
stripos() - 大文字小文字を区別せずに文字列が最初に現れる位置を探す
strripos() - 文字列中で、特定の(大文字小文字を区別しない)文字列が最後に現れた位置を探す
strrchr() - 文字列中に文字が最後に現れる場所を取得する
substr() - 文字列の一部分を返す

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User Contributed Notes 30 notes

down

brian at enchanter dot net ¶

17 years ago

The documentation for 'offset' is misleading.

It says, "offset may be specified to begin searching an arbitrary number of characters into the string. Negative values will stop searching at an arbitrary point prior to the end of the string."

This is confusing if you think of strrpos as starting at the end of the string and working backwards.

A better way to think of offset is:

- If offset is positive, then strrpos only operates on the part of the string from offset to the end. This will usually have the same results as not specifying an offset, unless the only occurences of needle are before offset (in which case specifying the offset won't find the needle).

- If offset is negative, then strrpos only operates on that many characters at the end of the string. If the needle is farther away from the end of the string, it won't be found.

If, for example, you want to find the last space in a string before the 50th character, you'll need to do something like this:

strrpos($text, " ", -(strlen($text) - 50));

If instead you used strrpos($text, " ", 50), then you would find the last space between the 50th character and the end of the string, which may not have been what you were intending.

down

dave at pixelmetrics dot com ¶

5 years ago

The description of offset is wrong. Here’s how it works, with supporting examples.

Offset effects both the starting point and stopping point of the search. The direction is always right to left. (The description wrongly says PHP searches left to right when offset is positive.)

Here’s how it works:
When offset is positive, PHP searches right to left from the end of haystack to offset. This ignores the left side of haystack.

When offset is negative, PHP searches right to left, starting offset bytes from the end, to the start of haystack. This ignores the right side of haystack.

Example 1:
$foo = ‘aaaaaaaaaa’;
var_dump(strrpos($foo, 'a', 5));
Result: int(10)

Example 2:
$foo = "aaaaaa67890";
var_dump(strrpos($foo, 'a', 5));
Result: int(5)

Conclusion: When offset is positive, PHP searches right to left from the end of haystack.

Example 3:
$foo = "aaaaa567890";
var_dump(strrpos($foo, 'a', 5));
Result: bool(false)

Conclusion: When offset is positive, PHP stops searching at offset.

Example 4:
$foo = ‘aaaaaaaaaa’;
var_dump(strrpos($foo, 'a', -5));
Result: int(6) 

Conclusion: When offset is negative, PHP searches right to left, starting offset bytes from the end. 

Example 5:
$foo = "a234567890";
var_dump(strrpos($foo, 'a', -5));
Result: int(0)

Conclusion: When offset is negative, PHP searches right to left, all the way to the start of haystack.

down

david dot mann at djmann dot co dot uk ¶

6 years ago

Ten years on, Brian's note is still a good overview of how offsets work, but a shorter and simpler summary is:

    strrpos($x, $y, 50);  // 1: this tells strrpos() when to STOP, counting from the START of $x
    strrpos($x, $y, -50); // 2: this tells strrpos() when to START, counting from the END of $x

Or to put it another way, a positive number lets you search the rightmost section of the string, while a negative number lets you search the leftmost section of the string.

Both these variations are useful, but picking the wrong one can cause some highly confusing results!

down

Daniel Brinca ¶

17 years ago

Here is a simple function to find the position of the next occurrence of needle in haystack, but searching backwards  (lastIndexOf type function):

//search backwards for needle in haystack, and return its position
function rstrpos ($haystack, $needle, $offset){
    $size = strlen ($haystack);
    $pos = strpos (strrev($haystack), $needle, $size - $offset);
    
    if ($pos === false)
        return false;
    
    return $size - $pos;
}

Note: supports full strings as needle

down

anonymous ¶

4 years ago

There is a lot of confusion around how $offset works and I feel it's really quite simple.

If $offset is positive, the operation ignores the first $offset characters of the haystack.
If $offset is negative, the operation ignores the last $offset-1 characters of the haystack (don't ask why -1...).

To understand this instinctively, just imagine the characters being replaced with invalid symbols. Here's an example:

<?php
$hackstack = '0123456789';

// Search the entire sequence 0123456789
var_dump(strrpos($hackstack, '0')); // int(0)
var_dump(strrpos($hackstack, '9')); // int(9)

// Only search ##23456789
var_dump(strrpos($hackstack, '1', 2)); // bool(false)
var_dump(strrpos($hackstack, '2', 2)); // int(2)

// Only search 0123456###
var_dump(strrpos($hackstack, '6', -4)); // int(6)
var_dump(strrpos($hackstack, '7', -4)); // bool(false)

?>

down

stevewa ¶

8 years ago

i wanted to find a leading space BEFORE a hyphen

Crude Oil (Dec) 51.00-56.00 

so I had to find the position of the hyphen 

then subtract that position from the length of the string (to make it a negative number)
and then walk left toward the beginning of the string, looking for the first space before the hyphen

ex:
$str_position_hyphen  = strpos($line_new,"-",$str_position_spread);

$line_new_length = strlen($line_new);

$str_position_hyphen_from_end = $str_position_hyphen - $line_new_length;

echo "hyphen position from end = " . $str_position_hyphen_from_end . "<br />\n";
            
            
$str_position_space_before_hyphen  = strrpos($line_new, " ", $str_position_hyphen_from_end);

echo "*** previous space= " . $str_position_space_before_hyphen . "<br />\n";
            
$line_new = substr_replace($line_new, ",", $str_position_space_before_hyphen, 1  );    
    
echo $line_new . "<br /><br />\n";

down

islandispeace at hotmail dot com ¶

8 years ago

$offset is very misleading, here is my understanding:

function mystrrpos($haystack, $needle, $offset = 0) {
    if ($offset == 0) {
        return strrpos ($haystack, $needle);
    } else {
        return strrpos (substr($haystack, 0, $offset), $needle);
    }
}

down

dmitry dot polushkin at gmail dot com ¶

18 years ago

Returns the filename's string extension, else if no extension found returns false.
Example: filename_extension('some_file.mp3'); // mp3
Faster than the pathinfo() analogue in two times.
<?php
function filename_extension($filename) {
    $pos = strrpos($filename, '.');
    if($pos===false) {
        return false;
    } else {
        return substr($filename, $pos+1);
    }
}
?>

down

shimon at schoolportal dot co dot il ¶

18 years ago

In strrstr function in php 4 there is also no offset.
<?
// by Shimon Doodkin
function chrrpos($haystack, $needle, $offset=false)
{
 $needle=$needle[0];
 $l=strlen($haystack);
 if($l==0)  return false;
 if($offset===false)  $offset=$l-1;
 else
 {
  if($offset>$l) $offset=$l-1;
  if($offset<0) return false;
 }
 for(;$offset>0;$offset--)
  if($haystack[$offset]==$needle)
   return $offset;
 return false;
}
?>

down

gordon at kanazawa-gu dot ac dot jp ¶

19 years ago

The "find-last-occurrence-of-a-string" functions suggested here do not allow for a starting offset, so here's one, tried and tested, that does:

function my_strrpos($haystack, $needle, $offset=0) {
    // same as strrpos, except $needle can be a string
    $strrpos = false;
    if (is_string($haystack) && is_string($needle) && is_numeric($offset)) {
        $strlen = strlen($haystack);
        $strpos = strpos(strrev(substr($haystack, $offset)), strrev($needle));
        if (is_numeric($strpos)) {
            $strrpos = $strlen - $strpos - strlen($needle);
        }
    }
    return $strrpos;
}

down

fab ¶

19 years ago

RE: hao2lian

There are a lot of alternative - and unfortunately buggy - implementations of strrpos() (or last_index_of as it was called) on this page. This one is a slight modifiaction of the one below, but it should world like a *real* strrpos(), because it returns false if there is no needle in the haystack.

<?php

function my_strrpos($haystack, $needle) {
   $index = strpos(strrev($haystack), strrev($needle));
   if($index === false) {
        return false;
   }
   $index = strlen($haystack) - strlen($needle) - $index;
   return $index;
}

?>

down

-1

escii at hotmail dot com ( Brendan ) ¶

19 years ago

I was immediatley pissed when i found the behaviour of strrpos ( shouldnt it be called charrpos ?) the way it is, so i made my own implement to search for strings.

<?
function proper_strrpos($haystack,$needle){
        while($ret = strrpos($haystack,$needle))
        {       
                if(strncmp(substr($haystack,$ret,strlen($needle)),
                                $needle,strlen($needle)) == 0 )
                        return $ret;
                $haystack = substr($haystack,0,$ret -1 );
        }
        return $ret;
}
?>

down

-2

arlaud pierre ¶

12 years ago

This seems to behave like the exact equivalent to the PHP 5 offset parameter for a PHP 4 version.

<?php
 function strrpos_handmade($haystack, $needle, $offset = 0){

  if($offset === 0) return strrpos($haystack, $needle);
  
  $length = strlen($haystack);
  $size = strlen($needle);

  if($offset < 0) {
    $virtual_cut = $length+$offset;
    $haystack = substr($haystack, 0, $virtual_cut+$size);
    $ret = strrpos($haystack, $needle);
    return $ret > $virtual_cut ? false : $ret;
  } else {
    $haystack = substr($haystack, $offset);
    $ret = strrpos($haystack, $needle);
    return $ret === false ? $ret : $ret+$offset;
  }

}
?>

down

-2

su.noseelg@naes, only backwards ¶

21 years ago

Maybe I'm the only one who's bothered by it, but it really bugs me when the last line in a paragraph is a single word. Here's an example to explain what I don't like:



The quick brown fox jumps over the lazy

dog.



So that's why I wrote this function. In any paragraph that contains more than 1 space (i.e., more than two words), it will replace the last space with '&nbsp;'.



<?php

function no_orphans($TheParagraph) {

    if (substr_count($TheParagraph," ") > 1) {

    $lastspace = strrpos($TheParagraph," ");

    $TheParagraph = substr_replace($TheParagraph,"&nbsp;",$lastspace,1);

    }

return $TheParagraph;

}

?>



So, it would change "The quick brown fox jumps over the lazy dog." to "The quick brown fox jumps over the lazy&nbsp;dog." That way, the last two words will always stay together.

down

-4

maxmike at gmail dot com ¶

15 years ago

I've got a simple method of performing a reverse strpos which may be of use.  This version I have treats the offset very simply:
Positive offsets search backwards from the supplied string index.
Negative offsets search backwards from the position of the character that many characters from the end of the string.

Here is an example of backwards stepping through instances of a string with this function:

<?php
function backwardStrpos($haystack, $needle, $offset = 0){
    $length = strlen($haystack);
    $offset = ($offset > 0)?($length - $offset):abs($offset);
    $pos = strpos(strrev($haystack), strrev($needle), $offset);
    return ($pos === false)?false:( $length - $pos - strlen($needle) );
}

$pos = 0;
$count = 0;
echo "Test1<br/>";
while(($pos = backwardStrpos("012340567890", "0", $pos)) !== false){
     echo $pos."<br/>";
    $pos--;
    if($pos < 0){
        echo "Done<br/>";break;
    }
}
echo "---===---<br/>\nTest2<br/>";
echo backwardStrpos("12341234", "1", 2)."<br/>";
echo backwardStrpos("12341234", "1", -2);
?>

Outputs:
Test1
11
5
0
Done
---===---
Test2
0
4

With Test2 the first line checks from the first 3 in "12341234" and runs backwards until it finds a 1 (at position 0)

The second line checks from the second 2 in "12341234" and seeks towards the beginning for the first 1 it finds (at position 4).

This function is useful for php4 and also useful if the offset parameter in the existing strrpos is equally confusing to you as it is for me.

down

-5

alexandre at NOSPAM dot pixeline dot be ¶

15 years ago

I needed to check if a variable that contains a generated folder name based on user input had a trailing slash.



This did the trick:



<?php

    // Detect and remove a trailing slash

    $root_folder = ((strrpos($root_folder, '/') + 1) == strlen($root_folder)) ? substr($root_folder, 0, - 1) : $root_folder;

?>

down

-4

FIE ¶

21 years ago

refering to the comment and function about lastIndexOf()...

It seemed not to work for me the only reason I could find was the haystack was reversed and the string wasnt therefore it returnt the length of the haystack rather than the position of the last needle... i rewrote it as fallows:



<?php

function strlpos($f_haystack,$f_needle) {

      $rev_str = strrev($f_needle);

      $rev_hay = strrev($f_haystack);

      $hay_len = strlen($f_haystack);

      $ned_pos = strpos($rev_hay,$rev_str);

      $result  = $hay_len - $ned_pos - strlen($rev_str);

      return $result;

}

?>



this one fallows the strpos syntax rather than java's lastIndexOf.

I'm not positive if it takes more resources assigning all of those variables in there but you can put it all in return if you want, i dont care if i crash my server ;).



~SILENT WIND OF DOOM WOOSH!

down

-5

jafet at g dot m dot a dot i dot l dot com ¶

17 years ago

Full strpos() functionality, by yours truly.

<?php
function conforming_strrpos($haystack, $needle, $offset = 0)
{
    # Why does strpos() do this? Anyway...
    if(!is_string($needle)) $needle = ord(intval($needle));
    $haystack = strval($haystack);
    # Parameters
    $hlen = strlen($haystack);
    $nlen = strlen($needle);
    # Come on, this is a feature too
    if($nlen == 0)
    {
        trigger_error(__FUNCTION__.'(): Empty delimiter.', E_USER_WARNING);
        return false;
    }
    $offset = intval($offset);
    $hrev = strrev($haystack);
    $nrev = strrev($needle);
    # Search
    $pos = strpos($hrev, $nrev, $offset);
    if($pos === false) return false;
    else return $hlen - $nlen - $pos;
}
?>

Note that $offset is evaluated from the end of the string.

Also note that conforming_strrpos() performs some five times slower than strpos(). Just a thought.

down

-3

dixonmd at gmail dot com ¶

16 years ago

<?php

        $pos = strlen(string $haystack) - strpos (strrev(string $haystack), strrev(string $needle)) - strlen(string $needle);

?>



         If in the needle there is more than one character then in php 4 we can use the above statement for finding the position of last occurrence of a substring in a string instead of strrpos. Because in php 4 strrpos uses the first character of the substring.



eg : 

<?php

        $haystack = "you you you you you";

        $needle = "you";

        $pos1 = strlen($haystack) - strpos (strrev($haystack), strrev($needle)) - strlen($needle);

        echo $pos1 . "<br>";

        $pos2 strrpos($haystack, $needle);

        echo $pos2 . "<br>";

?>

down

-4

php dot net at insite-out dot com ¶

21 years ago

I was looking for the equivalent of Java's lastIndexOf(). I couldn't find it so I wrote this:



<?php

/*

Method to return the last occurrence of a substring within a 

string

*/

function last_index_of($sub_str,$instr) {

    if(strstr($instr,$sub_str)!="") {

        return(strlen($instr)-strpos(strrev($instr),$sub_str));

    }

    return(-1);

}

?>



It returns the numerical index of the substring you're searching for, or -1 if the substring doesn't exist within the string.

down

-3

mijsoot_at_gmail_dot_com ¶

17 years ago

To begin, i'm sorry for my English.
So, I needed of one function which gives me the front last position of a character. 
Then I said myself that it should be better to make one which gives the "N" last position.

$return_context = "1173120681_0__0_0_Mijsoot_Thierry";

// Here i need to find = "Mijsoot_Thierry"

//echo $return_context."<br />";// -- DEBUG

function findPos($haystack,$needle,$position){
    $pos = strrpos($haystack, $needle);
    if($position>1){
        $position --;
        $haystack = substr($haystack, 0, $pos);
        $pos = findPos($haystack,$needle,$position);
    }else{
        // echo $haystack."<br />"; // -- DEBUG
        return $pos;
    }
    return $pos;
}

var_dump(findPos($return_context,"_",2)); // -- TEST

down

-3

tsa at medicine dot wisc dot edu ¶

20 years ago

What the heck, I thought I'd throw another function in the mix.  It's not pretty but the following function counts backwards from your starting point and tells you the last occurrance of a mixed char string:



<?php

function strrposmixed ($haystack, $needle, $start=0) {

   // init start as the end of the str if not set

   if($start == 0) {

       $start = strlen($haystack);

   }

   

   // searches backward from $start

   $currentStrPos=$start;

   $lastFoundPos=false;

   

   while($currentStrPos != 0) {

       if(!(strpos($haystack,$needle,$currentStrPos) === false)) {

           $lastFoundPos=strpos($haystack,$needle,$currentStrPos);

           break;

       }

       $currentStrPos--;

   }

   

   if($lastFoundPos === false) {

       return false;

   } else {

       return $lastFoundPos;

   }

}

?>

down

-5

lee at 5ss dot net ¶

21 years ago

I should have looked here first, but instead I wrote my own version of strrpos that supports searching for entire strings, rather than individual characters.  This is a recursive function.  I have not tested to see if it is more or less efficient than the others on the page.  I hope this helps someone!



<?php

//Find last occurance of needle in haystack

function str_rpos($haystack, $needle, $start = 0){

    $tempPos = strpos($haystack, $needle, $start);

    if($tempPos === false){

        if($start == 0){

            //Needle not in string at all

            return false;

        }else{

            //No more occurances found

            return $start - strlen($needle);

        }

    }else{

        //Find the next occurance

        return str_rpos($haystack, $needle, $tempPos + strlen($needle));

    }

}

?>

down

-4

kavih7 at yahoo dot com ¶

18 years ago

<?php

###################################################

#

# DESCRIPTION:

# This function returns the last occurance of a string,

# rather than the last occurance of a single character like

# strrpos does. It also supports an offset from where to

# start the searching in the haystack string.

#

# ARGS:

# $haystack (required) -- the string to search upon

# $needle (required) -- the string you are looking for

# $offset (optional) -- the offset to start from

#

# RETURN VALS:

# returns integer on success

# returns false on failure to find the string at all

#

###################################################



function strrpos_string($haystack, $needle, $offset = 0)

{

    if(trim($haystack) != "" && trim($needle) != "" && $offset <= strlen($haystack))

    {

        $last_pos = $offset;

        $found = false;

        while(($curr_pos = strpos($haystack, $needle, $last_pos)) !== false)

        {

            $found = true;

            $last_pos = $curr_pos + 1;

        }

        if($found)

        {

            return $last_pos - 1;

        }

        else

        {

            return false;

        }

    }

    else 

    {

        return false;

    }

}

?>

down

-5

Christ Off ¶

17 years ago

Function to truncate a string
Removing dot and comma
Adding ... only if a is character found

function TruncateString($phrase, $longueurMax = 150) {
    $phrase = substr(trim($phrase), 0, $longueurMax);
    $pos = strrpos($phrase, " ");
    $phrase = substr($phrase, 0, $pos);
    if ((substr($phrase,-1,1) == ",") or (substr($phrase,-1,1) == ".")) {
        $phrase = substr($phrase,0,-1);
    }
    if ($pos === false) {
        $phrase = $phrase;
    }
    else {
        $phrase = $phrase . "...";
    }
return $phrase;
}

down

-5

jonas at jonasbjork dot net ¶

19 years ago

I needed to remove last directory from an path, and came up with this solution:

<?php

  $path_dir = "/my/sweet/home/";
  $path_up = substr( $path_dir, 0, strrpos( $path_dir, '/', -2 ) )."/";
  echo $path_up;

?>

Might be helpful for someone..

down

-5

nexman at playoutloud dot net ¶

20 years ago

Function like the 5.0 version of strrpos for 4.x.
This will return the *last* occurence of a string within a string.

    function strepos($haystack, $needle, $offset=0) {        
        $pos_rule = ($offset<0)?strlen($haystack)+($offset-1):$offset;
        $last_pos = false; $first_run = true;
        do {
            $pos=strpos($haystack, $needle, (intval($last_pos)+(($first_run)?0:strlen($needle))));
            if ($pos!==false && (($offset<0 && $pos <= $pos_rule)||$offset >= 0)) {
                $last_pos = $pos;
            } else { break; }
            $first_run = false;
        } while ($pos !== false);
        if ($offset>0 && $last_pos<$pos_rule) { $last_pos = false; }
        return $last_pos;
    }

If my math is off, please feel free to correct.
  - A positive offset will be the minimum character index position of the first character allowed.
  - A negative offset will be subtracted from the total length and the position directly before will be the maximum index of the first character being searched.

returns the character index ( 0+ ) of the last occurence of the needle. 

* boolean FALSE will return no matches within the haystack, or outside boundries specified by the offset.

down

-3

ZaraWebFX ¶

21 years ago

this could be, what derek mentioned:

<?
function cut_last_occurence($string,$cut_off) {
    return strrev(substr(strstr(strrev($string), strrev($cut_off)),strlen($cut_off)));
}    

//    example: cut off the last occurence of "limit"
    $str = "select delta_limit1, delta_limit2, delta_limit3 from table limit 1,7";
    $search = " limit";
    echo $str."\n";
    echo cut_last_occurence($str,"limit");
?>

down

-4

php NO at SPAMMERS willfris SREMMAPS dot ON nl ¶

17 years ago

<?php
/*******
 ** Maybe the shortest code to find the last occurence of a string, even in php4
 *******/
function stringrpos($haystack,$needle,$offset=NULL)
{
    return strlen($haystack)
           - strpos( strrev($haystack) , strrev($needle) , $offset)
           - strlen($needle);
}
// @return   ->   chopped up for readability.
?>

down

-4

genetically altered mastermind at gmail ¶

19 years ago

Very handy to get a file extension:
$this->data['extension'] = substr($this->data['name'],strrpos($this->data['name'],'.')+1);

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