PHP 5.4.36 Released

ftp_fput

(PHP 4, PHP 5)

ftp_fputオープン中のファイルを FTP サーバーにアップロードする

説明

bool ftp_fput ( resource $ftp_stream , string $remote_file , resource $handle , int $mode [, int $startpos = 0 ] )

ftp_fput() は、ファイルポインタが指すデータを FTP サーバー上のリモートファイルへアップロードします。

パラメータ

ftp_stream

FTP 接続のリンク ID 。

remote_file

リモートファイルのパス。

handle

ローカルでオープンされているファイルのポインタ。 ファイルの終端まで進むと読み込みが終了します。

mode

転送モード。FTP_ASCII または FTP_BINARY のどちらかを指定する必要があります。

startpos

リモートファイル内での、アップロード開始位置。

返り値

成功した場合に TRUE を、失敗した場合に FALSE を返します。

例1 ftp_fput() の例

<?php

// ファイルを読み込みモードで開く
$file 'somefile.txt';
$fp fopen($file'r');

// 接続を確立する
$conn_id ftp_connect($ftp_server);

// ユーザー名とパスワードでログインする
$login_result ftp_login($conn_id$ftp_user_name$ftp_user_pass);

// $file のアップロードを試みる
if (ftp_fput($conn_id$file$fpFTP_ASCII)) {
    echo 
"Successfully uploaded $file\n";
} else {
    echo 
"There was a problem while uploading $file\n";
}

// 接続を閉じ、ファイルを閉じる
ftp_close($conn_id);
fclose($fp);

?>

参考

  • ftp_put() - FTP サーバーにファイルをアップロードする
  • ftp_nb_fput() - オープン中のファイルを FTP サーバーに保存する(非ブロッキング)
  • ftp_nb_put() - FTP サーバーにファイルを保存する(非ブロッキング)

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User Contributed Notes 10 notes

up
5
jopi paranoid fi
6 years ago
When you have your file contents as a string, create temporary stream and use that as a file handle.

<?php

$contents
= "This is a test file\nTesting 1,2,3..";

$tempHandle = fopen('php://temp', 'r+');
fwrite($tempHandle, $contents);
rewind($tempHandle);       

ftp_fput($this->ftp, $filename, $tempHandle, FTP_ASCII);

?>
up
3
roy at user dot nl
1 year ago
For directly inserting content into a file on an FTP host, you could also create a string stream wich streams directly to the ftp_fput function.

This should create less overhead than first writing to any temp directories locally before streaming, as suggested here.

<?php

$string
= "Your content goes here";
$stream = fopen('data://text/plain,' . $string,'r');

ftp_fput($this->connection,$pathTo,$stream, FTP_BINARY);

?>
up
1
rok dot meglic at gmail dot com
6 years ago
Make sure you chdir to remote directory before using ftp_put or else ftp_put will just return error that it cannot create file. After you do the chdir you should NOT pass the whole path of file to ftp_put but just basename (filename). See example for more info.

Example:
<?php
$locpath
= 'local_path/resources/js/test.js';
$rempath = 'resources/js/';
$remFile = 'test.js';

ftp_chdir($this->conn_id, $rempath);
ftp_put($this->conn_id, $remFile, $locpath, FTP_BINARY);
?>
up
0
php at cpis dot me
2 years ago
This might be obvious to most of you, but make sure your stream isn't write-only. It has to be able to read from your stream in order to upload its contents.

Took me a while trying to figure out why my  uploaded file was 0B, and that was why.
up
0
jevin
3 years ago
You might also want to note that ftp_fput will overwrite any existing file.
up
0
timgolding_10 at hotmail dot com
5 years ago
If when using fput you get the one of the following errors:

Warning: ftp_fput() [function.ftp-fput]: Opening ASCII mode data connection

Warning: ftp_fput() [function.ftp-fput]: Opening BINARY mode data connection

and it creates the file in the correct location but is a 0kb file and all FTP commands thereafter fail. It is likely that the client is behind a firewall. To rectify this use:

<?php
ftp_pasv
($resource, true);
?>

Before executing any put commands. Took me so long to figure this out I actually cheered when I did :D
up
0
robert b
6 years ago
Using jopi paranoid fi's example, tmpfile() works on PHP 4 and 5 instead of using the php://temp file.
up
0
Charlie Brown
6 years ago
Fails if destination file exists. Delete first and it works.
up
0
info at daniel-marschall dot de
8 years ago
This is a function i wrote to copy a complete directory to a FTP-Server-folder.

function ftp_uploaddirectory($conn_id, $local_dir, $remote_dir)
{
  @ftp_mkdir($conn_id, $remote_dir);
  $handle = opendir($local_dir);
  while (($file = readdir($handle)) !== false)
  {
    if (($file != '.') && ($file != '..'))
    {
      if (is_dir($local_dir.$file))
      {
        ftp_uploaddirectory($conn_id, $local_dir.$file.'/', $remote_dir.$file.'/');
      }
      else
        $f[] = $file;
    }
  }
  closedir($handle);
  if (count($f))
  {
    sort($f);
    @ftp_chdir($conn_id, $remote_dir);
    foreach ($f as $files)
    {
      $from = @fopen("$local_dir$files", 'r');
      @ftp_fput($conn_id, $files, $from, FTP_BINARY);
    }
  }
}

Example:

$conn_id = @ftp_connect($server);
@ftp_login ($conn_id, $username, $passwort);
ftp_uploaddirectory($conn_id, 'mydirectory/', 'theftpdirectory/');
@ftp_quit($conn_id);

I hope you'll find it useful.
up
0
darian lassan at yahoo de
11 years ago
If you want to pass a string containing the filename as source and not a resource handle use ftp_put() instead. Trivial but not mentioned here.
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